{"id":182208,"date":"2025-01-13T13:45:52","date_gmt":"2025-01-13T13:45:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=182208"},"modified":"2025-01-13T13:45:55","modified_gmt":"2025-01-13T13:45:55","slug":"the-substance-cs%e2%82%82-has-a-melting-point-of-110-8-c-and-a-boiling-point-of-46-3-c","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/13\/the-substance-cs%e2%82%82-has-a-melting-point-of-110-8-c-and-a-boiling-point-of-46-3-c\/","title":{"rendered":"The substance CS\u2082 has a melting point of -110.8 \u00b0C and a boiling point of 46.3 \u00b0C"},"content":{"rendered":"\n

The substance CS\u2082 has a melting point of -110.8 \u00b0C and a boiling point of 46.3 \u00b0C. Its density at 20 \u00b0C is 1.26 g\/cm\u00b3. It is highly flammable. (a) What is the name of this compound? (b) List the intermolecular forces that CS2 molecules exert on one another. (c) Write a balanced equation for the combustion of this compound in air. (You will have to decide on the most likely oxidation products.) (d) The critical temperature and pressure for CS2 are 552 K and 78 atm, respectively. Compare these values with those for CO\u2082 in Table 11.5 and discuss the possible origins of the differences.<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

(a) Name of the compound:<\/strong><\/p>\n\n\n\n

The substance CS\u2082<\/strong> is carbon disulfide<\/strong>. It consists of one carbon atom bonded to two sulfur atoms.<\/p>\n\n\n\n

(b) Intermolecular forces:<\/strong><\/p>\n\n\n\n

Carbon disulfide molecules exert London dispersion forces<\/strong> (also known as Van der Waals forces) on one another. These forces are the result of temporary dipoles that form due to fluctuations in the electron cloud distribution. CS\u2082 is a non-polar molecule because the linear arrangement of the molecule causes the dipoles of the two C-S bonds to cancel each other out. Since CS\u2082 does not have dipole-dipole interactions or hydrogen bonding, the primary intermolecular force is London dispersion forces.<\/p>\n\n\n\n

(c) Balanced equation for combustion:<\/strong><\/p>\n\n\n\n

The combustion of carbon disulfide in air (which consists of oxygen, O\u2082) typically leads to the formation of carbon dioxide (CO\u2082) and sulfur dioxide (SO\u2082) as oxidation products. The balanced equation for this reaction is:<\/p>\n\n\n\n

[
\\text{CS}_2 (l) + 3\\text{O}_2 (g) \\rightarrow \\text{CO}_2 (g) + 2\\text{SO}_2 (g)
]<\/p>\n\n\n\n

This equation is balanced by ensuring the number of atoms of each element on both sides is equal. For each molecule of CS\u2082, one molecule of carbon dioxide and two molecules of sulfur dioxide are produced, using up three molecules of oxygen gas.<\/p>\n\n\n\n

(d) Comparison with CO\u2082:<\/strong><\/p>\n\n\n\n