{"id":180157,"date":"2025-01-03T19:22:58","date_gmt":"2025-01-03T19:22:58","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=180157"},"modified":"2025-01-03T19:23:00","modified_gmt":"2025-01-03T19:23:00","slug":"draw-the-lewis-structure-for-nbr3-molecule","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/03\/draw-the-lewis-structure-for-nbr3-molecule\/","title":{"rendered":"Draw the Lewis structure for NBr3 molecule"},"content":{"rendered":"\n

Draw the Lewis structure for NBr3 molecule. Draw the molecule by placing atoms on the canvas and connecting them with bonds. Include all lone pairs of electrons. ZE [] + C H O N S P F DOO Br CI I X @? More<\/p>\n\n\n\n

The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To draw the Lewis structure for the NBr\u2083 (Nitrogen Tribromide) molecule, we need to follow these steps:<\/p>\n\n\n\n

    \n
  1. Count the valence electrons:<\/strong>\n
      \n
    • Nitrogen (N) is in Group 15, so it has 5 valence electrons.<\/li>\n\n\n\n
    • Bromine (Br) is in Group 17, so each bromine atom has 7 valence electrons. Since there are three bromine atoms, that gives 3 \u00d7 7 = 21 valence electrons from bromine.<\/li>\n\n\n\n
    • Total valence electrons = 5 (from N) + 21 (from Br) = 26 electrons.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • Determine the central atom:<\/strong>\n
        \n
      • Nitrogen (N) will be the central atom since it is less electronegative than bromine (Br).<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • Connect the atoms with single bonds:<\/strong>\n
          \n
        • Place nitrogen (N) in the center and connect it with the three bromine (Br) atoms using single bonds. Each single bond consists of two electrons. So, 3 single bonds will use 6 electrons.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
        • Distribute the remaining electrons as lone pairs:<\/strong>\n
            \n
          • After placing the bonds, we have 26 – 6 = 20 electrons remaining.<\/li>\n\n\n\n
          • Place 3 lone pairs of electrons (6 electrons) around each bromine atom. This accounts for 18 electrons.<\/li>\n\n\n\n
          • The remaining 2 electrons will be placed as a lone pair on nitrogen (N).<\/li>\n<\/ul>\n<\/li>\n\n\n\n
          • Check for octet completion:<\/strong>\n
              \n
            • Each bromine atom now has 8 electrons around it (2 from the bond and 6 from the lone pairs), fulfilling its octet rule.<\/li>\n\n\n\n
            • Nitrogen has 8 electrons around it: 6 from the 3 single bonds with bromine and 2 from the lone pair.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

              Final Structure:<\/strong><\/p>\n\n\n\n

                \n
              • The molecule consists of nitrogen in the center with three single bonds to three bromine atoms. Nitrogen has one lone pair, and each bromine has three lone pairs.<\/li>\n<\/ul>\n\n\n\n

                Summary of Key Points:<\/h3>\n\n\n\n
                  \n
                • Nitrogen (N) is the central atom, forming three single bonds with bromine (Br).<\/li>\n\n\n\n
                • Each bromine atom has three lone pairs, and nitrogen has one lone pair.<\/li>\n\n\n\n
                • All atoms follow the octet rule, and the molecule has 26 valence electrons in total.<\/li>\n<\/ul>\n\n\n\n

                  If you want a more visual representation, I can generate an image for you!<\/p>\n","protected":false},"excerpt":{"rendered":"

                  Draw the Lewis structure for NBr3 molecule. Draw the molecule by placing atoms on the canvas and connecting them with bonds. Include all lone pairs of electrons. ZE [] + C H O N S P F DOO Br CI I X @? More The correct answer and explanation is: To draw the Lewis structure […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-180157","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/180157","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=180157"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/180157\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=180157"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=180157"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=180157"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}