{"id":182525,"date":"2025-01-14T07:38:00","date_gmt":"2025-01-14T07:38:00","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=182525"},"modified":"2025-01-14T07:38:02","modified_gmt":"2025-01-14T07:38:02","slug":"this-compound-is-called-2-bromo-5-ethylcyclohexanol-4-bromo-1-ethyl-5-phenol-2-bromo-5-ethylphenol-6-bromo-3-ethylphenol-in-a-tertiary-alcohol","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/14\/this-compound-is-called-2-bromo-5-ethylcyclohexanol-4-bromo-1-ethyl-5-phenol-2-bromo-5-ethylphenol-6-bromo-3-ethylphenol-in-a-tertiary-alcohol\/","title":{"rendered":"This compound is called 2-bromo-5-ethylcyclohexanol 4-bromo-1-ethyl-5-phenol 2-bromo-5-ethylphenol 6-bromo-3-ethylphenol In a tertiary alcohol"},"content":{"rendered":"\n<p>This compound is called 2-bromo-5-ethylcyclohexanol 4-bromo-1-ethyl-5-phenol 2-bromo-5-ethylphenol 6-bromo-3-ethylphenol In a tertiary alcohol, a hydroxzyl group is linked to a(n) disubstituted carbon. triple-bonded carbon. double bonded carbon. trisubstituted carbon<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/01\/image-186.png\" alt=\"\" class=\"wp-image-182526\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/01\/image-187.png\" alt=\"\" class=\"wp-image-182527\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Let&#8217;s break down the information in your question.<\/p>\n\n\n\n<p>You are asking about the structure of a tertiary alcohol and a specific compound&#8217;s name, followed by identifying the correct type of carbon to which a hydroxyl group is attached.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. Compound Name:<\/h3>\n\n\n\n<p>You provided a list of compounds:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>2-bromo-5-ethylcyclohexanol<\/strong><\/li>\n\n\n\n<li><strong>4-bromo-1-ethyl-5-phenol<\/strong><\/li>\n\n\n\n<li><strong>2-bromo-5-ethylphenol<\/strong><\/li>\n\n\n\n<li><strong>6-bromo-3-ethylphenol<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Based on these names, the hydroxyl group (OH) is likely attached to a carbon in the structure of the compound. The first compound, <strong>2-bromo-5-ethylcyclohexanol<\/strong>, includes the word &#8220;cyclohexanol&#8221; which indicates the presence of a hydroxyl group attached to a cyclohexane ring.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">2. Tertiary Alcohol and Carbon Types:<\/h3>\n\n\n\n<p>A <strong>tertiary alcohol<\/strong> has a hydroxyl group (-OH) attached to a <strong>tertiary carbon<\/strong>, which means the carbon holding the hydroxyl group is connected to three other carbon atoms. In your question, the options you gave were:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Disubstituted carbon<\/strong>: A carbon connected to two other carbon atoms.<\/li>\n\n\n\n<li><strong>Triple-bonded carbon<\/strong>: A carbon connected to another carbon by a triple bond.<\/li>\n\n\n\n<li><strong>Double-bonded carbon<\/strong>: A carbon connected to another carbon by a double bond.<\/li>\n\n\n\n<li><strong>Trisubstituted carbon<\/strong>: A carbon connected to three other carbon atoms.<\/li>\n<\/ul>\n\n\n\n<p>The correct answer for the type of carbon that a hydroxyl group is attached to in a <strong>tertiary alcohol<\/strong> is <strong>trisubstituted carbon<\/strong>, as it is a carbon that is bonded to three other carbon atoms.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>In the case of a <strong>tertiary alcohol<\/strong>, the hydroxyl group is attached to a <strong>tertiary carbon<\/strong>, meaning that the carbon holding the OH group is attached to three other carbon atoms. This is a defining feature of tertiary alcohols. This is in contrast to primary and secondary alcohols, where the hydroxyl group is attached to a primary or secondary carbon, respectively, which are only bonded to one or two other carbon atoms.<\/p>\n\n\n\n<p>In the context of your compounds, if you were referring to a structure such as <strong>2-bromo-5-ethylcyclohexanol<\/strong>, the position of the hydroxyl group would likely be on a carbon within the cyclohexane ring that is bonded to three other carbon atoms, making it a tertiary carbon.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>This compound is called 2-bromo-5-ethylcyclohexanol 4-bromo-1-ethyl-5-phenol 2-bromo-5-ethylphenol 6-bromo-3-ethylphenol In a tertiary alcohol, a hydroxzyl group is linked to a(n) disubstituted carbon. triple-bonded carbon. double bonded carbon. trisubstituted carbon The Correct Answer and Explanation is : Let&#8217;s break down the information in your question. You are asking about the structure of a tertiary alcohol and a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-182525","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182525","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=182525"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182525\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=182525"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=182525"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=182525"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}