{"id":184392,"date":"2025-01-20T20:08:25","date_gmt":"2025-01-20T20:08:25","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=184392"},"modified":"2025-01-20T20:08:27","modified_gmt":"2025-01-20T20:08:27","slug":"carbonic-acid-h%e2%82%82co%e2%82%83-is-diprotic-acid","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/20\/carbonic-acid-h%e2%82%82co%e2%82%83-is-diprotic-acid\/","title":{"rendered":"Carbonic acid (H\u2082CO\u2083) is diprotic acid"},"content":{"rendered":"\n

Carbonic acid (H\u2082CO\u2083) is diprotic acid. Draw the Lewis dot structure of carbonic acid and tell whether it is polar or not. (place the polarity here) If a 36.4 g piece of Iron (III) carbonate (Molar Mass = 291.72 g\/mole) is dropped into a large excess of hydrochloric acid how many liters of carbon dioxide (at STP) are produced. Enter your answer with two decimal places.<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Solution:<\/h3>\n\n\n\n

1. Lewis Dot Structure of Carbonic Acid (H\u2082CO\u2083)<\/strong><\/h4>\n\n\n\n

Carbonic acid is composed of one carbon atom, two oxygen atoms (double-bonded to carbon), one oxygen atom (single-bonded to carbon), and two hydrogen atoms bonded to the singly-bonded oxygen. The Lewis structure shows:<\/p>\n\n\n\n

    \n
  • Carbon (C) is the central atom.<\/li>\n\n\n\n
  • One oxygen is doubly bonded to carbon.<\/li>\n\n\n\n
  • One oxygen is singly bonded to carbon and also bonded to a hydrogen atom.<\/li>\n\n\n\n
  • The third oxygen is singly bonded to carbon and also bonded to the other hydrogen atom.<\/li>\n<\/ul>\n\n\n\n

    Polarity:<\/strong>
    Carbonic acid is polar<\/strong> because it has polar bonds (C=O and O-H bonds) and an asymmetrical shape, causing a net dipole moment.<\/p>\n\n\n\n

    \n\n\n\n

    2. Calculating CO\u2082 Produced<\/strong><\/h4>\n\n\n\n

    Step 1: Write the reaction.<\/strong>
    The reaction between Iron (III) carbonate (Fe\u2082(CO\u2083)\u2083) and hydrochloric acid (HCl) produces iron (III) chloride, water, and carbon dioxide:<\/p>\n\n\n\n

    [
    Fe_2(CO_3)_3 + 6HCl \\rightarrow 2FeCl_3 + 3CO_2 + 3H_2O
    ]<\/p>\n\n\n\n

    Step 2: Moles of Fe\u2082(CO\u2083)\u2083.<\/strong>
    [
    \\text{Moles of } Fe_2(CO_3)_3 = \\frac{\\text{Mass}}{\\text{Molar Mass}} = \\frac{36.4 \\, \\text{g}}{291.72 \\, \\text{g\/mol}} = 0.1247 \\, \\text{mol}
    ]<\/p>\n\n\n\n

    Step 3: Moles of CO\u2082 produced.<\/strong>
    From the reaction, 1 mole of Fe\u2082(CO\u2083)\u2083 produces 3 moles of CO\u2082:
    [
    \\text{Moles of CO}_2 = 0.1247 \\, \\text{mol} \\times 3 = 0.3741 \\, \\text{mol}
    ]<\/p>\n\n\n\n

    Step 4: Volume of CO\u2082 at STP.<\/strong>
    At STP, 1 mole of any gas occupies 22.4 L. Thus:
    [
    \\text{Volume of CO}_2 = 0.3741 \\, \\text{mol} \\times 22.4 \\, \\text{L\/mol} = 8.38 \\, \\text{L}
    ]<\/p>\n\n\n\n

    \n\n\n\n

    Answer:<\/strong><\/h3>\n\n\n\n
      \n
    • Polarity:<\/strong> Polar<\/li>\n\n\n\n
    • Volume of CO\u2082:<\/strong> 8.38 L<\/strong><\/li>\n<\/ul>\n\n\n\n
      \n\n\n\n

      Explanation:<\/strong><\/h3>\n\n\n\n

      Carbonic acid is a diprotic acid that can donate two protons due to the presence of two -OH groups. The asymmetry in its structure makes it polar. In the reaction, Fe\u2082(CO\u2083)\u2083 reacts with HCl, releasing CO\u2082 as a gas. The stoichiometric calculation considers the molar ratio and the gas law at STP, providing the volume with high accuracy.<\/p>\n","protected":false},"excerpt":{"rendered":"

      Carbonic acid (H\u2082CO\u2083) is diprotic acid. Draw the Lewis dot structure of carbonic acid and tell whether it is polar or not. (place the polarity here) If a 36.4 g piece of Iron (III) carbonate (Molar Mass = 291.72 g\/mole) is dropped into a large excess of hydrochloric acid how many liters of carbon dioxide […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-184392","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184392","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=184392"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184392\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=184392"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=184392"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=184392"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}