{"id":185393,"date":"2025-01-22T13:27:22","date_gmt":"2025-01-22T13:27:22","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=185393"},"modified":"2025-01-22T13:27:24","modified_gmt":"2025-01-22T13:27:24","slug":"enter-the-formula-of-the-conjugate-base-for-the-acid-hco3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/22\/enter-the-formula-of-the-conjugate-base-for-the-acid-hco3\/","title":{"rendered":"Enter the formula of the conjugate base for the acid HCO3"},"content":{"rendered":"\n<p>A.) Enter the formula of the conjugate base for the acid HCO3-. Express your answer as a chemical formula.<\/p>\n\n\n\n<p>B.) Enter the formula of the conjugate base for the acid CH3-NH3+. Express your answer as a chemical formula.<\/p>\n\n\n\n<p>C.) Enter the formula of the conjugate base for the acid HPO42-. Express your answer as a chemical formula.<\/p>\n\n\n\n<p>D.) Enter the formula of the conjugate base for the acid HNO2. Express your answer as a chemical formula.<\/p>\n\n\n\n<p>E.) Enter the formula of the conjugate base for the acid HBrO. Express your answer as a chemical formula.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Answers:<\/h3>\n\n\n\n<p><strong>A.<\/strong> ( \\text{CO}_3^{2-} )<br><strong>B.<\/strong> ( \\text{CH}_3\\text{-NH}_2 )<br><strong>C.<\/strong> ( \\text{PO}_4^{3-} )<br><strong>D.<\/strong> ( \\text{NO}_2^- )<br><strong>E.<\/strong> ( \\text{BrO}^- )<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>A conjugate base forms when an acid donates a proton (( \\text{H}^+ )) during a chemical reaction. The conjugate base has one fewer proton and a corresponding change in charge compared to the acid.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>A.) Conjugate base of ( \\text{HCO}_3^- ):<\/strong><br>The bicarbonate ion (( \\text{HCO}_3^- )) can lose one proton to become ( \\text{CO}_3^{2-} ) (carbonate ion). The reaction is:<br>[ \\text{HCO}_3^- \\rightarrow \\text{CO}_3^{2-} + \\text{H}^+ ]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>B.) Conjugate base of ( \\text{CH}_3\\text{-NH}_3^+ ):<\/strong><br>The methylammonium ion (( \\text{CH}_3\\text{-NH}_3^+ )) loses a proton to form ( \\text{CH}_3\\text{-NH}_2 ) (methylamine). The reaction is:<br>[ \\text{CH}_3\\text{-NH}_3^+ \\rightarrow \\text{CH}_3\\text{-NH}_2 + \\text{H}^+ ]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>C.) Conjugate base of ( \\text{HPO}_4^{2-} ):<\/strong><br>The hydrogen phosphate ion (( \\text{HPO}_4^{2-} )) loses a proton to become ( \\text{PO}_4^{3-} ) (phosphate ion). The reaction is:<br>[ \\text{HPO}_4^{2-} \\rightarrow \\text{PO}_4^{3-} + \\text{H}^+ ]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>D.) Conjugate base of ( \\text{HNO}_2 ):<\/strong><br>Nitrous acid (( \\text{HNO}_2 )) loses a proton to form ( \\text{NO}_2^- ) (nitrite ion). The reaction is:<br>[ \\text{HNO}_2 \\rightarrow \\text{NO}_2^- + \\text{H}^+ ]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>E.) Conjugate base of ( \\text{HBrO} ):<\/strong><br>Hypobromous acid (( \\text{HBrO} )) loses a proton to form ( \\text{BrO}^- ) (hypobromite ion). The reaction is:<br>[ \\text{HBrO} \\rightarrow \\text{BrO}^- + \\text{H}^+ ]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">General Rule:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A conjugate base is derived by removing one ( \\text{H}^+ ) (proton) from the acid.<\/li>\n\n\n\n<li>The charge decreases by 1 unit for each proton lost.<\/li>\n\n\n\n<li>The chemical formula changes by removing the hydrogen atom.<\/li>\n<\/ul>\n\n\n\n<p>This framework ensures accurate identification of conjugate bases.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A.) Enter the formula of the conjugate base for the acid HCO3-. Express your answer as a chemical formula. B.) Enter the formula of the conjugate base for the acid CH3-NH3+. Express your answer as a chemical formula. C.) Enter the formula of the conjugate base for the acid HPO42-. Express your answer as a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-185393","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185393","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=185393"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185393\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=185393"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=185393"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=185393"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}