{"id":185290,"date":"2025-01-22T10:17:51","date_gmt":"2025-01-22T10:17:51","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=185290"},"modified":"2025-01-22T10:17:53","modified_gmt":"2025-01-22T10:17:53","slug":"indicate-the-hybridization-and-bond-angles-associated-with-each-of-the-following-molecular-geometries","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/22\/indicate-the-hybridization-and-bond-angles-associated-with-each-of-the-following-molecular-geometries\/","title":{"rendered":"Indicate The Hybridization And Bond Angles Associated With Each Of The Following Molecular Geometries"},"content":{"rendered":"\n

Indicate The Hybridization And Bond Angles Associated With Each Of The Following Molecular Geometries Geometry Hybridization Bond Angles Linear Tetrahedral Trigonal Planar Trigonal Bipyramidal Octahedral<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Table of Molecular Geometries, Hybridization, and Bond Angles<\/strong><\/h3>\n\n\n\n
Geometry<\/strong><\/th>Hybridization<\/strong><\/th>Bond Angles<\/strong><\/th><\/tr><\/thead>
Linear<\/strong><\/td>sp<\/td>180\u00b0<\/td><\/tr>
Tetrahedral<\/strong><\/td>sp\u00b3<\/td>109.5\u00b0<\/td><\/tr>
Trigonal Planar<\/strong><\/td>sp\u00b2<\/td>120\u00b0<\/td><\/tr>
Trigonal Bipyramidal<\/strong><\/td>sp\u00b3d<\/td>90\u00b0 (axial), 120\u00b0 (equatorial)<\/td><\/tr>
Octahedral<\/strong><\/td>sp\u00b3d\u00b2<\/td>90\u00b0<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
\n\n\n\n

Explanation<\/strong><\/h3>\n\n\n\n
    \n
  1. Linear Geometry (sp hybridization):<\/strong><\/li>\n<\/ol>\n\n\n\n
      \n
    • In a linear geometry, the central atom forms two regions of electron density (e.g., bonds or lone pairs).<\/li>\n\n\n\n
    • The sp hybridization involves mixing one s orbital and one p orbital.<\/li>\n\n\n\n
    • The bond angles are 180\u00b0, ensuring minimal repulsion between the electron density regions (e.g., CO\u2082, BeCl\u2082).<\/li>\n<\/ul>\n\n\n\n
        \n
      1. Tetrahedral Geometry (sp\u00b3 hybridization):<\/strong><\/li>\n<\/ol>\n\n\n\n
          \n
        • The central atom has four regions of electron density arranged to minimize repulsion.<\/li>\n\n\n\n
        • sp\u00b3 hybridization involves one s orbital and three p orbitals.<\/li>\n\n\n\n
        • The bond angle is approximately 109.5\u00b0 (e.g., CH\u2084, NH\u2084\u207a).<\/li>\n<\/ul>\n\n\n\n
            \n
          1. Trigonal Planar Geometry (sp\u00b2 hybridization):<\/strong><\/li>\n<\/ol>\n\n\n\n
              \n
            • Three regions of electron density around the central atom form a flat, triangular structure.<\/li>\n\n\n\n
            • sp\u00b2 hybridization involves one s orbital and two p orbitals.<\/li>\n\n\n\n
            • The bond angle is 120\u00b0 (e.g., BF\u2083, CO\u2083\u00b2\u207b).<\/li>\n<\/ul>\n\n\n\n
                \n
              1. Trigonal Bipyramidal Geometry (sp\u00b3d hybridization):<\/strong><\/li>\n<\/ol>\n\n\n\n
                  \n
                • Five regions of electron density form this geometry, with three in an equatorial plane and two in axial positions.<\/li>\n\n\n\n
                • sp\u00b3d hybridization involves one s orbital, three p orbitals, and one d orbital.<\/li>\n\n\n\n
                • Bond angles are 120\u00b0 (equatorial) and 90\u00b0 (axial) (e.g., PCl\u2085).<\/li>\n<\/ul>\n\n\n\n
                    \n
                  1. Octahedral Geometry (sp\u00b3d\u00b2 hybridization):<\/strong><\/li>\n<\/ol>\n\n\n\n
                      \n
                    • Six regions of electron density form a symmetrical octahedron.<\/li>\n\n\n\n
                    • sp\u00b3d\u00b2 hybridization involves one s orbital, three p orbitals, and two d orbitals.<\/li>\n\n\n\n
                    • The bond angle is 90\u00b0 (e.g., SF\u2086, [Cr(NH\u2083)\u2086]\u00b3\u207a).<\/li>\n<\/ul>\n\n\n\n

                      This framework explains how molecular geometry arises from electron repulsions and orbital hybridization to minimize energy and maximize stability.<\/p>\n","protected":false},"excerpt":{"rendered":"

                      Indicate The Hybridization And Bond Angles Associated With Each Of The Following Molecular Geometries Geometry Hybridization Bond Angles Linear Tetrahedral Trigonal Planar Trigonal Bipyramidal Octahedral The Correct Answer and Explanation is : Table of Molecular Geometries, Hybridization, and Bond Angles Geometry Hybridization Bond Angles Linear sp 180\u00b0 Tetrahedral sp\u00b3 109.5\u00b0 Trigonal Planar sp\u00b2 120\u00b0 Trigonal […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-185290","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185290","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=185290"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185290\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=185290"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=185290"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=185290"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}