What is the mass in milligrams of<\/p>\n\n\n\n
(a) 0.367 mol of HNO3?<\/p>\n\n\n\n
(b) 245 mmol of MgO?<\/p>\n\n\n\n
(c) 12.5 mol of NH4NO3?<\/p>\n\n\n\n
(d) 4.95 mol of (NH4)2Ce(NO3)6 (548.23 g\/mol)?<\/p>\n\n\n\n
(a) 3.20 mol of KBr?<\/p>\n\n\n\n
(b) 18.9 mmol of PbO?<\/p>\n\n\n\n
(c) 6.02 mol of MgSO4?<\/p>\n\n\n\n
(d) 10.9 mmol of Fe(NH4)2(SO4)2 . 6H2O?<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To solve the given problems, we use the formula:<\/p>\n\n\n\n [ First, calculate molar masses for each compound, then multiply by the given number of moles or millimoles (1 mmol = (10^{-3}) mol) to find the mass.<\/p>\n\n\n\n The key is understanding the relationship between moles, molar mass, and mass. Molar mass gives the weight of one mole of a compound, allowing direct conversion from moles to grams (or milligrams for smaller quantities). Ensure units are consistent\u2014convert mmol to moles and grams to mg when necessary. This calculation is essential in chemistry for preparing solutions or determining reactant\/product amounts.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the mass in milligrams of (a) 0.367 mol of HNO3? (b) 245 mmol of MgO? (c) 12.5 mol of NH4NO3? (d) 4.95 mol of (NH4)2Ce(NO3)6 (548.23 g\/mol)? (a) 3.20 mol of KBr? (b) 18.9 mmol of PbO? (c) 6.02 mol of MgSO4? (d) 10.9 mmol of Fe(NH4)2(SO4)2 . 6H2O? The Correct Answer and […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-182125","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182125","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=182125"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182125\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=182125"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=182125"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=182125"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\\text{Mass} = \\text{Moles} \\times \\text{Molar Mass}.
]<\/p>\n\n\n\n
\n\n\n\nMass in Milligrams:<\/h3>\n\n\n\n
\n
Molar mass of HNO\u2083 = 1 (H) + 14 (N) + 16\u00d73 (O) = 63 g\/mol.
[
\\text{Mass} = 0.367 \\, \\text{mol} \\times 63 \\, \\text{g\/mol} = 23.121 \\, \\text{g}.
]
Convert to mg: (23.121 \\, \\text{g} \\times 1000 = 23,121 \\, \\text{mg}.)<\/li>\n\n\n\n
Molar mass of MgO = 24.3 (Mg) + 16 (O) = 40.3 g\/mol.
[
\\text{Mass} = 245 \\times 10^{-3} \\, \\text{mol} \\times 40.3 \\, \\text{g\/mol} = 9.8715 \\, \\text{g}.
]
Convert to mg: (9.8715 \\, \\text{g} \\times 1000 = 9,871.5 \\, \\text{mg}.)<\/li>\n\n\n\n
Molar mass of NH\u2084NO\u2083 = 14 (N) \u00d7 2 + 1\u00d74 (H) + 16\u00d73 (O) = 80 g\/mol.
[
\\text{Mass} = 12.5 \\, \\text{mol} \\times 80 \\, \\text{g\/mol} = 1,000 \\, \\text{g}.
]
Convert to mg: (1,000 \\, \\text{g} \\times 1000 = 1,000,000 \\, \\text{mg}.)<\/li>\n\n\n\n
Molar mass = (548.23 \\, \\text{g\/mol}).
[
\\text{Mass} = 4.95 \\, \\text{mol} \\times 548.23 \\, \\text{g\/mol} = 2,712.7 \\, \\text{g}.
]
Convert to mg: (2,712.7 \\, \\text{g} \\times 1000 = 2,712,700 \\, \\text{mg}.)<\/li>\n<\/ol>\n\n\n\n
\n\n\n\nMass in Grams:<\/h3>\n\n\n\n
\n
Molar mass of KBr = 39.1 (K) + 79.9 (Br) = 119 g\/mol.
[
\\text{Mass} = 3.20 \\, \\text{mol} \\times 119 \\, \\text{g\/mol} = 380.8 \\, \\text{g}.
]<\/li>\n\n\n\n
Molar mass of PbO = 207.2 (Pb) + 16 (O) = 223.2 g\/mol.
[
\\text{Mass} = 18.9 \\times 10^{-3} \\, \\text{mol} \\times 223.2 \\, \\text{g\/mol} = 4.2185 \\, \\text{g}.
]<\/li>\n\n\n\n
Molar mass of MgSO\u2084 = 24.3 (Mg) + 32.1 (S) + 16\u00d74 (O) = 120.4 g\/mol.
[
\\text{Mass} = 6.02 \\, \\text{mol} \\times 120.4 \\, \\text{g\/mol} = 724.8 \\, \\text{g}.
]<\/li>\n\n\n\n
Molar mass = (392.14 \\, \\text{g\/mol}).
[
\\text{Mass} = 10.9 \\times 10^{-3} \\, \\text{mol} \\times 392.14 \\, \\text{g\/mol} = 4.273 \\, \\text{g}.
]<\/li>\n<\/ol>\n\n\n\n
\n\n\n\nExplanation:<\/h3>\n\n\n\n