{"id":180318,"date":"2025-01-05T12:15:23","date_gmt":"2025-01-05T12:15:23","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=180318"},"modified":"2025-01-05T12:15:26","modified_gmt":"2025-01-05T12:15:26","slug":"draw-the-haworth-projection-of-beta-d-sorbose-fischer-projection-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/05\/draw-the-haworth-projection-of-beta-d-sorbose-fischer-projection-below\/","title":{"rendered":"Draw the Haworth projection of beta-D-sorbose Fischer projection below"},"content":{"rendered":"\n<p>Draw the Haworth projection of beta-D-sorbose Fischer projection below. n pr CH,0H ?? ?? ?? CH20H Show your work Sorbose is a ketose aldose puranose furanose disaccharide oligosaccharide polysaccharide Cellulose is a homopolysaccharide of what monomer units? 1 pt<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Haworth Projection of \u03b2-D-Sorbose from its Fischer Projection<\/strong><\/h3>\n\n\n\n<p>To draw the Haworth projection of \u03b2-D-sorbose from its Fischer projection, we follow these steps:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Analyze D-sorbose structure<\/strong><\/h3>\n\n\n\n<p>D-sorbose is a ketose sugar (a monosaccharide with a ketone group) with six carbons. Its Fischer projection includes:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon 1: Part of the ketone group.<\/li>\n\n\n\n<li>Carbon 2: Has the configuration defining the D-series.<\/li>\n\n\n\n<li>Carbons 3\u20135: Hydroxyl (-OH) and hydrogen (-H) groups attached, determining chirality.<\/li>\n\n\n\n<li>Carbon 6: Terminal CH2_2OH group.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Cyclization<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>D-sorbose typically forms a <strong>furanose (5-membered ring)<\/strong> structure due to the reaction of the hydroxyl group on Carbon 5 with the ketone group on Carbon 2.<\/li>\n\n\n\n<li>This cyclization creates a new stereocenter at Carbon 2, forming two anomers: <strong>\u03b1 and \u03b2<\/strong>. The <strong>\u03b2-anomer<\/strong> has the anomeric -OH group on the same side as the CH2_2OH group in the Haworth projection.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Draw the Haworth projection<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Orient the ring with the oxygen at the top right.<\/li>\n\n\n\n<li>Place the CH2_2OH group above the ring at Carbon 5.<\/li>\n\n\n\n<li>Place the -OH group on Carbon 2 <strong>above<\/strong> the plane (\u03b2-form).<\/li>\n\n\n\n<li>Assign positions for the -OH groups on Carbons 3 and 4 based on the Fischer projection:\n<ul class=\"wp-block-list\">\n<li>-OH on Carbon 3 is below the plane.<\/li>\n\n\n\n<li>-OH on Carbon 4 is above the plane.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Add the CH2_2OH group at Carbon 1 below the plane.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Sorbose Classification<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Ketose<\/strong>: Contains a ketone group.<\/li>\n\n\n\n<li><strong>Furanose<\/strong>: Forms a 5-membered ring.<\/li>\n\n\n\n<li><strong>Monosaccharide<\/strong>: Simplest sugar unit.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Cellulose Structure<\/strong><\/h3>\n\n\n\n<p>Cellulose is a <strong>homopolysaccharide<\/strong> consisting of <strong>\u03b2-D-glucose<\/strong> units. These units are linked by <strong>\u03b2(1\u21924) glycosidic bonds<\/strong>. It forms linear chains that aggregate into microfibrils, giving structural integrity to plant cell walls.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Explanation of \u03b2-D-glucose in Cellulose:<\/strong><\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Each glucose unit alternates orientation (180\u00b0 rotation) to allow hydrogen bonding between adjacent chains.<\/li>\n\n\n\n<li>This arrangement makes cellulose strong, insoluble, and ideal for structural purposes.<\/li>\n\n\n\n<li>Humans lack the enzyme <strong>cellulase<\/strong> to break \u03b2(1\u21924) linkages, making cellulose indigestible.<\/li>\n<\/ol>\n\n\n\n<p>Let me know if you&#8217;d like me to draw the Haworth projection or elaborate further!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw the Haworth projection of beta-D-sorbose Fischer projection below. n pr CH,0H ?? ?? ?? CH20H Show your work Sorbose is a ketose aldose puranose furanose disaccharide oligosaccharide polysaccharide Cellulose is a homopolysaccharide of what monomer units? 1 pt The correct answer and explanation is: Haworth Projection of \u03b2-D-Sorbose from its Fischer Projection To draw [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-180318","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/180318","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=180318"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/180318\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=180318"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=180318"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=180318"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}