{"id":179438,"date":"2024-12-31T06:38:09","date_gmt":"2024-12-31T06:38:09","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=179438"},"modified":"2024-12-31T06:38:11","modified_gmt":"2024-12-31T06:38:11","slug":"write-the-reaction-mechanism-for-both-reactions","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/12\/31\/write-the-reaction-mechanism-for-both-reactions\/","title":{"rendered":"Write the reaction mechanism for both reactions"},"content":{"rendered":"\n

Write the reaction mechanism for both reactions:<\/p>\n\n\n\n

CoCl2.6H2O + Ethylenediamine -> [Co(en)3]Cl3<\/p>\n\n\n\n

[Co(en)3]Cl3 + Na2CO3 + Nitromethane -> [Co(dinosaur)]Cl3<\/p>\n\n\n\n

2 – What is the oxidation state of the metal and valence electrons count for the compounds: [Co(en)3]Cl3 and [Co(dinosaur)]Cl3 ?<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Reaction Mechanisms<\/h3>\n\n\n\n

1. Synthesis of ([Co(en)_3]Cl_3):<\/h4>\n\n\n\n

Reaction<\/strong>:
[ CoCl_2 \\cdot 6H_2O + 3(en) \\rightarrow [Co(en)_3]Cl_3 + 6H_2O ]<\/p>\n\n\n\n

Mechanism<\/strong>:<\/p>\n\n\n\n

    \n
  1. Hydrolysis of CoCl(_2)<\/strong>: The water molecules around cobalt dissociate, leaving the cobalt center in an octahedral environment.
    [ CoCl_2 \\cdot 6H_2O \\xrightarrow{\\text{hydration}} [Co(H_2O)_6]^{2+} + 2Cl^- ]<\/li>\n\n\n\n
  2. Ligand Exchange<\/strong>: Ethylenediamine ((en)), a bidentate ligand, displaces water molecules stepwise:
    [ [Co(H_2O)_6]^{2+} + 3(en) \\rightarrow [Co(en)_3]^{3+} + 6H_2O ]<\/li>\n\n\n\n
  3. Addition of Chloride Ions<\/strong>: The solution is neutralized with chloride ions to form the salt ([Co(en)_3]Cl_3).<\/li>\n<\/ol>\n\n\n\n

    2. Conversion to ([Co(dinosaur)]Cl_3):<\/h4>\n\n\n\n

    Reaction<\/strong>:
    [ [Co(en)_3]Cl_3 + Na_2CO_3 + CH_3NO_2 \\rightarrow [Co(dinosaur)]Cl_3 + Byproducts ]<\/p>\n\n\n\n

    Mechanism<\/strong>:
    The ([Co(dinosaur)]^{3+}) complex is synthesized through substitution or addition reactions involving nitromethane ((CH_3NO_2)) and possibly carbonate ((CO_3^{2-})). The exact ligand substitution depends on the structure of the hypothetical \u201cdinosaur\u201d ligand, which might involve a multidentate ligand derived from the reactants.<\/p>\n\n\n\n

    \n\n\n\n

    Oxidation State and Valence Electrons<\/h3>\n\n\n\n
      \n
    1. For ([Co(en)_3]Cl_3):<\/strong><\/li>\n<\/ol>\n\n\n\n
        \n
      • Oxidation state<\/strong>: (+3)
        The ethylenediamine ligands are neutral, and each Cl(^-) contributes (-1), leading to a charge balance of (+3) for Co.<\/li>\n\n\n\n
      • Valence electrons<\/strong>: (6)
        Cobalt in the (+3) oxidation state has (3d^6) electronic configuration in a low-spin state due to strong ligand field from ethylenediamine.<\/li>\n<\/ul>\n\n\n\n
          \n
        1. For ([Co(dinosaur)]Cl_3):<\/strong><\/li>\n<\/ol>\n\n\n\n
            \n
          • Oxidation state<\/strong>: (+3)
            The hypothetical “dinosaur” ligand is assumed neutral or anionic, maintaining the (+3) charge on Co for similar charge balance.<\/li>\n\n\n\n
          • Valence electrons<\/strong>: Dependent on ligand field strength. For a strong field ligand, a low-spin (3d^6) configuration would be likely.<\/li>\n<\/ul>\n\n\n\n
            \n\n\n\n

            300-Word Explanation<\/strong>
            The oxidation state is determined by considering the charges contributed by ligands and balancing with the total charge of the complex. In ([Co(en)_3]Cl_3), ethylenediamine is neutral, while three Cl(^-) ions add a (-3) charge. To balance this, Co must have a (+3) oxidation state.<\/p>\n\n\n\n

            Valence electrons include the (d)-electrons remaining after oxidation. Cobalt has (9) valence electrons in its neutral state ((3d^7 4s^2)). Oxidation to (+3) removes (3) electrons ((4s^2) and (1) from (3d)), leaving (6) valence electrons.<\/p>\n\n\n\n

            For ([Co(dinosaur)]Cl_3), the same logic applies. The oxidation state is (+3), assuming the dinosaur ligand maintains charge neutrality. Depending on the ligand field strength, the (3d^6) electrons are either low-spin (strong field) or high-spin (weak field).<\/p>\n","protected":false},"excerpt":{"rendered":"

            Write the reaction mechanism for both reactions: CoCl2.6H2O + Ethylenediamine -> [Co(en)3]Cl3 [Co(en)3]Cl3 + Na2CO3 + Nitromethane -> [Co(dinosaur)]Cl3 2 – What is the oxidation state of the metal and valence electrons count for the compounds: [Co(en)3]Cl3 and [Co(dinosaur)]Cl3 ? The Correct Answer and Explanation is : Reaction Mechanisms 1. Synthesis of ([Co(en)_3]Cl_3): Reaction:[ CoCl_2 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-179438","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/179438","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=179438"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/179438\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=179438"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=179438"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=179438"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}