{"id":185042,"date":"2025-01-22T04:52:31","date_gmt":"2025-01-22T04:52:31","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=185042"},"modified":"2025-01-22T04:52:34","modified_gmt":"2025-01-22T04:52:34","slug":"give-the-raceway-size-required-for-each-of-the-following-conductor-combinations","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/22\/give-the-raceway-size-required-for-each-of-the-following-conductor-combinations\/","title":{"rendered":"Give the raceway size required for each of the following conductor combinations"},"content":{"rendered":"\n<p>Give the raceway size required for each of the following conductor combinations:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Five, 10 AWG, Type THW in Schedule 80 PVC <strong><em><strong><em>___<\/em><\/strong><\/em><\/strong><\/li>\n\n\n\n<li>Three, 1\/0 AWG, Type THHN in EMT <strong><em><strong><em>___<\/em><\/strong><\/em><\/strong><\/li>\n\n\n\n<li>Three, 1\/0 AWG and one, 1 AWG, Type THW in EMT_______________<\/li>\n<\/ol>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To determine the correct raceway size for the given conductor combinations, we refer to <strong>NEC Chapter 9, Table 5<\/strong> for conductor dimensions and <strong>Chapter 9, Table 4<\/strong> for raceway fill limits. Here are the answers along with an explanation of the calculations:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>Five, 10 AWG, Type THW in Schedule 80 PVC<\/strong><\/h3>\n\n\n\n<p><strong>Answer<\/strong>: <strong>1\/2 inch Schedule 80 PVC<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>From <strong>NEC Chapter 9, Table 5<\/strong>, the cross-sectional area of a single 10 AWG THW conductor is <strong>0.0211 in\u00b2<\/strong>.<\/li>\n\n\n\n<li>Total conductor area = ( 5 \\times 0.0211 \\, \\text{in}\u00b2 = 0.1055 \\, \\text{in}\u00b2 ).<\/li>\n\n\n\n<li>For Schedule 80 PVC, the maximum fill is 40% for more than 2 conductors.<\/li>\n\n\n\n<li>From <strong>NEC Chapter 9, Table 4<\/strong>, a 1\/2-inch Schedule 80 PVC conduit has a total area of <strong>0.122 in\u00b2<\/strong> with a 40% allowable fill of <strong>0.0488 in\u00b2<\/strong>.<\/li>\n\n\n\n<li>The calculated conductor area exceeds the 40% fill of a 1\/2-inch Schedule 80 PVC. Thus, a <strong>3\/4-inch Schedule 80 PVC<\/strong> conduit is required, with a 40% fill of <strong>0.164 in\u00b2<\/strong>, which accommodates the conductors.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>Three, 1\/0 AWG, Type THHN in EMT<\/strong><\/h3>\n\n\n\n<p><strong>Answer<\/strong>: <strong>1-inch EMT<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>From <strong>Table 5<\/strong>, the area of one 1\/0 AWG THHN conductor is <strong>0.0837 in\u00b2<\/strong>.<\/li>\n\n\n\n<li>Total conductor area = ( 3 \\times 0.0837 \\, \\text{in}\u00b2 = 0.2511 \\, \\text{in}\u00b2 ).<\/li>\n\n\n\n<li>For EMT conduits with more than two conductors, the allowable fill is 40%.<\/li>\n\n\n\n<li>From <strong>Table 4<\/strong>, a 1-inch EMT has a total area of <strong>0.346 in\u00b2<\/strong> and a 40% allowable fill of <strong>0.1384 in\u00b2<\/strong>.<\/li>\n\n\n\n<li>A <strong>1-1\/4-inch EMT<\/strong> conduit, with a 40% allowable fill of <strong>0.581 in\u00b2<\/strong>, is required to fit the total conductor area.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>Three, 1\/0 AWG and one, 1 AWG, Type THW in EMT<\/strong><\/h3>\n\n\n\n<p><strong>Answer<\/strong>: <strong>1-1\/4-inch EMT<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>From <strong>Table 5<\/strong>, the area of one 1\/0 AWG THW conductor is <strong>0.1333 in\u00b2<\/strong>, and one 1 AWG THW conductor is <strong>0.1158 in\u00b2<\/strong>.<\/li>\n\n\n\n<li>Total conductor area = ( 3 \\times 0.1333 + 0.1158 = 0.5157 \\, \\text{in}\u00b2 ).<\/li>\n\n\n\n<li>From <strong>Table 4<\/strong>, a 1-1\/4-inch EMT has a total area of <strong>0.785 in\u00b2<\/strong> with a 40% allowable fill of <strong>0.314 in\u00b2<\/strong>.<\/li>\n\n\n\n<li>A <strong>1-1\/2-inch EMT<\/strong> conduit, with a 40% allowable fill of <strong>0.514 in\u00b2<\/strong>, accommodates the calculated conductor area.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>The National Electrical Code (NEC) provides specific guidelines for raceway fill to prevent overheating and allow easy wire pulling. The fill percentage depends on the number of conductors:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>53% fill<\/strong> for one conductor.<\/li>\n\n\n\n<li><strong>31% fill<\/strong> for two conductors.<\/li>\n\n\n\n<li><strong>40% fill<\/strong> for three or more conductors.<\/li>\n<\/ul>\n\n\n\n<p>Correct sizing ensures compliance, safety, and functionality of the electrical system.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Give the raceway size required for each of the following conductor combinations: The Correct Answer and Explanation is : To determine the correct raceway size for the given conductor combinations, we refer to NEC Chapter 9, Table 5 for conductor dimensions and Chapter 9, Table 4 for raceway fill limits. Here are the answers along [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-185042","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185042","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=185042"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185042\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=185042"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=185042"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=185042"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}