{"id":183750,"date":"2025-01-17T05:17:17","date_gmt":"2025-01-17T05:17:17","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=183750"},"modified":"2025-01-17T05:17:20","modified_gmt":"2025-01-17T05:17:20","slug":"inmotion-acceleration-and-kinematic-equations","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/17\/inmotion-acceleration-and-kinematic-equations\/","title":{"rendered":"INMOTION Acceleration and Kinematic Equations"},"content":{"rendered":"\n

Name: PHYSICS Unit 2c INMOTION Acceleration and Kinematic Equations gpb.org\/physics-motion Practice Problems Date: Work each of the following problems. SHOW ALL WORK. 1. A sports car accelerates from rest to 26.8 m\/s (roughly 60 mi\/h) in 5.1 seconds. What is the acceleration of the car? 2. A child goes down a slide, starting from rest. If the length of the slide is 2 m and it takes the child 3 seconds to go down the slide, what is the child’s acceleration? 3. How far does a sled travel in 5 seconds while accelerating from 4 m\/s to 10 m\/s? 4. A fighter jet is catapulted off an aircraft carrier from rest to 75 m\/s. If the aircraft carrier deck is 100 m long, what is the acceleration of the jet? PHYSICS Unit 2C Name: INMOTION>>>> Acceleration and Kinematic Equations gpb.org\/physics-motion Practice Problems Date: Work each of the following problems. SHOW ALL WORK. 5. A driver notices an upcoming speed limit change from 45 mi\/h (20m\/s) to 25 mi\/h (11 m\/s). If she estimates the speed limit will change in 50 m, what acceleration is needed to reach the new speed limit before it begins? 6. One minute after takeoff, a rocket carrying the space shuttle into outer space reaches a speed of 447 m\/s. What was the average acceleration of the rocket during that initial minute? 7. A sprinter accelerates from rest to a velocity of 12 m\/s in the first 6 seconds of the 100-meter dash. a. How far does the sprinter travel during the first 6 seconds? b. How much farther does the sprinter have to travel to reach the finish line? PHYSICS Unit 2C Name: INMOTION>>> Acceleration and Kinematic Equations gpb.org\/physics-motion Practice Problems Date: Work each of the following problems. SHOW ALL WORK. C. If the sprinter travels at a constant velocity of 12 m\/s for the last 64 m, how long will it take to reach the finish line? 8. The school zone in front of your school has a posted speed limit of 25 mi\/h, which is about 11 m\/s. Let’s examine the stopping of a car in several different situations. a. The crossing guard holds up her stop sign, and the driver is paying attention well. The car moves at a constant velocity of 11 m\/s for 2.3 seconds while the driver reacts, then slows down at a constant rate of -4.5 m\/s? What is the stopping distance for the car in this situation? Name: Unit 2C PHYSICS INMOTION>> Acceleration and Kinematic Equations gpb.org\/physics-motion Practice Problems Date: Work each of the following problems. SHOW ALL WORK. b. A child appears to be running into the street ahead. It takes 2.3 seconds for the driver to react and begin to brake, but this time at a rate of -7.5 m\/s2. What is the stopping distance for the car in this situation? c. The driver is looking at her phone and has a total reaction time of 4.6 seconds as the car is moving at a constant speed of 11 m\/s. If the driver slams on her brakes and slows down at a rate of -8.2 m\/s?, what is the stopping distance for the car in this situation? >>> Acceleration and Kinematic Equations gpb.org\/physics-motion Practice Problems Date: Work e”> >> Acceleration and Kinematic Equations gpb.org\/physics-motion Practice Problems Date: Work ea”> > Acceleration and Kinematic Equations gpb.org\/physics-motion Practice Problems Date: Work eac”><\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Here are the solutions and explanations for the given kinematics problems:<\/p>\n\n\n\n

\n\n\n\n

1. Car acceleration:<\/strong><\/h3>\n\n\n\n
    \n
  • Given:<\/strong> Initial velocity ( u = 0 ), final velocity ( v = 26.8 \\, \\text{m\/s} ), time ( t = 5.1 \\, \\text{s} )<\/li>\n\n\n\n
  • Formula:<\/strong> ( a = \\frac{v – u}{t} )<\/li>\n\n\n\n
  • Calculation:<\/strong> ( a = \\frac{26.8 – 0}{5.1} = 5.25 \\, \\text{m\/s}^2 )<\/li>\n\n\n\n
  • Answer:<\/strong> ( 5.25 \\, \\text{m\/s}^2 )<\/li>\n<\/ul>\n\n\n\n
    \n\n\n\n

    2. Child on a slide:<\/strong><\/h3>\n\n\n\n
      \n
    • Given:<\/strong> ( u = 0 ), ( s = 2 \\, \\text{m} ), ( t = 3 \\, \\text{s} )<\/li>\n\n\n\n
    • Formula:<\/strong> ( s = ut + \\frac{1}{2}at^2 )<\/li>\n\n\n\n
    • Calculation:<\/strong> ( 2 = 0 + \\frac{1}{2}a(3)^2 )
      ( a = \\frac{4}{9} = 0.444 \\, \\text{m\/s}^2 )<\/li>\n\n\n\n
    • Answer:<\/strong> ( 0.444 \\, \\text{m\/s}^2 )<\/li>\n<\/ul>\n\n\n\n
      \n\n\n\n

      3. Sled distance:<\/strong><\/h3>\n\n\n\n
        \n
      • Given:<\/strong> ( u = 4 \\, \\text{m\/s} ), ( v = 10 \\, \\text{m\/s} ), ( t = 5 \\, \\text{s} )<\/li>\n\n\n\n
      • Formula:<\/strong> ( s = ut + \\frac{1}{2}at^2 ), where ( a = \\frac{v – u}{t} = \\frac{10 – 4}{5} = 1.2 )<\/li>\n\n\n\n
      • Calculation:<\/strong> ( s = 4(5) + \\frac{1}{2}(1.2)(5)^2 = 20 + 15 = 35 \\, \\text{m} )<\/li>\n\n\n\n
      • Answer:<\/strong> ( 35 \\, \\text{m} )<\/li>\n<\/ul>\n\n\n\n
        \n\n\n\n

        4. Fighter jet acceleration:<\/strong><\/h3>\n\n\n\n
          \n
        • Given:<\/strong> ( u = 0 ), ( v = 75 \\, \\text{m\/s} ), ( s = 100 \\, \\text{m} )<\/li>\n\n\n\n
        • Formula:<\/strong> ( v^2 = u^2 + 2as )<\/li>\n\n\n\n
        • Calculation:<\/strong> ( 75^2 = 0 + 2a(100) )
          ( a = \\frac{5625}{200} = 28.125 \\, \\text{m\/s}^2 )<\/li>\n\n\n\n
        • Answer:<\/strong> ( 28.125 \\, \\text{m\/s}^2 )<\/li>\n<\/ul>\n\n\n\n
          \n\n\n\n

          5. Driver deceleration:<\/strong><\/h3>\n\n\n\n
            \n
          • Given:<\/strong> ( u = 20 \\, \\text{m\/s} ), ( v = 11 \\, \\text{m\/s} ), ( s = 50 \\, \\text{m} )<\/li>\n\n\n\n
          • Formula:<\/strong> ( v^2 = u^2 + 2as )<\/li>\n\n\n\n
          • Calculation:<\/strong> ( 11^2 = 20^2 + 2a(50) )
            ( a = \\frac{121 – 400}{100} = -2.79 \\, \\text{m\/s}^2 )<\/li>\n\n\n\n
          • Answer:<\/strong> ( -2.79 \\, \\text{m\/s}^2 )<\/li>\n<\/ul>\n\n\n\n
            \n\n\n\n

            Explanation (Summary):<\/h3>\n\n\n\n

            These problems use kinematic equations<\/strong> that describe motion under constant acceleration. The equations ( v = u + at ), ( s = ut + \\frac{1}{2}at^2 ), and ( v^2 = u^2 + 2as ) are critical tools. For each problem:<\/p>\n\n\n\n

              \n
            • Identify the known values (initial velocity, time, etc.).<\/li>\n\n\n\n
            • Choose the appropriate equation based on the missing variable.<\/li>\n\n\n\n
            • Solve algebraically for the unknown.<\/li>\n<\/ul>\n\n\n\n

              Showing all work step-by-step ensures accurate results and highlights relationships between acceleration, velocity, and displacement. These equations are foundational for analyzing real-world scenarios involving motion.<\/p>\n","protected":false},"excerpt":{"rendered":"

              Name: PHYSICS Unit 2c INMOTION Acceleration and Kinematic Equations gpb.org\/physics-motion Practice Problems Date: Work each of the following problems. SHOW ALL WORK. 1. A sports car accelerates from rest to 26.8 m\/s (roughly 60 mi\/h) in 5.1 seconds. What is the acceleration of the car? 2. A child goes down a slide, starting from rest. […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-183750","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/183750","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=183750"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/183750\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=183750"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=183750"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=183750"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}