{"id":182249,"date":"2025-01-13T14:30:11","date_gmt":"2025-01-13T14:30:11","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=182249"},"modified":"2025-01-13T14:30:14","modified_gmt":"2025-01-13T14:30:14","slug":"ir-spectrum-for-product-obtained","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/13\/ir-spectrum-for-product-obtained\/","title":{"rendered":"IR Spectrum for Product Obtained"},"content":{"rendered":"\n

IR Spectrum for Product Obtained 0.8 0.6 Transmitance worm 0.2 3500 3000 2500 1500 1000 500 2000 Wavenumbers (cm-1). (2pts) Upload your annotated IR spectrum. If you are completing this report virtually, download the IR spectra above and annotate it. Complete the table with 3 Major IR peaks. Saved Normal . ????? X2 X = fc 8 TH TE Report Table BO.1: IR Analysis IR Peak, cm-1 Bond Type (2pts) Use 1-2 key peaks to justify what compound(s) that you think are present. Saved Normal . BIU X2 X fx IIIII IX Does this suggest that your reaction worked? Use 1 or two key IR peaks to justify your answer. Normal BIU X2 X = fa e ? | T| ?=|| TK (2pts) What does this IR data indicate about the purity of the product? Use 1 or two key IR peaks to justify your answer. Saved Normal BIU X21 X2 ? = fy lilli *<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n
\"\"<\/figure>\n\n\n\n
\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

To assist you with the IR analysis, we need to follow these steps:<\/p>\n\n\n\n

1. Identify Major IR Peaks:<\/strong><\/h3>\n\n\n\n

The IR spectrum shows absorbances (peaks) that correspond to vibrations of different bonds in the compound. The most important peaks usually occur between 3500 and 1500 cm-1, as they correspond to functional groups that are key to identifying the structure.<\/p>\n\n\n\n

Given the information:<\/p>\n\n\n\n

    \n
  • 3500 cm-1 (Broad, strong):<\/strong> Likely an O-H stretch, suggesting the presence of an alcohol or carboxylic acid group.<\/li>\n\n\n\n
  • 3000 cm-1 (Medium, sharp):<\/strong> This typically corresponds to the C-H stretch of alkyl groups.<\/li>\n\n\n\n
  • 1600 cm-1 (Medium, sharp):<\/strong> This could indicate a C=C stretch, common for alkenes or aromatic compounds. You can annotate your IR spectrum by marking these regions and highlighting the relevant peaks.<\/li>\n<\/ul>\n\n\n\n

    2. Complete the Table:<\/strong><\/h3>\n\n\n\n
      \n
    • IR Peak (cm-1):<\/strong>\n
        \n
      • 3500 cm-1:<\/strong> O-H stretch (likely alcohol or carboxylic acid).<\/li>\n\n\n\n
      • 3000 cm-1:<\/strong> C-H stretch (alkyl group).<\/li>\n\n\n\n
      • 1600 cm-1:<\/strong> C=C stretch (alkene or aromatic).<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • Bond Type:<\/strong>\n
          \n
        • O-H (Alcohol\/Carboxylic Acid).<\/li>\n\n\n\n
        • C-H (Alkyl).<\/li>\n\n\n\n
        • C=C (Alkene or Aromatic).<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n

          3. Does the Reaction Appear to Have Worked?<\/strong><\/h3>\n\n\n\n

          You can check for the disappearance of functional groups that were present in the starting material and the appearance of new peaks. For example:<\/p>\n\n\n\n

            \n
          • If an alcohol (O-H stretch) appears in the product, and the starting material was an alcohol, then the reaction worked as expected.<\/li>\n\n\n\n
          • The presence of a carbonyl stretch (around 1700 cm-1) in place of an alcohol peak might suggest the formation of an ester or other carbonyl-containing compound.<\/li>\n<\/ul>\n\n\n\n

            4. Purity of the Product:<\/strong><\/h3>\n\n\n\n

            If there are unexpected peaks or residual starting material peaks, this could indicate impurities. For example:<\/p>\n\n\n\n

              \n
            • If peaks corresponding to starting materials (e.g., C-H stretches of alkyl groups) are still present, the product might not be pure.<\/li>\n\n\n\n
            • If there\u2019s a broad O-H stretch with no accompanying carbonyl stretch, it may suggest incomplete reaction or the presence of water.<\/li>\n<\/ul>\n\n\n\n

              By focusing on key functional group peaks, you can determine the identity and purity of the product. However, additional details from the spectrum itself would be necessary for a more in-depth analysis.<\/p>\n\n\n\n

              Let me know if you’d like help with a specific part of the IR interpretation!<\/p>\n","protected":false},"excerpt":{"rendered":"

              IR Spectrum for Product Obtained 0.8 0.6 Transmitance worm 0.2 3500 3000 2500 1500 1000 500 2000 Wavenumbers (cm-1). (2pts) Upload your annotated IR spectrum. If you are completing this report virtually, download the IR spectra above and annotate it. Complete the table with 3 Major IR peaks. Saved Normal . ????? X2 X = […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-182249","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182249","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=182249"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182249\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=182249"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=182249"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=182249"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}