How many grams of lithium nitrate, LiNO3 (68.9 g\/mol), are required to prepare 781.0mL of a 0.100 M LiNO3 solution?<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To prepare 781.0 mL of a 0.100 M lithium nitrate (LiNO\u2083) solution, you need to determine the mass of LiNO\u2083 required. Here’s how to calculate it:<\/p>\n\n\n\n Step 1: Convert volume to liters<\/strong><\/p>\n\n\n\n Since molarity (M) is expressed in moles per liter, first convert the volume from milliliters to liters:<\/p>\n\n\n\n 781.0 mL \u00d7 (1 L \/ 1000 mL) = 0.781 L<\/p>\n\n\n\n Step 2: Calculate moles of LiNO\u2083 needed<\/strong><\/p>\n\n\n\n Use the molarity formula:<\/p>\n\n\n\n Moles = Molarity \u00d7 Volume<\/p>\n\n\n\n Moles = 0.100 mol\/L \u00d7 0.781 L = 0.0781 mol<\/p>\n\n\n\n Step 3: Calculate mass of LiNO\u2083 required<\/strong><\/p>\n\n\n\n The molar mass of LiNO\u2083 is 68.9 g\/mol. To find the mass:<\/p>\n\n\n\n Mass = Moles \u00d7 Molar Mass<\/p>\n\n\n\n Mass = 0.0781 mol \u00d7 68.9 g\/mol = 5.38109 g<\/p>\n\n\n\n Therefore, approximately 5.38 grams of LiNO\u2083 are needed.<\/p>\n\n\n\n Explanation:<\/strong><\/p>\n\n\n\n Molarity (M) represents the concentration of a solution, defined as the number of moles of solute per liter of solution. To prepare a solution with a specific molarity and volume, you can calculate the required moles of solute by multiplying the molarity by the volume in liters. Once you have the moles, you can convert this to grams using the molar mass of the solute.<\/p>\n\n\n\n In this case, the desired concentration is 0.100 M, and the volume is 781.0 mL (which converts to 0.781 L). Multiplying these gives the moles of LiNO\u2083 needed. Then, multiplying the moles by the molar mass of LiNO\u2083 (68.9 g\/mol) provides the mass required.<\/p>\n\n\n\n This method ensures that the solution has the correct concentration for its intended use.<\/p>\n","protected":false},"excerpt":{"rendered":" How many grams of lithium nitrate, LiNO3 (68.9 g\/mol), are required to prepare 781.0mL of a 0.100 M LiNO3 solution? The Correct Answer and Explanation is : To prepare 781.0 mL of a 0.100 M lithium nitrate (LiNO\u2083) solution, you need to determine the mass of LiNO\u2083 required. Here’s how to calculate it: Step 1: […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-185610","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185610","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=185610"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185610\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=185610"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=185610"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=185610"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}