{"id":184509,"date":"2025-01-21T06:17:02","date_gmt":"2025-01-21T06:17:02","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=184509"},"modified":"2025-01-21T06:17:04","modified_gmt":"2025-01-21T06:17:04","slug":"draw-bfcl-2-assume-the-molecule-is-planar-and-with-suitable-diagrams-show-all-the-symmetry-elements-possessed-by-this-molecule","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/21\/draw-bfcl-2-assume-the-molecule-is-planar-and-with-suitable-diagrams-show-all-the-symmetry-elements-possessed-by-this-molecule\/","title":{"rendered":"Draw BFCl 2 (assume the molecule is planar) and with suitable diagrams show ALL the symmetry elements possessed by this molecule"},"content":{"rendered":"\n<p>Draw BFCl 2 (assume the molecule is planar) and with suitable diagrams show ALL the symmetry elements possessed by this molecule. Identify the point group of this molecule. 2. If BFCl 2 is non-planar instead of planar, identify all of the symmetry elements possessed by this molecule and identify its point group.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To address this, I will explain the symmetry elements, point group identification, and the implications of BFCl\u2082 being planar or non-planar. Here&#8217;s the detailed analysis:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. BFCl\u2082 (Planar):<\/strong><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Structure:<\/strong><\/h4>\n\n\n\n<p>BFCl\u2082 is planar, with boron at the center and three substituents (F, Cl, Cl) forming a trigonal planar geometry.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Symmetry Elements:<\/strong><\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>E (Identity):<\/strong> Every molecule has this symmetry element.<\/li>\n\n\n\n<li><strong>C\u2083 (Principal Axis of Rotation):<\/strong> A 120\u00b0 rotation around the axis passing through boron and perpendicular to the plane leaves the molecule unchanged.<\/li>\n\n\n\n<li><strong>\u03c3_v (Vertical Planes):<\/strong> Three vertical planes pass through B and each B\u2013X bond (F or Cl). These planes include the principal axis.<\/li>\n\n\n\n<li><strong>\u03c3_h (Horizontal Plane):<\/strong> The plane of the molecule itself is a horizontal plane of symmetry.<\/li>\n\n\n\n<li><strong>S\u2083 (Improper Axis):<\/strong> A 120\u00b0 rotation around the C\u2083 axis, followed by a reflection in \u03c3_h, also leaves the molecule unchanged.<\/li>\n<\/ol>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Point Group:<\/strong><\/h4>\n\n\n\n<p>The planar BFCl\u2082 belongs to the <strong>D3hD_{3h}<\/strong> point group due to the presence of C\u2083, \u03c3_v, \u03c3_h, and S\u2083.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. BFCl\u2082 (Non-Planar):<\/strong><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Structure:<\/strong><\/h4>\n\n\n\n<p>If BFCl\u2082 is non-planar, boron is at the center with the substituents (F, Cl, Cl) arranged in a trigonal pyramidal geometry, breaking the planar symmetry.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Symmetry Elements:<\/strong><\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>E (Identity):<\/strong> Present as always.<\/li>\n\n\n\n<li><strong>C\u2083 (Principal Axis of Rotation):<\/strong> A 120\u00b0 rotation around the axis passing through boron and perpendicular to the base remains valid.<\/li>\n\n\n\n<li><strong>\u03c3_v (Vertical Planes):<\/strong> Only one vertical plane exists due to the asymmetry introduced by non-planarity.<\/li>\n<\/ol>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Point Group:<\/strong><\/h4>\n\n\n\n<p>The non-planar BFCl\u2082 belongs to the <strong>C3vC_{3v}<\/strong> point group, characterized by a C\u2083 axis and three \u03c3_v planes.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Planar BFCl\u2082 has more symmetry, belonging to D3hD_{3h}.<\/li>\n\n\n\n<li>Non-planar BFCl\u2082 has reduced symmetry, belonging to C3vC_{3v}.<\/li>\n<\/ul>\n\n\n\n<p>This change in geometry significantly reduces the number of symmetry elements, which alters the point group classification.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw BFCl 2 (assume the molecule is planar) and with suitable diagrams show ALL the symmetry elements possessed by this molecule. Identify the point group of this molecule. 2. If BFCl 2 is non-planar instead of planar, identify all of the symmetry elements possessed by this molecule and identify its point group. The Correct Answer [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-184509","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184509","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=184509"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184509\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=184509"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=184509"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=184509"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}