{"id":182909,"date":"2025-01-15T07:00:38","date_gmt":"2025-01-15T07:00:38","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=182909"},"modified":"2025-01-15T07:00:41","modified_gmt":"2025-01-15T07:00:41","slug":"write-an-equation-for-the-function-graphed-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/15\/write-an-equation-for-the-function-graphed-below\/","title":{"rendered":"Write an equation for the function graphed below"},"content":{"rendered":"\n

Write an equation for the function graphed below. The y<\/em> intercept is at (0,-0.5)<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

To determine the equation of a line with a y-intercept at (0, -0.5), we can utilize the slope-intercept form of a linear equation:<\/p>\n\n\n\n

[ y = mx + c ]<\/p>\n\n\n\n

Here, ( m ) represents the slope of the line, and ( c ) denotes the y-intercept. Given that the y-intercept is at (0, -0.5), we know ( c = -0.5 ). Therefore, the equation becomes:<\/p>\n\n\n\n

[ y = mx – 0.5 ]<\/p>\n\n\n\n

To fully define the equation, we need the slope ( m ). The slope indicates the rate at which ( y ) changes with respect to ( x ). Without additional information, such as another point on the line or the slope value, we cannot determine the exact value of ( m ).<\/p>\n\n\n\n

For example, if we had another point on the line, say (1, 0), we could calculate the slope using the formula:<\/p>\n\n\n\n

[ m = \\frac{y_2 – y_1}{x_2 – x_1} ]<\/p>\n\n\n\n

Substituting the points (0, -0.5) and (1, 0):<\/p>\n\n\n\n

[ m = \\frac{0 – (-0.5)}{1 – 0} = \\frac{0.5}{1} = 0.5 ]<\/p>\n\n\n\n

Thus, the equation of the line would be:<\/p>\n\n\n\n

[ y = 0.5x – 0.5 ]<\/p>\n\n\n\n

In summary, while we can establish the general form of the equation as [ y = mx – 0.5 ], the exact equation requires knowledge of the slope ( m ), which can be determined if another point on the line is provided.<\/p>\n","protected":false},"excerpt":{"rendered":"

Write an equation for the function graphed below. The y intercept is at (0,-0.5) The Correct Answer and Explanation is : To determine the equation of a line with a y-intercept at (0, -0.5), we can utilize the slope-intercept form of a linear equation: [ y = mx + c ] Here, ( m ) represents the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-182909","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182909","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=182909"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/182909\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=182909"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=182909"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=182909"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}