{"id":180674,"date":"2025-01-08T14:48:10","date_gmt":"2025-01-08T14:48:10","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=180674"},"modified":"2025-01-08T14:48:14","modified_gmt":"2025-01-08T14:48:14","slug":"the-bh2-ion-diagram-is-for-the-lewis-structure-with-the-hydrogens-pointing-straight-up","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/08\/the-bh2-ion-diagram-is-for-the-lewis-structure-with-the-hydrogens-pointing-straight-up\/","title":{"rendered":"The BH2+ ion diagram is for the Lewis structure with the hydrogens pointing straight up"},"content":{"rendered":"\n<p>The BH2+ ion diagram is for the Lewis structure with the hydrogens pointing straight up, and is correct. How would the diagram look when the H&#8217;s are rotated 90 degrees? Rank the SN2 reaction rates for the following compounds: iodomethane 3-iodo-2-methylhexane 1-iodo-2-methylhexane 2-iodo-2-methylhexane<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">BH\u2082\u207a Ion Diagram with Hydrogens Rotated 90 Degrees<\/h3>\n\n\n\n<p>The BH\u2082\u207a ion has a trigonal planar geometry because boron typically forms three bonds and lacks a complete octet in this ion. If the hydrogens in the correct Lewis structure (pointing straight up) are rotated 90 degrees, the diagram would resemble a flat triangle where the boron atom is at the center and the hydrogens are aligned in a plane at a 90-degree angle relative to the original orientation. This rotation does not change the bond angles (120\u00b0) because trigonal planar geometry inherently maintains the angles regardless of rotation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Ranking SN2 Reaction Rates<\/h3>\n\n\n\n<p><strong>Compounds:<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Iodomethane (CH\u2083I)<\/strong><\/li>\n\n\n\n<li><strong>3-iodo-2-methylhexane<\/strong><\/li>\n\n\n\n<li><strong>1-iodo-2-methylhexane<\/strong><\/li>\n\n\n\n<li><strong>2-iodo-2-methylhexane<\/strong><\/li>\n<\/ol>\n\n\n\n<p><strong>Correct Order of Reaction Rates (Fastest to Slowest):<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Iodomethane (CH\u2083I)<\/strong><\/li>\n\n\n\n<li><strong>1-iodo-2-methylhexane<\/strong><\/li>\n\n\n\n<li><strong>3-iodo-2-methylhexane<\/strong><\/li>\n\n\n\n<li><strong>2-iodo-2-methylhexane<\/strong><\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>The <strong>SN2 (bimolecular nucleophilic substitution)<\/strong> reaction depends on two factors:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Steric Hindrance<\/strong>: The bulkier the substituents around the electrophilic carbon, the slower the reaction rate.<\/li>\n\n\n\n<li><strong>Leaving Group Ability<\/strong>: Iodine (I\u207b) is an excellent leaving group, so differences in rates arise primarily due to steric hindrance.<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Iodomethane (CH\u2083I)<\/strong> has minimal steric hindrance because the electrophilic carbon is only bonded to hydrogens, making it the fastest to react.<\/li>\n\n\n\n<li><strong>1-iodo-2-methylhexane<\/strong> has moderate hindrance as the electrophilic carbon is attached to a primary carbon chain with a single branching.<\/li>\n\n\n\n<li><strong>3-iodo-2-methylhexane<\/strong> is more hindered than 1-iodo-2-methylhexane because the iodine is attached to a secondary carbon with more branching in proximity.<\/li>\n\n\n\n<li><strong>2-iodo-2-methylhexane<\/strong> has the slowest reaction rate because the iodine is on a tertiary carbon, causing significant steric hindrance.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the reaction rate decreases as the steric hindrance around the electrophilic carbon increases.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The BH2+ ion diagram is for the Lewis structure with the hydrogens pointing straight up, and is correct. How would the diagram look when the H&#8217;s are rotated 90 degrees? Rank the SN2 reaction rates for the following compounds: iodomethane 3-iodo-2-methylhexane 1-iodo-2-methylhexane 2-iodo-2-methylhexane The Correct Answer and Explanation is : BH\u2082\u207a Ion Diagram with Hydrogens [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-180674","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/180674","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=180674"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/180674\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=180674"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=180674"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=180674"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}