{"id":184734,"date":"2025-01-21T10:50:03","date_gmt":"2025-01-21T10:50:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=184734"},"modified":"2025-01-21T10:51:07","modified_gmt":"2025-01-21T10:51:07","slug":"total-polarity-bond-angles-molecular-shape-molecule-valence-lewis-structure-electrons-polar-non-polar-nhy-al-bond","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/21\/total-polarity-bond-angles-molecular-shape-molecule-valence-lewis-structure-electrons-polar-non-polar-nhy-al-bond\/","title":{"rendered":"Examine The Models You Have Built For The Three Substances In The Reaction Below"},"content":{"rendered":"\n

Total Polarity Bond Angles Molecular Shape Molecule Valence Lewis Structure Electrons Polar Non-Polar NHy Al Bond Angle Molecular Shape Triang Polar Non-Polar BH3 Bond Angle Molecular Shape 13 NH,BH3 I-F Question #3 Examine The Models You Have Built For The Three Substances In The Reaction Below Based Upon Your Models, Which Atom Do The Electrons Come From<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

To accurately address your question, let’s analyze the components based on the molecular models and concepts:<\/p>\n\n\n\n

    \n
  1. Ammonia ((NH_3))<\/strong>:<\/li>\n<\/ol>\n\n\n\n
      \n
    • Bond Angle<\/strong>: Approximately (107^\\circ), slightly less than the (109.5^\\circ) of a perfect tetrahedral due to lone pair repulsion.<\/li>\n\n\n\n
    • Molecular Shape<\/strong>: Trigonal pyramidal.<\/li>\n\n\n\n
    • Polarity<\/strong>: Polar due to its lone pair and the electronegativity of nitrogen.<\/li>\n<\/ul>\n\n\n\n
        \n
      1. Boron Trifluoride ((BH_3))<\/strong>:<\/li>\n<\/ol>\n\n\n\n
          \n
        • Bond Angle<\/strong>: (120^\\circ), characteristic of a trigonal planar structure.<\/li>\n\n\n\n
        • Molecular Shape<\/strong>: Trigonal planar.<\/li>\n\n\n\n
        • Polarity<\/strong>: Non-polar because the molecule is symmetric, and the dipoles cancel out.<\/li>\n<\/ul>\n\n\n\n
            \n
          1. Interaction in Reaction ((NH_3) and (BH_3))<\/strong>:
            The reaction involves (NH_3) (electron donor) and (BH_3) (electron acceptor). (BH_3) lacks a full octet (boron has only six valence electrons), making it an electrophile. (NH_3) has a lone pair on nitrogen, which can be donated to (BH_3). The product is a coordinate covalent bond between the nitrogen of (NH_3) and the boron of (BH_3), forming a (NH_3BH_3) adduct.<\/li>\n\n\n\n
          2. Source of Electrons<\/strong>:<\/li>\n<\/ol>\n\n\n\n
              \n
            • The electrons come from the lone pair on the nitrogen atom in (NH_3).<\/li>\n\n\n\n
            • Boron in (BH_3) does not have lone pairs to share; it accepts electrons to complete its octet.<\/li>\n<\/ul>\n\n\n\n
              \n\n\n\n

              Explanation (300 words):<\/h3>\n\n\n\n

              The reaction between ammonia ((NH_3)) and boron trifluoride ((BH_3)) showcases the principles of molecular geometry, polarity, and electron pair donation. (NH_3) has a trigonal pyramidal shape due to its lone pair of electrons, which repel the bonding pairs, resulting in a bond angle of (107^\\circ). Being polar, (NH_3) can interact strongly with other molecules.<\/p>\n\n\n\n

              In contrast, (BH_3) has a trigonal planar shape and a bond angle of (120^\\circ). (BH_3) is non-polar, but boron is electron-deficient, as it does not complete an octet. This makes (BH_3) a strong Lewis acid (electron pair acceptor).<\/p>\n\n\n\n

              During the reaction, the nitrogen in (NH_3) donates its lone pair of electrons to the electron-deficient boron atom in (BH_3). This forms a coordinate covalent bond, resulting in the adduct (NH_3BH_3). The boron atom accepts the lone pair to achieve an octet configuration, while nitrogen retains its original valence configuration.<\/p>\n\n\n\n

              In conclusion, the electrons in this reaction come from the lone pair of nitrogen in (NH_3), highlighting nitrogen’s role as a Lewis base. This interaction is fundamental to understanding acid-base chemistry and molecular interactions in reactions involving electron pair transfer.<\/p>\n","protected":false},"excerpt":{"rendered":"

              Total Polarity Bond Angles Molecular Shape Molecule Valence Lewis Structure Electrons Polar Non-Polar NHy Al Bond Angle Molecular Shape Triang Polar Non-Polar BH3 Bond Angle Molecular Shape 13 NH,BH3 I-F Question #3 Examine The Models You Have Built For The Three Substances In The Reaction Below Based Upon Your Models, Which Atom Do The Electrons […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-184734","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184734","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=184734"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184734\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=184734"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=184734"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=184734"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}