{"id":182259,"date":"2025-01-13T14:35:26","date_gmt":"2025-01-13T14:35:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=182259"},"modified":"2025-01-13T14:35:28","modified_gmt":"2025-01-13T14:35:28","slug":"melting-or-boiling-point-of-hydrocarbons","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/13\/melting-or-boiling-point-of-hydrocarbons\/","title":{"rendered":"Melting or Boiling Point of Hydrocarbons"},"content":{"rendered":"\n<p>C. Melting or Boiling Point of Hydrocarbons. Example: Cyclooctane Cyclopentane 1. \u00c3\ufffd\u00c2\ufffd\u00c3\ufffd\u00c2\u00b5\u00c3\u2018\u00e2\u20ac\u00a6\u00c3\ufffd\u00c2\u00b0\u00c3\ufffd\u00c2\u00bf\u00c3\ufffd\u00c2\u00b5 Octane 2. Cyclohexane \u00c3\ufffd\u00c2\ufffd\u00c3\ufffd\u00c2\u00b5\u00c3\u2018\u00e2\u20ac\u00a6ane 3. Methane Ethane 4. Pentane Cyclooctane 5. Cyclobutane Cycloheptane 6. 2-\u00c3\ufffd\u00c2\ufffd\u00c3\ufffd\u00c2\u00b5\u00c3\u2018\u00e2\u20ac\u00a6\u00c3\ufffd\u00c2\u00b5\u00c3\ufffd\u00c2\u00bfe 2-Octene 7. Cyclobutene Cyclooctene<br>Melting or Boiling Point of Hydrocarbons<\/p>\n\n\n\n<p>Procedure:\u00c3\u201a\u00c2<\/p>\n\n\n\n<p>In the picture below,\u00c3\u201a\u00c2 ENCIRCLE\u00c3\u201a\u00c2 the compound that has higher boiling point or melting point for each\u00c3\u201a\u00c2 of the following pairs.\u00c3\u201a\u00c2 \u00c3\u201a\u00c2<\/p>\n\n\n\n<p>The longer the hydrocarbon chain or ring size the higher the melting or boiling points. 3. Cyclic structures have higher boiling or melting points than their non-cyclic counterparts with the same\u00c3\u201a\u00c2 number of carbon atoms. These differences are due in large part to cyclic systems having more rigid\u00c3\u201a\u00c2 and more symmetrical structures.\u00c3\u201a\u00c2<br>Example:\u00c3\u201a\u00c2<\/p>\n\n\n\n<p>o Propane has higher melting or boiling point compared to ethane because propane has longer\u00c3\u201a\u00c2 hydrocarbon chain which is composed of 3 carbon atoms in contrast to ethane which is composed\u00c3\u201a\u00c2 only of 2 carbon atoms.<\/p>\n\n\n\n<p>o Cyclopentene has higher melting or boiling point compared to cyclobutene because cyclopentene\u00c3\u201a\u00c2 has larger ring size which is composed of 5 carbon atoms in contrast to cyclobutene which is\u00c3\u201a\u00c2 composed only of 4 carbon atoms.\u00c3\u201a\u00c2<\/p>\n\n\n\n<p>o Cyclopropane has higher melting or boiling point compared to propane because cyclic structures\u00c3\u201a\u00c2 have higher boiling or melting points than their non-cyclic counterparts with the same number of\u00c3\u201a\u00c2 carbon atoms. These differences are due in large part to cyclic systems having more rigid and\u00c3\u201a\u00c2 more symmetrical structures.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/01\/image-163-1024x584.png\" alt=\"\" class=\"wp-image-182260\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The picture and procedure you referred to discuss the comparison of boiling or melting points of hydrocarbons. The general principles for determining the compound with a higher boiling or melting point in the pairs you listed are based on chain length and structural differences. Here\u2019s how you can approach the given pairs:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Cyclooctane vs Cyclopentane<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>Cyclooctane<\/strong> has 8 carbon atoms in a ring, while <strong>Cyclopentane<\/strong> has 5. According to the rule that cyclic structures have higher boiling or melting points than their non-cyclic counterparts with the same number of carbon atoms, cyclooctane has a higher boiling\/melting point due to its larger ring size and increased symmetry and rigidity.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Octane vs Cyclohexane<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>Octane<\/strong> (C8H18) is a straight-chain alkane, while <strong>Cyclohexane<\/strong> (C6H12) is a cyclic compound. Even though octane has more carbon atoms, cyclohexane\u2019s cyclic structure makes it more rigid and symmetric, increasing its boiling\/melting point. Therefore, <strong>Cyclohexane<\/strong> has a higher boiling\/melting point.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Methane vs Ethane<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>Ethane<\/strong> (C2H6) has a longer carbon chain compared to <strong>Methane<\/strong> (CH4), so <strong>Ethane<\/strong> has a higher boiling\/melting point.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Pentane vs Cyclooctane<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>Cyclooctane<\/strong> is a cyclic compound with 8 carbon atoms, while <strong>Pentane<\/strong> (C5H12) is a straight-chain alkane. As noted, cyclic compounds have higher boiling\/melting points than non-cyclic ones with the same number of carbon atoms. Therefore, <strong>Cyclooctane<\/strong> has a higher boiling\/melting point.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Cyclobutane vs Cycloheptane<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>Cycloheptane<\/strong> (C7H14) has a larger ring size compared to <strong>Cyclobutane<\/strong> (C4H8), and cyclic structures are more stable and symmetrical. Therefore, <strong>Cycloheptane<\/strong> has a higher boiling\/melting point.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>2-Octene vs Cycloheptene<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>Cycloheptene<\/strong> is a cyclic compound, while <strong>2-Octene<\/strong> is a straight-chain alkene. Following the trend, <strong>Cycloheptene<\/strong> has a higher boiling\/melting point due to its cyclic structure.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Cyclobutene vs Cyclooctene<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>Cyclooctene<\/strong> has a larger ring size (8 carbon atoms) compared to <strong>Cyclobutene<\/strong> (4 carbon atoms), so <strong>Cyclooctene<\/strong> has a higher boiling\/melting point.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p><strong>Explanation<\/strong>: In hydrocarbons, several factors determine the melting or boiling points: the size of the molecule, whether the structure is cyclic or acyclic, and the symmetry and rigidity of the molecule. Cyclic compounds generally have higher melting and boiling points because their structures are more rigid and symmetric, allowing for stronger intermolecular forces. Additionally, longer chains or larger rings increase the surface area for van der Waals forces, which also contributes to higher boiling or melting points. Thus, when comparing hydrocarbons, cyclic structures tend to have higher melting or boiling points than their acyclic counterparts with the same number of carbon atoms, and longer hydrocarbon chains or larger ring sizes also lead to higher melting\/boiling points.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>C. Melting or Boiling Point of Hydrocarbons. Example: Cyclooctane Cyclopentane 1. \u00c3\ufffd\u00c2\ufffd\u00c3\ufffd\u00c2\u00b5\u00c3\u2018\u00e2\u20ac\u00a6\u00c3\ufffd\u00c2\u00b0\u00c3\ufffd\u00c2\u00bf\u00c3\ufffd\u00c2\u00b5 Octane 2. Cyclohexane \u00c3\ufffd\u00c2\ufffd\u00c3\ufffd\u00c2\u00b5\u00c3\u2018\u00e2\u20ac\u00a6ane 3. Methane Ethane 4. Pentane Cyclooctane 5. Cyclobutane Cycloheptane 6. 2-\u00c3\ufffd\u00c2\ufffd\u00c3\ufffd\u00c2\u00b5\u00c3\u2018\u00e2\u20ac\u00a6\u00c3\ufffd\u00c2\u00b5\u00c3\ufffd\u00c2\u00bfe 2-Octene 7. Cyclobutene CycloocteneMelting or Boiling Point of Hydrocarbons Procedure:\u00c3\u201a\u00c2 In the picture below,\u00c3\u201a\u00c2 ENCIRCLE\u00c3\u201a\u00c2 the compound that has higher boiling point or melting point for each\u00c3\u201a\u00c2 of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-182259","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182259","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=182259"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182259\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=182259"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=182259"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=182259"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}