{"id":184755,"date":"2025-01-21T15:03:29","date_gmt":"2025-01-21T15:03:29","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=184755"},"modified":"2025-01-21T15:03:30","modified_gmt":"2025-01-21T15:03:30","slug":"the-density-of-2-methyl-2-butanol-is-0-806-g-ml","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/21\/the-density-of-2-methyl-2-butanol-is-0-806-g-ml\/","title":{"rendered":"The density of 2-methyl-2-butanol is 0.806 g\/mL"},"content":{"rendered":"\n

The density of 2-methyl-2-butanol is 0.806 g\/mL.. How many mgs represent an aliquot of 430 \u00b5L.? How many mmols represent an aliquot of 0.650 mL. (2-methyl-2-butanol, formula weight is 88.15 g\/mol)?<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

To solve this, we need to compute the mass and the number of millimoles of 2-methyl-2-butanol for the given volumes and conditions. Here’s the breakdown:<\/p>\n\n\n\n

\n\n\n\n

1. Mass of 430 \u00b5L aliquot in mg:<\/strong><\/h3>\n\n\n\n
    \n
  1. Convert \u00b5L to mL:<\/strong>
    430\u2009\u03bcL=430\u00d710\u22123\u2009mL=0.430\u2009mL430 \\, \\mu\\text{L} = 430 \\times 10^{-3} \\, \\text{mL} = 0.430 \\, \\text{mL}<\/li>\n\n\n\n
  2. Calculate the mass (g):<\/strong>
    Using the formula: Mass\u00a0(g)=Density\u00a0(g\/mL)\u00d7Volume\u00a0(mL)\\text{Mass (g)} = \\text{Density (g\/mL)} \\times \\text{Volume (mL)} Mass=0.806\u2009g\/mL\u00d70.430\u2009mL=0.34658\u2009g\\text{Mass} = 0.806 \\, \\text{g\/mL} \\times 0.430 \\, \\text{mL} = 0.34658 \\, \\text{g}<\/li>\n\n\n\n
  3. Convert to mg:<\/strong>
    0.34658\u2009g\u00d71000=346.58\u2009mg0.34658 \\, \\text{g} \\times 1000 = 346.58 \\, \\text{mg} Mass = 346.58 mg<\/strong><\/li>\n<\/ol>\n\n\n\n
    \n\n\n\n

    2. Millimoles in 0.650 mL aliquot:<\/strong><\/h3>\n\n\n\n
      \n
    1. Calculate the mass (g):<\/strong> Mass\u00a0(g)=0.806\u2009g\/mL\u00d70.650\u2009mL=0.5239\u2009g\\text{Mass (g)} = 0.806 \\, \\text{g\/mL} \\times 0.650 \\, \\text{mL} = 0.5239 \\, \\text{g}<\/li>\n\n\n\n
    2. Convert mass to moles:<\/strong>
      Using the molar mass of 2-methyl-2-butanol (88.15\u2009g\/mol88.15 \\, \\text{g\/mol}): Moles=Mass\u00a0(g)Molar\u00a0mass\u00a0(g\/mol)\\text{Moles} = \\frac{\\text{Mass (g)}}{\\text{Molar mass (g\/mol)}} Moles=0.523988.15=0.005945\u2009mol\\text{Moles} = \\frac{0.5239}{88.15} = 0.005945 \\, \\text{mol}<\/li>\n\n\n\n
    3. Convert to millimoles (mmol):<\/strong>
      0.005945\u2009mol\u00d71000=5.945\u2009mmol0.005945 \\, \\text{mol} \\times 1000 = 5.945 \\, \\text{mmol} Millimoles = 5.945 mmol<\/strong><\/li>\n<\/ol>\n\n\n\n
      \n\n\n\n

      Explanation:<\/strong><\/h3>\n\n\n\n
        \n
      • Mass Calculation:<\/strong> To calculate the mass from a given volume, multiply the volume by the substance’s density. Density links mass and volume, and converting units (\u00b5L to mL, g to mg) ensures consistency.<\/li>\n\n\n\n
      • Millimoles Calculation:<\/strong> To find millimoles, calculate the mass of the aliquot first using its density and volume. Then divide the mass by the molar mass of the compound to determine the moles, which can be converted to millimoles.<\/li>\n<\/ul>\n\n\n\n

        These calculations are crucial in chemistry for preparing solutions, performing stoichiometric calculations, and understanding the substance’s physical and chemical properties.<\/p>\n","protected":false},"excerpt":{"rendered":"

        The density of 2-methyl-2-butanol is 0.806 g\/mL.. How many mgs represent an aliquot of 430 \u00b5L.? How many mmols represent an aliquot of 0.650 mL. (2-methyl-2-butanol, formula weight is 88.15 g\/mol)? The Correct Answer and Explanation is : To solve this, we need to compute the mass and the number of millimoles of 2-methyl-2-butanol for […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-184755","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184755","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=184755"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/184755\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=184755"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=184755"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=184755"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}