{"id":184422,"date":"2025-01-20T20:36:12","date_gmt":"2025-01-20T20:36:12","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=184422"},"modified":"2025-01-20T20:36:14","modified_gmt":"2025-01-20T20:36:14","slug":"describe-the-molecular-geometry-of-the-central-atoms","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/20\/describe-the-molecular-geometry-of-the-central-atoms\/","title":{"rendered":"Describe the molecular geometry of the central atoms"},"content":{"rendered":"\n

Describe the molecular geometry of the central atoms in; a) CH3COOH b) CH3CHCH2 c) CH3CCCH2OH<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Here\u2019s the molecular geometry of the central atoms in the given molecules:<\/p>\n\n\n\n

a) CH\u2083COOH (Acetic acid)<\/strong><\/h3>\n\n\n\n
    \n
  1. CH\u2083 group<\/strong>: The central atom (C) in CH\u2083 is tetrahedral<\/strong> due to four sigma bonds (three C-H bonds and one C-C bond).<\/li>\n\n\n\n
  2. COOH group<\/strong>: The central atom (C) in the carboxylic acid group is trigonal planar<\/strong> because it is sp\u00b2 hybridized (one C=O double bond and two sigma bonds to the hydroxyl group and CH\u2083 group).<\/li>\n<\/ol>\n\n\n\n

    b) CH\u2083CH=CH\u2082 (Propene)<\/strong><\/h3>\n\n\n\n
      \n
    1. CH\u2083 group<\/strong>: The central atom (C) in CH\u2083 is tetrahedral<\/strong> for the same reason as in acetic acid: it has four sigma bonds.<\/li>\n\n\n\n
    2. CH group<\/strong>: The second carbon (in CH=CH\u2082) is trigonal planar<\/strong> due to sp\u00b2 hybridization (one C=C bond and two sigma bonds to the CH\u2083 group and one hydrogen).<\/li>\n\n\n\n
    3. CH\u2082 group<\/strong>: The last carbon in CH\u2082 is also trigonal planar<\/strong> because it is sp\u00b2 hybridized with one C=C bond and two sigma bonds to hydrogen atoms.<\/li>\n<\/ol>\n\n\n\n

      c) CH\u2083C\u2261CCH\u2082OH (Butyne-1-ol)<\/strong><\/h3>\n\n\n\n
        \n
      1. CH\u2083 group<\/strong>: As before, the CH\u2083 carbon is tetrahedral<\/strong>.<\/li>\n\n\n\n
      2. C\u2261C group<\/strong>: The central carbon in the triple bond is linear<\/strong> due to sp hybridization (two sigma bonds and two \u03c0 bonds).<\/li>\n\n\n\n
      3. CH\u2082 group<\/strong>: The carbon in CH\u2082 is tetrahedral<\/strong> (sp\u00b3 hybridized, with three sigma bonds to H atoms and one sigma bond to the OH group).<\/li>\n<\/ol>\n\n\n\n

        Explanation:<\/h3>\n\n\n\n

        The molecular geometry is determined by the hybridization of the central atoms. Hybridization arises from the number of sigma bonds and lone pairs on a central atom. For instance:<\/p>\n\n\n\n

          \n
        • Tetrahedral<\/strong> geometry (sp\u00b3 hybridized) occurs when the atom forms four sigma bonds.<\/li>\n\n\n\n
        • Trigonal planar<\/strong> geometry (sp\u00b2 hybridized) results from three sigma bonds.<\/li>\n\n\n\n
        • Linear<\/strong> geometry (sp hybridized) arises when there are two sigma bonds.<\/li>\n<\/ul>\n\n\n\n

          These geometries are derived from VSEPR theory, which minimizes electron-pair repulsion around the central atom. Each geometry optimizes the spatial arrangement for stability.<\/p>\n","protected":false},"excerpt":{"rendered":"

          Describe the molecular geometry of the central atoms in; a) CH3COOH b) CH3CHCH2 c) CH3CCCH2OH The Correct Answer and Explanation is : Here\u2019s the molecular geometry of the central atoms in the given molecules: a) CH\u2083COOH (Acetic acid) b) CH\u2083CH=CH\u2082 (Propene) c) CH\u2083C\u2261CCH\u2082OH (Butyne-1-ol) Explanation: The molecular geometry is determined by the hybridization of the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-184422","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184422","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=184422"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184422\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=184422"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=184422"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=184422"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}