{"id":170735,"date":"2024-11-19T22:46:56","date_gmt":"2024-11-19T22:46:56","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=170735"},"modified":"2024-11-19T22:46:58","modified_gmt":"2024-11-19T22:46:58","slug":"6co2-6h20-%e2%86%92-ch120-602","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/19\/6co2-6h20-%e2%86%92-ch120-602\/","title":{"rendered":"6CO2 + 6H20 \u2192 C,H120, + 602"},"content":{"rendered":"\n<p>6CO2 + 6H20 \u2192 C,H120, + 602<\/p>\n\n\n\n<ol start=\"6\" class=\"wp-block-list\">\n<li>How many molecules of CO2 are presenta<\/li>\n\n\n\n<li>How many atoms of oxygen are present in the reactants?<\/li>\n\n\n\n<li>How many atoms of carbon are present in the products<\/li>\n\n\n\n<li>How many total atoms are present in C.H120,?<\/li>\n\n\n\n<li>Is the equation above balanced or unbalanced?<\/li>\n<\/ol>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Let\u2019s break this down step by step:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Given Equation:<\/h3>\n\n\n\n<p>[ 6CO_2 + 6H_2O \\rightarrow C_6H_{12}O_6 + 6O_2 ]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">6. <strong>How many molecules of CO\u2082 are present?<\/strong><\/h3>\n\n\n\n<p>From the equation, there are <strong>6 molecules<\/strong> of ( CO_2 ) in the reactants.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">7. <strong>How many atoms of oxygen are present in the reactants?<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>( CO_2 ): Each molecule has 2 oxygen atoms, and there are 6 molecules. So, ( 6 \\times 2 = 12 ) oxygen atoms.<\/li>\n\n\n\n<li>( H_2O ): Each molecule has 1 oxygen atom, and there are 6 molecules. So, ( 6 \\times 1 = 6 ) oxygen atoms.<\/li>\n<\/ul>\n\n\n\n<p><strong>Total oxygen atoms = 12 + 6 = 18 oxygen atoms<\/strong> in the reactants.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">8. <strong>How many atoms of carbon are present in the products?<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>( C_6H_{12}O_6 ): This molecule contains 6 carbon atoms.<\/li>\n<\/ul>\n\n\n\n<p><strong>Total carbon atoms = 6 carbon atoms<\/strong> in the products.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">9. <strong>How many total atoms are present in ( C_6H_{12}O_6 )?<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon: 6 atoms<\/li>\n\n\n\n<li>Hydrogen: 12 atoms<\/li>\n\n\n\n<li>Oxygen: 6 atoms<\/li>\n<\/ul>\n\n\n\n<p><strong>Total = 6 + 12 + 6 = 24 atoms<\/strong> in ( C_6H_{12}O_6 ).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">10. <strong>Is the equation balanced or unbalanced?<\/strong><\/h3>\n\n\n\n<p><strong>The equation is balanced.<\/strong><\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Explanation:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>On the <strong>reactants<\/strong> side:<\/li>\n\n\n\n<li>Carbon: ( 6 ) (from ( 6CO_2 ))<\/li>\n\n\n\n<li>Hydrogen: ( 12 ) (from ( 6H_2O ))<\/li>\n\n\n\n<li>Oxygen: ( 18 ) (( 12 ) from ( CO_2 ) + ( 6 ) from ( H_2O ))<\/li>\n\n\n\n<li>On the <strong>products<\/strong> side:<\/li>\n\n\n\n<li>Carbon: ( 6 ) (from ( C_6H_{12}O_6 ))<\/li>\n\n\n\n<li>Hydrogen: ( 12 ) (from ( C_6H_{12}O_6 ))<\/li>\n\n\n\n<li>Oxygen: ( 18 ) (( 6 ) from ( C_6H_{12}O_6 ) + ( 12 ) from ( 6O_2 ))<\/li>\n<\/ul>\n\n\n\n<p>Since the number of each type of atom is the same on both sides, the equation is <strong>balanced<\/strong>, satisfying the Law of Conservation of Mass. Balancing ensures that no atoms are created or destroyed during the reaction, which is critical in chemical processes. This equation specifically represents <strong>photosynthesis<\/strong>, where plants use sunlight to convert carbon dioxide and water into glucose and oxygen, a cornerstone of life on Earth.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>6CO2 + 6H20 \u2192 C,H120, + 602 The Correct Answer and Explanation is : Let\u2019s break this down step by step: Given Equation: [ 6CO_2 + 6H_2O \\rightarrow C_6H_{12}O_6 + 6O_2 ] 6. How many molecules of CO\u2082 are present? From the equation, there are 6 molecules of ( CO_2 ) in the reactants. 7. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-170735","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/170735","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=170735"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/170735\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=170735"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=170735"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=170735"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}