{"id":179270,"date":"2024-12-30T10:48:26","date_gmt":"2024-12-30T10:48:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=179270"},"modified":"2024-12-30T10:48:28","modified_gmt":"2024-12-30T10:48:28","slug":"chrome-extension-bpmcpldpdmajfigpchkicefoigmkfalc-views-app-html-s","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/12\/30\/chrome-extension-bpmcpldpdmajfigpchkicefoigmkfalc-views-app-html-s\/","title":{"rendered":"chrome-extension\/bpmcpldpdmajfigpchkicefoigmkfalc\/views\/app.html s"},"content":{"rendered":"\n<p>chrome-extension\/bpmcpldpdmajfigpchkicefoigmkfalc\/views\/app.html s, Sheets &amp; Slides University Physics S PowerDrafXMStud PHYL 201-v1 pdf O 123Movies I Watch FXanity-Watch M Log In to Canvas BIUA E EE armal DEPARIMENT CIVE ANU ENVHUNMENIAL ENGINEEHING CIV 222-ENGINEERING MECHANICS I (FALL 2019) HoMEWORK No. 7 (DiSTRBUTED LOADS) DUE DATE: 10\/29\/2019 Problem 1 Find the equivalent resultant force, and specify its location on the beam measured from point A? I 15 kN\/m 10 kN\/m 3m 3 m 3 m Problem 2 Find the equivalent resultant force, and specity its location on the beam mneasured from point 0? hp $ 96 A &amp;<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To solve this problem, we will calculate the equivalent resultant force for the distributed loads and find its location on the beam.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Problem 1: Find the Equivalent Resultant Force and Its Location on the Beam Measured from Point A<\/h3>\n\n\n\n<p>You have two distributed loads on a beam:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>A load of 15 kN\/m acting over 3 meters (from A to 3 meters).<\/li>\n\n\n\n<li>A load of 10 kN\/m acting over 3 meters (from 3 meters to 6 meters).<\/li>\n<\/ol>\n\n\n\n<h4 class=\"wp-block-heading\">Step 1: Find the Total Equivalent Force of Each Distributed Load<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>For the 15 kN\/m load:<\/strong><br>[<br>F_1 = \\text{Load per unit length} \\times \\text{Length} = 15 \\, \\text{kN\/m} \\times 3 \\, \\text{m} = 45 \\, \\text{kN}<br>]<\/li>\n\n\n\n<li><strong>For the 10 kN\/m load:<\/strong><br>[<br>F_2 = \\text{Load per unit length} \\times \\text{Length} = 10 \\, \\text{kN\/m} \\times 3 \\, \\text{m} = 30 \\, \\text{kN}<br>]<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Step 2: Find the Location of the Resultant Force for Each Load<\/h4>\n\n\n\n<p>The location of the resultant force for a uniform distributed load is at the centroid of the load. For a uniform load, the centroid is at the midpoint of the load&#8217;s length.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>For the 15 kN\/m load:<\/strong><br>The location of the resultant force is at the midpoint of the first 3 meters, which is at 1.5 meters from point A.<\/li>\n\n\n\n<li><strong>For the 10 kN\/m load:<\/strong><br>The location of the resultant force is at the midpoint of the second 3 meters, which is at 4.5 meters from point A (3 meters + 1.5 meters).<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Step 3: Calculate the Location of the Combined Resultant Force<\/h4>\n\n\n\n<p>The equivalent resultant force (R) is the sum of the two forces:<br>[<br>R = F_1 + F_2 = 45 \\, \\text{kN} + 30 \\, \\text{kN} = 75 \\, \\text{kN}<br>]<\/p>\n\n\n\n<p>Now, to find the location of the resultant force ( x_{\\text{R}} ), use the moment balance equation:<br>[<br>x_{\\text{R}} = \\frac{F_1 x_1 + F_2 x_2}{F_1 + F_2}<br>]<br>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>( F_1 = 45 \\, \\text{kN} ), ( x_1 = 1.5 \\, \\text{m} )<\/li>\n\n\n\n<li>( F_2 = 30 \\, \\text{kN} ), ( x_2 = 4.5 \\, \\text{m} )<\/li>\n<\/ul>\n\n\n\n<p>Substitute the values:<br>[<br>x_{\\text{R}} = \\frac{45 \\times 1.5 + 30 \\times 4.5}{45 + 30}<br>]<br>[<br>x_{\\text{R}} = \\frac{67.5 + 135}{75}<br>]<br>[<br>x_{\\text{R}} = \\frac{202.5}{75} = 2.7 \\, \\text{m}<br>]<\/p>\n\n\n\n<p>Therefore, the location of the resultant force from point A is <strong>2.7 meters<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Problem 2: Equivalent Resultant Force and Its Location from Point O<\/h3>\n\n\n\n<p>This problem is similar to Problem 1, but the loads and positions are different. If you can provide the details, we can calculate the solution in a similar way.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>chrome-extension\/bpmcpldpdmajfigpchkicefoigmkfalc\/views\/app.html s, Sheets &amp; Slides University Physics S PowerDrafXMStud PHYL 201-v1 pdf O 123Movies I Watch FXanity-Watch M Log In to Canvas BIUA E EE armal DEPARIMENT CIVE ANU ENVHUNMENIAL ENGINEEHING CIV 222-ENGINEERING MECHANICS I (FALL 2019) HoMEWORK No. 7 (DiSTRBUTED LOADS) DUE DATE: 10\/29\/2019 Problem 1 Find the equivalent resultant force, and specify its [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-179270","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/179270","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=179270"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/179270\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=179270"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=179270"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=179270"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}