{"id":183844,"date":"2025-01-17T07:02:09","date_gmt":"2025-01-17T07:02:09","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=183844"},"modified":"2025-01-17T07:02:11","modified_gmt":"2025-01-17T07:02:11","slug":"literature-ir-spectrum-of-salicylic-acid-copy-image-of-the-ir-kbr-disc-from-sdbs-and-attach","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/17\/literature-ir-spectrum-of-salicylic-acid-copy-image-of-the-ir-kbr-disc-from-sdbs-and-attach\/","title":{"rendered":"Literature IR spectrum of salicylic acid &#8211; copy image of the IR (KBr disc) from SDBS and attach"},"content":{"rendered":"\n<p>Literature IR spectrum of salicylic acid &#8211; copy image of the IR (KBr disc) from SDBS and attach here &#8211; (For all IR spectra: labelling of diagnostic peaks, written structure, and figure title explaining conditions of IR (i.e. KBr) and for what compound.)<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/01\/image-305.png\" alt=\"\" class=\"wp-image-183845\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To create the requested response with the required IR spectrum, labeled peaks, structure, and detailed explanation, I will outline the necessary components. Since I cannot directly extract the spectrum from the provided link, I will instead generate a description and provide relevant context to meet the requirements.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">IR Spectrum of Salicylic Acid (KBr disc)<\/h3>\n\n\n\n<p><strong>Figure Title:<\/strong> IR Spectrum of Salicylic Acid Using a KBr Disc, Highlighting Diagnostic Peaks<\/p>\n\n\n\n<p><strong>Written Structure:<\/strong> Salicylic acid (C\u2087H\u2086O\u2083) consists of a benzene ring with two functional groups: a hydroxyl (-OH) group and a carboxylic acid (-COOH) group in the ortho position.<\/p>\n\n\n\n<p><strong>Key Diagnostic Peaks in the IR Spectrum:<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>O-H Stretching (Carboxylic Acid):<\/strong> Broad absorption band around <strong>2500-3300 cm\u207b\u00b9<\/strong> due to hydrogen-bonded O-H stretching.<\/li>\n\n\n\n<li><strong>O-H Stretching (Phenolic):<\/strong> Sharp peak near <strong>3200-3600 cm\u207b\u00b9<\/strong> due to the phenolic hydroxyl group.<\/li>\n\n\n\n<li><strong>C=O Stretching:<\/strong> Strong absorption near <strong>1700 cm\u207b\u00b9<\/strong> attributed to the carboxylic acid group.<\/li>\n\n\n\n<li><strong>C=C Stretching (Aromatic Ring):<\/strong> Peaks in the region of <strong>1500-1600 cm\u207b\u00b9<\/strong> due to aromatic ring vibrations.<\/li>\n\n\n\n<li><strong>C-O Stretching:<\/strong> Medium intensity peaks around <strong>1200-1300 cm\u207b\u00b9<\/strong> due to the C-O bond in both the carboxylic and phenolic groups.<\/li>\n\n\n\n<li><strong>Out-of-Plane C-H Bending:<\/strong> Peaks near <strong>750-800 cm\u207b\u00b9<\/strong> characteristic of an ortho-substituted benzene ring.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>Infrared (IR) spectroscopy identifies functional groups by their vibrational modes. In salicylic acid:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>broad O-H stretching<\/strong> bands reflect hydrogen bonding in the carboxylic acid and phenolic groups.<\/li>\n\n\n\n<li>The <strong>sharp C=O stretch<\/strong> indicates the carbonyl group&#8217;s strong dipole moment.<\/li>\n\n\n\n<li><strong>Aromatic C=C stretching<\/strong> vibrations confirm the presence of a benzene ring.<\/li>\n\n\n\n<li><strong>C-O stretching<\/strong> and bending vibrations reflect contributions from hydroxyl and carboxylic functionalities.<\/li>\n<\/ul>\n\n\n\n<p>The KBr disc method involves dispersing a fine powder of the sample in potassium bromide and pressing it into a pellet. This ensures minimal interference and provides clear spectral readings.<\/p>\n\n\n\n<p>By analyzing these peaks, the IR spectrum confirms the compound&#8217;s functional groups and overall structure.<\/p>\n\n\n\n<p>Let me know if you&#8217;d like an illustrated version of this explanation or further clarification!<\/p>\n\n\n\n<p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Literature IR spectrum of salicylic acid &#8211; copy image of the IR (KBr disc) from SDBS and attach here &#8211; (For all IR spectra: labelling of diagnostic peaks, written structure, and figure title explaining conditions of IR (i.e. KBr) and for what compound.) The Correct Answer and Explanation is : To create the requested response [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-183844","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/183844","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=183844"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/183844\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=183844"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=183844"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=183844"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}