{"id":182013,"date":"2025-01-13T07:39:49","date_gmt":"2025-01-13T07:39:49","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=182013"},"modified":"2025-01-13T07:39:51","modified_gmt":"2025-01-13T07:39:51","slug":"the-element-with-an-electron-configuration-of-1s2-2s2-2p6-3s2-3p6-4s2-3d10-4p4-is-in-group-and-period-the-element-with-an-electron-configuration-of-1s2-2s2-2p2-is-in-group-__-and-period","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/13\/the-element-with-an-electron-configuration-of-1s2-2s2-2p6-3s2-3p6-4s2-3d10-4p4-is-in-group-and-period-the-element-with-an-electron-configuration-of-1s2-2s2-2p2-is-in-group-__-and-period\/","title":{"rendered":"The element with an electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4 is in group and period The element with an electron configuration of 1s2 2s2 2p2 is in group __ and period"},"content":{"rendered":"\n<p>The element with an electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4 is in group and period The element with an electron configuration of 1s2 2s2 2p2 is in group __ and period<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Let&#8217;s first examine the two electron configurations and deduce their respective elements.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">First Electron Configuration:<\/h3>\n\n\n\n<p>1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 4s\u00b2 3d\u00b9\u2070 4p\u2074<\/p>\n\n\n\n<p>This configuration represents an element with:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 electrons in the 1s orbital (1s\u00b2),<\/li>\n\n\n\n<li>2 electrons in the 2s orbital (2s\u00b2),<\/li>\n\n\n\n<li>6 electrons in the 2p orbital (2p\u2076),<\/li>\n\n\n\n<li>2 electrons in the 3s orbital (3s\u00b2),<\/li>\n\n\n\n<li>6 electrons in the 3p orbital (3p\u2076),<\/li>\n\n\n\n<li>2 electrons in the 4s orbital (4s\u00b2),<\/li>\n\n\n\n<li>10 electrons in the 3d orbital (3d\u00b9\u2070),<\/li>\n\n\n\n<li>4 electrons in the 4p orbital (4p\u2074).<\/li>\n<\/ul>\n\n\n\n<p>This corresponds to an element in <strong>Group 16<\/strong> (since the last subshell, 4p, has 4 electrons) and <strong>Period 4<\/strong> (since the highest principal quantum number is 4).<\/p>\n\n\n\n<p><strong>Conclusion:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Group: 16<\/li>\n\n\n\n<li>Period: 4<\/li>\n<\/ul>\n\n\n\n<p>This element is <strong>Selenium (Se)<\/strong>, which is a nonmetal found in Group 16 (the chalcogens) and Period 4 of the periodic table.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Second Electron Configuration:<\/h3>\n\n\n\n<p>1s\u00b2 2s\u00b2 2p\u00b2<\/p>\n\n\n\n<p>This configuration represents an element with:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 electrons in the 1s orbital (1s\u00b2),<\/li>\n\n\n\n<li>2 electrons in the 2s orbital (2s\u00b2),<\/li>\n\n\n\n<li>2 electrons in the 2p orbital (2p\u00b2).<\/li>\n<\/ul>\n\n\n\n<p>This corresponds to an element in <strong>Group 14<\/strong> (since the last subshell, 2p, has 2 electrons) and <strong>Period 2<\/strong> (since the highest principal quantum number is 2).<\/p>\n\n\n\n<p><strong>Conclusion:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Group: 14<\/li>\n\n\n\n<li>Period: 2<\/li>\n<\/ul>\n\n\n\n<p>This element is <strong>Carbon (C)<\/strong>, which is a nonmetal found in Group 14 (the carbon group) and Period 2 of the periodic table.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>The periodic table is organized by electron configurations. The <strong>group number<\/strong> corresponds to the number of valence electrons an element has in its outermost shell, while the <strong>period number<\/strong> reflects the highest principal energy level in the electron configuration.<\/p>\n\n\n\n<p>In the first example (1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 4s\u00b2 3d\u00b9\u2070 4p\u2074), Selenium has 4 valence electrons in its 4p orbital, placing it in Group 16 and Period 4. In the second example (1s\u00b2 2s\u00b2 2p\u00b2), Carbon has 4 valence electrons in its 2p orbital, placing it in Group 14 and Period 2.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The element with an electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4 is in group and period The element with an electron configuration of 1s2 2s2 2p2 is in group __ and period The Correct Answer and Explanation is : Let&#8217;s first examine the two electron configurations and deduce their respective elements. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-182013","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182013","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=182013"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182013\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=182013"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=182013"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=182013"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}