{"id":181894,"date":"2025-01-11T17:20:26","date_gmt":"2025-01-11T17:20:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=181894"},"modified":"2025-01-11T17:20:28","modified_gmt":"2025-01-11T17:20:28","slug":"convert-the-structure-below-to-a-skeletal-drawing","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/11\/convert-the-structure-below-to-a-skeletal-drawing\/","title":{"rendered":"Convert The Structure Below To A Skeletal Drawing"},"content":{"rendered":"\n<p>Convert The Structure Below To A Skeletal Drawing. Consider E\/Z Stereochemistry Of Alkenes.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/01\/image-133.png\" alt=\"\" class=\"wp-image-181895\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To convert a given molecular structure to a skeletal drawing while considering the E\/Z stereochemistry of alkenes, follow these steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Identify the Alkene Functional Group<\/strong>: Locate the double bond (C=C) within the molecule.<\/li>\n\n\n\n<li><strong>Assign Priorities to Substituents<\/strong>: For each carbon of the double bond, assign priorities to the attached substituents using the Cahn-Ingold-Prelog priority rules. This involves comparing the atomic numbers of atoms directly attached to each carbon. The substituent with the higher atomic number receives the higher priority.<\/li>\n\n\n\n<li><strong>Determine the Stereochemistry<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>(E)-Isomer<\/strong>: If the higher-priority substituents on each carbon are on opposite sides of the double bond, the configuration is (E) (from the German &#8220;entgegen,&#8221; meaning &#8220;opposite&#8221;).<\/li>\n\n\n\n<li><strong>(Z)-Isomer<\/strong>: If the higher-priority substituents are on the same side, the configuration is (Z) (from the German &#8220;zusammen,&#8221; meaning &#8220;together&#8221;).<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Construct the Skeletal Structure<\/strong>: In skeletal drawings, carbon atoms are implied at the ends of lines and at intersections. Hydrogen atoms are also implied to satisfy the carbon&#8217;s valency of four. Explicitly draw the double bond and indicate the positions of the higher-priority substituents based on the determined stereochemistry.<\/li>\n<\/ol>\n\n\n\n<p><strong>Example<\/strong>:<\/p>\n\n\n\n<p>Consider 2-butene, which has the molecular formula C\u2084H\u2088. The double bond is between the second and third carbon atoms.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Assign Priorities<\/strong>:<\/li>\n\n\n\n<li>For the second carbon: the methyl group (\u2013CH\u2083) has a higher priority than the hydrogen atom.<\/li>\n\n\n\n<li>For the third carbon: the ethyl group (\u2013C\u2082H\u2085) has a higher priority than the hydrogen atom.<\/li>\n\n\n\n<li><strong>Determine Stereochemistry<\/strong>:<\/li>\n\n\n\n<li>If the methyl group and ethyl group are on opposite sides of the double bond, the configuration is (E)-2-butene.<\/li>\n\n\n\n<li>If they are on the same side, the configuration is (Z)-2-butene.<\/li>\n\n\n\n<li><strong>Skeletal Drawing<\/strong>:<\/li>\n\n\n\n<li>For (E)-2-butene: draw a line representing the double bond between the second and third carbon atoms, with the methyl group on the left and the ethyl group on the right.<\/li>\n\n\n\n<li>For (Z)-2-butene: draw the same double bond, but place both the methyl and ethyl groups on the same side.<\/li>\n<\/ul>\n\n\n\n<p>Understanding E\/Z stereochemistry is crucial for accurately representing and predicting the properties and reactivity of alkenes. The E\/Z system provides a clear and systematic way to describe the spatial arrangement of substituents around a double bond, which is essential for understanding molecular behavior in chemical reactions.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Convert The Structure Below To A Skeletal Drawing. Consider E\/Z Stereochemistry Of Alkenes. The Correct Answer and Explanation is : To convert a given molecular structure to a skeletal drawing while considering the E\/Z stereochemistry of alkenes, follow these steps: Example: Consider 2-butene, which has the molecular formula C\u2084H\u2088. The double bond is between the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-181894","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/181894","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=181894"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/181894\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=181894"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=181894"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=181894"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}