{"id":184429,"date":"2025-01-21T04:27:27","date_gmt":"2025-01-21T04:27:27","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=184429"},"modified":"2025-01-21T04:27:30","modified_gmt":"2025-01-21T04:27:30","slug":"what-is-hybridization-and-number-of-lone-electron-pairs-on-the-tellurium-atom-in-the-molecule","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/21\/what-is-hybridization-and-number-of-lone-electron-pairs-on-the-tellurium-atom-in-the-molecule\/","title":{"rendered":"What is hybridization and number of lone electron pairs on the tellurium atom in the molecule"},"content":{"rendered":"\n

What is hybridization and number of lone electron pairs on the tellurium atom in the molecule, TeCl4?<\/p>\n\n\n\n

A sp\u00bad, 2 lone pairs of e-<\/p>\n\n\n\n

B. sp3, 1 lone pair of e-<\/p>\n\n\n\n

c. spd, 2 lone pairs of e-<\/p>\n\n\n\n

D. sp\u00bad, I lone pair of e-<\/p>\n\n\n\n

E. Sp\u00ba, O lone pair of e-<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

The correct answer is: B. sp\u00b3, 1 lone pair of e\u207b<\/strong><\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

1. Determining the Hybridization of Tellurium in TeCl\u2084<\/strong><\/h4>\n\n\n\n

Tellurium (Te) is the central atom in the TeCl\u2084 molecule. To determine its hybridization, follow these steps:<\/p>\n\n\n\n

    \n
  1. Count the valence electrons of tellurium<\/strong>:
    Tellurium belongs to Group 16, so it has 6 valence electrons<\/strong>.<\/li>\n\n\n\n
  2. Add the contributions from chlorine atoms<\/strong>:
    Each chlorine atom contributes 1 electron through bonding, and there are 4 chlorine atoms.
    Total electrons from chlorine = ( 4 \\times 1 = 4 ).<\/li>\n\n\n\n
  3. Find the total electron pairs around tellurium<\/strong>:
    Total electrons = ( 6 \\text{ (Te’s valence electrons)} + 4 \\text{ (from Cl)} = 10 ).
    Divide by 2 to find electron pairs:
    ( \\frac{10}{2} = 5 \\text{ electron pairs} ).<\/li>\n\n\n\n
  4. Assign the pairs as bonding and lone pairs<\/strong>:
    Four pairs are used for bonding with the four chlorine atoms.
    One pair remains as a lone pair<\/strong> on tellurium.<\/li>\n\n\n\n
  5. Hybridization determination<\/strong>:
    The number of electron pairs (5) corresponds to sp\u00b3d hybridization<\/strong>, which usually forms a seesaw molecular geometry<\/strong>.<\/li>\n<\/ol>\n\n\n\n
    \n\n\n\n

    2. Lone Electron Pairs on Tellurium<\/strong><\/h4>\n\n\n\n

    As determined earlier, tellurium has one lone pair<\/strong> in the TeCl\u2084 molecule.<\/p>\n\n\n\n

    \n\n\n\n

    3. Molecular Geometry and Shape<\/strong><\/h4>\n\n\n\n

    The molecular geometry is seesaw<\/strong>, derived from the trigonal bipyramidal electron geometry. The lone pair occupies an equatorial position to minimize repulsion.<\/p>\n\n\n\n

    \n\n\n\n

    Summary<\/h3>\n\n\n\n
      \n
    • Hybridization<\/strong>: sp\u00b3d<\/li>\n\n\n\n
    • Lone pairs<\/strong>: 1<\/li>\n\n\n\n
    • Molecular geometry<\/strong>: Seesaw<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"

      What is hybridization and number of lone electron pairs on the tellurium atom in the molecule, TeCl4? A sp\u00bad, 2 lone pairs of e- B. sp3, 1 lone pair of e- c. spd, 2 lone pairs of e- D. sp\u00bad, I lone pair of e- E. Sp\u00ba, O lone pair of e- The Correct Answer […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-184429","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184429","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=184429"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184429\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=184429"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=184429"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=184429"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}