{"id":181739,"date":"2025-01-11T10:04:53","date_gmt":"2025-01-11T10:04:53","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=181739"},"modified":"2025-01-11T10:04:55","modified_gmt":"2025-01-11T10:04:55","slug":"the-solution-to-an-addition-problem-is-called-the","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/11\/the-solution-to-an-addition-problem-is-called-the\/","title":{"rendered":"The solution to an addition problem is called the"},"content":{"rendered":"\n
    \n
  1. The solution to an addition problem is called the _<\/strong>. Add -50-(-40)+( -60)+80<\/li>\n\n\n\n
  2. The solution to a subtraction problem is called the __<\/em>. Subtract -10-(-19)<\/li>\n\n\n\n
  3. The solution to a multiplication problem is called the __<\/em>. Multiply -2-3<\/em>(-4)*5<\/li>\n\n\n\n
  4. The solution to a division problem is called the _<\/strong>. Divide 10\u00f7 \u00be
    Combine terms if possible, if not explain why
    5) 6x-8x
    6) x + x2<\/li>\n<\/ol>\n\n\n\n

    The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

      \n
    1. The solution to an addition problem is called the sum<\/strong>.\n
        \n
      • For the expression \u221250\u2212(\u221240)+(\u221260)+80-50 – (-40) + (-60) + 80, the calculation steps are: \u221250+40\u221260+80=10-50 + 40 – 60 + 80 = 10 Therefore, the sum is 10.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • The solution to a subtraction problem is called the difference<\/strong>.\n
          \n
        • For the expression \u221210\u2212(\u221219)-10 – (-19), the calculation steps are: \u221210+19=9-10 + 19 = 9 Therefore, the difference is 9.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
        • The solution to a multiplication problem is called the product<\/strong>.\n
            \n
          • For the expression \u22122\u00d7\u22123\u00d7\u22124\u00d75-2 \\times -3 \\times -4 \\times 5, the calculation steps are: (\u22122)\u00d7(\u22123)=6(multiplying\u00a0negative\u00a0values\u00a0gives\u00a0a\u00a0positive\u00a0result)(-2) \\times (-3) = 6 \\quad \\text{(multiplying negative values gives a positive result)} 6\u00d7(\u22124)=\u221224(multiplying\u00a0by\u00a0a\u00a0negative\u00a0value\u00a0gives\u00a0a\u00a0negative\u00a0result)6 \\times (-4) = -24 \\quad \\text{(multiplying by a negative value gives a negative result)} \u221224\u00d75=\u2212120-24 \\times 5 = -120 Therefore, the product is \u2212120-120.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
          • The solution to a division problem is called the quotient<\/strong>.\n
              \n
            • For the expression 10\u00f73410 \\div \\frac{3}{4}, this is equivalent to multiplying 10 by the reciprocal of 34\\frac{3}{4}, which is 43\\frac{4}{3}: 10\u00d743=403\u224813.3310 \\times \\frac{4}{3} = \\frac{40}{3} \\approx 13.33 Therefore, the quotient is 403\\frac{40}{3} or approximately 13.33.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n
              \n\n\n\n

              Now, let’s look at combining terms:<\/p>\n\n\n\n

                \n
              1. 6x\u22128x6x – 8x\n
                  \n
                • Both terms contain the variable xx, so we combine them by adding the coefficients: 6x\u22128x=\u22122x6x – 8x = -2x Therefore, the simplified expression is \u22122x-2x.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
                • x+x2x + x^2\n
                    \n
                  • This expression contains two terms: one with xx and one with x2x^2. Since they have different powers of xx, they cannot<\/strong> be combined. Therefore, the expression remains as x+x2x + x^2.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

                    Explanation of combining terms:<\/h3>\n\n\n\n

                    When simplifying algebraic expressions, we combine like terms. Like terms are terms that have the same variable raised to the same power. For example:<\/p>\n\n\n\n

                      \n
                    • 6x6x and \u22128x-8x are like terms because both have the variable xx raised to the power of 1.<\/li>\n\n\n\n
                    • However, xx and x2x^2 are not<\/strong> like terms, as xx is raised to the first power and x2x^2 is raised to the second power. They cannot be combined directly because they represent different powers of the variable xx.<\/li>\n<\/ul>\n\n\n\n

                      To combine like terms, you simply add or subtract their coefficients. In the case of 6x\u22128x6x – 8x, the result is \u22122x-2x because the coefficients are 6 and -8. However, in expressions like x+x2x + x^2, where the terms involve different exponents, you leave the terms separate and do not combine them.<\/p>\n","protected":false},"excerpt":{"rendered":"

                      The Correct Answer and Explanation is : Now, let’s look at combining terms: Explanation of combining terms: When simplifying algebraic expressions, we combine like terms. Like terms are terms that have the same variable raised to the same power. For example: To combine like terms, you simply add or subtract their coefficients. In the case […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-181739","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/181739","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=181739"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/181739\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=181739"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=181739"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=181739"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}