{"id":182158,"date":"2025-01-13T13:02:58","date_gmt":"2025-01-13T13:02:58","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=182158"},"modified":"2025-01-13T13:03:00","modified_gmt":"2025-01-13T13:03:00","slug":"you-illuminate-a-slit-with-a-width-of-70-5-um-with-a-light-of-wavelength-727-nm-and-observe-the-resulting-diffraction-pattern-on-a-screen-that-is-situated-2-83-m-from-the-slit","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/13\/you-illuminate-a-slit-with-a-width-of-70-5-um-with-a-light-of-wavelength-727-nm-and-observe-the-resulting-diffraction-pattern-on-a-screen-that-is-situated-2-83-m-from-the-slit\/","title":{"rendered":"You illuminate a slit with a width of 70.5 um with a light of wavelength 727 nm and observe the resulting diffraction pattern on a screen that is situated 2.83 m from the slit"},"content":{"rendered":"\n

You illuminate a slit with a width of 70.5 um with a light of wavelength 727 nm and observe the resulting diffraction pattern on a screen that is situated 2.83 m from the slit. What is the width, in centimeters, of the pattern’s central maximum? width: 8.8 cm Incorrect Light of wavelength 558.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 86.5 cm from the slit. The distance on the screen between the third order minimum and the central maximum is 1.87 cm. What is the width a of the slit in micrometers (um)? a= 5.16 x10-5 um Incorrect<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

To solve these diffraction problems, we need to use the diffraction formula for a single slit, which is given by:<\/p>\n\n\n\n

[
\\sin(\\theta_m) = \\frac{m \\lambda}{a}
]<\/p>\n\n\n\n

where:<\/p>\n\n\n\n