{"id":185704,"date":"2025-01-22T20:36:02","date_gmt":"2025-01-22T20:36:02","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=185704"},"modified":"2025-01-22T20:36:04","modified_gmt":"2025-01-22T20:36:04","slug":"lead-iv-sulfate-reacts-with-lithium-nitrate","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/22\/lead-iv-sulfate-reacts-with-lithium-nitrate\/","title":{"rendered":"Lead (IV) sulfate reacts with lithium nitrate"},"content":{"rendered":"\n<p>Lead (IV) sulfate reacts with lithium nitrate, write a balanced equation to represent this reaction.<br>How many grams of lithium nitrate will be needed to make 250. grams of lithium sulfate. assuming that you have an adequate amount of lead (IV) sulfate?<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To start, let&#8217;s write the balanced chemical equation for the reaction between lead (IV) sulfate and lithium nitrate to form lithium sulfate and lead (IV) nitrate.<\/p>\n\n\n\n<p>The reaction is:<\/p>\n\n\n\n<p>[<br>\\text{Pb(SO}_4\\text{)}_2 + 4 \\text{LiNO}_3 \\rightarrow 2 \\text{Li}_2\\text{SO}_4 + \\text{Pb(NO}_3\\text{)}_4<br>]<\/p>\n\n\n\n<p>In this equation, lead (IV) sulfate reacts with lithium nitrate to form lithium sulfate and lead (IV) nitrate.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Determining the Molar Masses<\/h3>\n\n\n\n<p>To find the mass of lithium nitrate required to produce 250 g of lithium sulfate, we need to follow a few steps, beginning with determining the molar masses.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Molar Mass of Lithium Sulfate (Li\u2082SO\u2084):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Lithium (Li): 6.94 g\/mol<\/li>\n\n\n\n<li>Sulfur (S): 32.07 g\/mol<\/li>\n\n\n\n<li>Oxygen (O): 16.00 g\/mol<\/li>\n\n\n\n<li>Molar mass of Li\u2082SO\u2084 = (2 \u00d7 6.94) + 32.07 + (4 \u00d7 16.00) = 45.88 + 32.07 + 64.00 = <strong>141.95 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Molar Mass of Lithium Nitrate (LiNO\u2083):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Lithium (Li): 6.94 g\/mol<\/li>\n\n\n\n<li>Nitrogen (N): 14.01 g\/mol<\/li>\n\n\n\n<li>Oxygen (O): 16.00 g\/mol<\/li>\n\n\n\n<li>Molar mass of LiNO\u2083 = 6.94 + 14.01 + (3 \u00d7 16.00) = 6.94 + 14.01 + 48.00 = <strong>68.95 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Using Stoichiometry to Calculate Required Mass of Lithium Nitrate<\/h3>\n\n\n\n<p>From the balanced equation, we know that 1 mole of Pb(SO\u2084)\u2082 produces 2 moles of Li\u2082SO\u2084. For every 1 mole of Li\u2082SO\u2084 produced, 4 moles of LiNO\u2083 are required.<\/p>\n\n\n\n<p>We can use this information to set up a stoichiometric calculation.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Determine moles of Li\u2082SO\u2084 needed:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass of Li\u2082SO\u2084 required = 250.0 g<\/li>\n\n\n\n<li>Moles of Li\u2082SO\u2084 = mass \/ molar mass = 250.0 g \/ 141.95 g\/mol = <strong>1.76 moles of Li\u2082SO\u2084<\/strong><\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Calculate moles of LiNO\u2083 required:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>From the balanced equation, 4 moles of LiNO\u2083 are required for every 2 moles of Li\u2082SO\u2084. Therefore, moles of LiNO\u2083 = (1.76 moles Li\u2082SO\u2084) \u00d7 (4 moles LiNO\u2083 \/ 2 moles Li\u2082SO\u2084) = <strong>3.52 moles of LiNO\u2083<\/strong><\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Convert moles of LiNO\u2083 to grams:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass of LiNO\u2083 = moles \u00d7 molar mass = 3.52 moles \u00d7 68.95 g\/mol = <strong>242.6 g<\/strong><\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>To make 250.0 grams of lithium sulfate, <strong>242.6 grams of lithium nitrate<\/strong> will be needed, assuming an adequate amount of lead (IV) sulfate is available.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Lead (IV) sulfate reacts with lithium nitrate, write a balanced equation to represent this reaction.How many grams of lithium nitrate will be needed to make 250. grams of lithium sulfate. assuming that you have an adequate amount of lead (IV) sulfate? The Correct Answer and Explanation is : To start, let&#8217;s write the balanced chemical [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-185704","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185704","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=185704"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185704\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=185704"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=185704"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=185704"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}