{"id":183269,"date":"2025-01-16T06:48:03","date_gmt":"2025-01-16T06:48:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=183269"},"modified":"2025-01-16T06:48:05","modified_gmt":"2025-01-16T06:48:05","slug":"draw-the-lewis-structures-of-so3na-and-h3co","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/16\/draw-the-lewis-structures-of-so3na-and-h3co\/","title":{"rendered":"Draw the lewis structures of SO3Na and H3CO"},"content":{"rendered":"\n<p>Draw the lewis structures of SO3Na and H3CO<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To understand the Lewis structures of <strong>SO\u2083Na<\/strong> and <strong>H\u2083CO<\/strong>, let&#8217;s break them down:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>SO\u2083Na (Sodium Sulfite)<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Atoms involved:<\/strong> Sodium (Na), Sulfur (S), and Oxygen (O).<\/li>\n\n\n\n<li><strong>Step 1: Identify the central atom.<\/strong><br>Sulfur is the central atom as it is less electronegative than oxygen and can form multiple bonds.<\/li>\n\n\n\n<li><strong>Step 2: Count valence electrons.<\/strong><\/li>\n\n\n\n<li>Sodium (Na): 1 valence electron.<\/li>\n\n\n\n<li>Sulfur (S): 6 valence electrons.<\/li>\n\n\n\n<li>Oxygen (O): 6 valence electrons (3 oxygens in total). Total valence electrons: 1 (Na) + 6 (S) + 3\u00d76 (O) = 25 valence electrons.<\/li>\n\n\n\n<li><strong>Step 3: Bonding.<\/strong><br>Sodium (Na) will lose its one valence electron, forming a Na\u207a ion. This leaves behind the sulfate ion (SO\u2083\u00b2\u207b), where sulfur is double-bonded to each oxygen atom.<\/li>\n\n\n\n<li><strong>Step 4: Assign electron pairs.<\/strong><\/li>\n\n\n\n<li>Sulfur (S) will form 3 double bonds with the three oxygen atoms. This uses up 6 electrons.<\/li>\n\n\n\n<li>Each oxygen will have 2 lone pairs, each using up 2 electrons (3\u00d72 = 6).<\/li>\n\n\n\n<li>This structure leaves 2 extra electrons that will be placed on sulfur to complete its octet.<\/li>\n<\/ul>\n\n\n\n<p>The <strong>Lewis structure<\/strong> of SO\u2083Na shows sulfur double-bonded to three oxygens with one oxygen forming an ionic bond with sodium. The sulfur atom has a formal charge of 0, and each oxygen has a formal charge of -1.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>H\u2083CO (Formyl Group)<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Atoms involved:<\/strong> Hydrogen (H), Carbon (C), and Oxygen (O).<\/li>\n\n\n\n<li><strong>Step 1: Identify the central atom.<\/strong><br>Carbon is the central atom as it is less electronegative than oxygen.<\/li>\n\n\n\n<li><strong>Step 2: Count valence electrons.<\/strong><\/li>\n\n\n\n<li>Hydrogen (H): 1 valence electron (3 hydrogens = 3).<\/li>\n\n\n\n<li>Carbon (C): 4 valence electrons.<\/li>\n\n\n\n<li>Oxygen (O): 6 valence electrons. Total valence electrons: 3 (H) + 4 (C) + 6 (O) = 13 valence electrons.<\/li>\n\n\n\n<li><strong>Step 3: Bonding.<\/strong><br>Carbon will be bonded to 3 hydrogens and double-bonded to oxygen.<\/li>\n\n\n\n<li><strong>Step 4: Assign electron pairs.<\/strong><\/li>\n\n\n\n<li>Carbon (C) will have 3 single bonds with hydrogen and 1 double bond with oxygen.<\/li>\n\n\n\n<li>Oxygen will have 2 lone pairs.<\/li>\n<\/ul>\n\n\n\n<p>The <strong>Lewis structure<\/strong> of H\u2083CO shows carbon bonded to three hydrogen atoms and double-bonded to oxygen. The oxygen atom has 2 lone pairs.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>SO\u2083Na<\/strong>: Sulfur is double-bonded to three oxygens, with one oxygen ionically bonded to sodium.<\/li>\n\n\n\n<li><strong>H\u2083CO<\/strong>: Carbon is single-bonded to three hydrogens and double-bonded to oxygen.<\/li>\n<\/ul>\n\n\n\n<p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw the lewis structures of SO3Na and H3CO The Correct Answer and Explanation is : To understand the Lewis structures of SO\u2083Na and H\u2083CO, let&#8217;s break them down: 1. SO\u2083Na (Sodium Sulfite) The Lewis structure of SO\u2083Na shows sulfur double-bonded to three oxygens with one oxygen forming an ionic bond with sodium. The sulfur atom [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-183269","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/183269","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=183269"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/183269\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=183269"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=183269"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=183269"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}