{"id":185779,"date":"2025-01-23T06:52:44","date_gmt":"2025-01-23T06:52:44","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=185779"},"modified":"2025-01-23T06:52:46","modified_gmt":"2025-01-23T06:52:46","slug":"which-of-the-following-electron-configurations-is-incorrect-as-written","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/23\/which-of-the-following-electron-configurations-is-incorrect-as-written\/","title":{"rendered":"Which of the following electron configurations is incorrect as written"},"content":{"rendered":"\n<p>41) Which of the following electron configurations is incorrect as written?<\/p>\n\n\n\n<p>A) 1s22s22p63s23p64s23d104p4<\/p>\n\n\n\n<p>B) 1s22s22px22py22pz23s2<\/p>\n\n\n\n<p>C) 1s22s22p63s23p63d10<\/p>\n\n\n\n<p>D) 1s22s22p63s2<\/p>\n\n\n\n<p>42) The electron configuration shown below is for the element <strong><em>__<\/em><\/strong>.<\/p>\n\n\n\n<p>1s22s22p63s23p64s23d104p4<\/p>\n\n\n\n<p>A) Se<\/p>\n\n\n\n<p>B) Ga<\/p>\n\n\n\n<p>C) As<\/p>\n\n\n\n<p>D) Br<\/p>\n\n\n\n<p>43) Which element has the electron configuration [Kr]5s24d105p2?<\/p>\n\n\n\n<p>A) Sn<\/p>\n\n\n\n<p>B) Sb<\/p>\n\n\n\n<p>C) Pb<\/p>\n\n\n\n<p>D) Ge<\/p>\n\n\n\n<p>44) Hund&#8217;s rule is needed in drawing an orbital diagram for which of the following elements?<\/p>\n\n\n\n<p>A) krypton<\/p>\n\n\n\n<p>B) lithium<\/p>\n\n\n\n<p>C) boron<\/p>\n\n\n\n<p>D) selenium<\/p>\n\n\n\n<p>45) The number of unpaired electrons present in a magnesium atom is <strong><em>__<\/em><\/strong>.<\/p>\n\n\n\n<p>A) 0<\/p>\n\n\n\n<p>B) 1<\/p>\n\n\n\n<p>C) 3<\/p>\n\n\n\n<p>D) 2<\/p>\n\n\n\n<p>46) How many unpaired electrons are in a Ru atom?<\/p>\n\n\n\n<p>A) 2<\/p>\n\n\n\n<p>B) 4<\/p>\n\n\n\n<p>C) 6<\/p>\n\n\n\n<p>D) 0<\/p>\n\n\n\n<p>47) In which pair are the atoms, Ba and Xe, correctly identified regarding their magnetic properties?<\/p>\n\n\n\n<p>A) Ba: diamagneticXe: diamagnetic<\/p>\n\n\n\n<p>B) Ba: diamagneticXe: paramagnetic<\/p>\n\n\n\n<p>C) Ba: paramagneticXe: diamagnetic<\/p>\n\n\n\n<p>D) Ba: paramagneticXe: paramagnetic<\/p>\n\n\n\n<p>48) Which of the following atoms is paramagnetic?<\/p>\n\n\n\n<p>A) Ar<\/p>\n\n\n\n<p>B) Ca<\/p>\n\n\n\n<p>C) O<\/p>\n\n\n\n<p>D) Zn<\/p>\n\n\n\n<p>49) In the electron configuration of an arsenic atom, there are <strong><em>__<\/em><\/strong> unpaired electrons.<\/p>\n\n\n\n<p>A) 2<\/p>\n\n\n\n<p>B) 0<\/p>\n\n\n\n<p>C) 1<\/p>\n\n\n\n<p>D) 3<\/p>\n\n\n\n<p>50) How many unpaired electrons are there in a phosphorous atom?<\/p>\n\n\n\n<p>A) 1<\/p>\n\n\n\n<p>B) 2<\/p>\n\n\n\n<p>C) 3<\/p>\n\n\n\n<p>D) 4<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p><strong>41) Which of the following electron configurations is incorrect as written?<\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>B) 1s\u00b22s\u00b22px\u00b22py\u00b22pz\u00b23s\u00b2<\/strong>.<\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Option A (1s\u00b22s\u00b22p\u20763s\u00b23p\u20764s\u00b23d\u00b9\u20704p\u2074) is correct. This corresponds to the element Selenium (Se), which follows the Aufbau principle, Pauli exclusion principle, and Hund&#8217;s rule.<\/li>\n\n\n\n<li>Option B is incorrect. The 2p subshell can hold a maximum of 6 electrons, not 4, and therefore the electron configuration &#8220;2px\u00b22py\u00b22pz\u00b2&#8221; is incorrect because it exceeds the capacity of the 2p orbital. The correct configuration for the 2p orbital would be 2px\u00b22py\u00b22pz\u00b2, which would fill all 6 available 2p electrons.<\/li>\n\n\n\n<li>Option C (1s\u00b22s\u00b22p\u20763s\u00b23p\u20763d\u00b9\u2070) is correct, as it represents the element Zinc (Zn) where the 3d subshell is completely filled.<\/li>\n\n\n\n<li>Option D (1s\u00b22s\u00b22p\u20763s\u00b2) is correct for Magnesium (Mg), which only has electrons up to the 3s orbital.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>42) The electron configuration shown below is for the element ________.<\/strong> 1s\u00b22s\u00b22p\u20763s\u00b23p\u20764s\u00b23d\u00b9\u20704p\u2074<\/p>\n\n\n\n<p>The correct answer is <strong>A) Se<\/strong> (Selenium).<\/p>\n\n\n\n<p><strong>Explanation:<\/strong> The electron configuration 1s\u00b22s\u00b22p\u20763s\u00b23p\u20764s\u00b23d\u00b9\u20704p\u2074 represents Selenium (Se), an element in the fourth period and group 16 of the periodic table. The configuration corresponds to 34 electrons, matching the atomic number of Selenium.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>43) Which element has the electron configuration [Kr]5s\u00b24d\u00b9\u20705p\u00b2?<\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>A) Sn<\/strong> (Tin).<\/p>\n\n\n\n<p><strong>Explanation:<\/strong> The electron configuration [Kr]5s\u00b24d\u00b9\u20705p\u00b2 corresponds to Tin (Sn), which has an atomic number of 50. The configuration shows the 5s, 4d, and 5p subshells, indicating the element is in period 5, group 14 of the periodic table.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>44) Hund&#8217;s rule is needed in drawing an orbital diagram for which of the following elements?<\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>C) Boron<\/strong>.<\/p>\n\n\n\n<p><strong>Explanation:<\/strong> Hund\u2019s rule states that electrons will fill degenerate orbitals (orbitals of the same energy) singly before pairing. For Boron, with an electron configuration of 1s\u00b22s\u00b22p\u00b9, the electrons in the 2p orbital will occupy individual orbitals before pairing, and this rule would apply in drawing its orbital diagram.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>45) The number of unpaired electrons present in a magnesium atom is ________.<\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>A) 0<\/strong>.<\/p>\n\n\n\n<p><strong>Explanation:<\/strong> Magnesium (Mg) has the electron configuration 1s\u00b22s\u00b22p\u20763s\u00b2. The 3s orbital is completely filled with 2 electrons, and since it has no unpaired electrons, the answer is 0.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>46) How many unpaired electrons are in a Ru atom?<\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>B) 4<\/strong>.<\/p>\n\n\n\n<p><strong>Explanation:<\/strong> Ruthenium (Ru) has an atomic number of 44, and its electron configuration is [Kr]5s\u00b24d\u2076. In the 4d subshell, there are 6 electrons, and based on Hund\u2019s rule, 4 of these electrons will be unpaired, giving a total of 4 unpaired electrons.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>47) In which pair are the atoms, Ba and Xe, correctly identified regarding their magnetic properties?<\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>C) Ba: paramagnetic Xe: diamagnetic<\/strong>.<\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ba (Barium) has the electron configuration [Xe]6s\u00b2, and since it has unpaired electrons, it is paramagnetic.<\/li>\n\n\n\n<li>Xe (Xenon) has the electron configuration [Kr]4d\u00b9\u20705s\u00b25p\u2076, which is completely filled and has no unpaired electrons, making it diamagnetic.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>48) Which of the following atoms is paramagnetic?<\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>C) O<\/strong> (Oxygen).<\/p>\n\n\n\n<p><strong>Explanation:<\/strong> Oxygen has the electron configuration 1s\u00b22s\u00b22p\u2074, and the 2p subshell has 2 unpaired electrons, making it paramagnetic (attracted to magnetic fields).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>49) In the electron configuration of an arsenic atom, there are ________ unpaired electrons.<\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>D) 3<\/strong>.<\/p>\n\n\n\n<p><strong>Explanation:<\/strong> Arsenic (As) has the electron configuration [Ar]4s\u00b23d\u00b9\u20704p\u00b3. In the 4p subshell, there are 3 unpaired electrons.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>50) How many unpaired electrons are there in a phosphorus atom?<\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>C) 3<\/strong>.<\/p>\n\n\n\n<p><strong>Explanation:<\/strong> Phosphorus (P) has the electron configuration 1s\u00b22s\u00b22p\u20763s\u00b23p\u00b3. In the 3p subshell, there are 3 unpaired electrons.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>41) Which of the following electron configurations is incorrect as written? A) 1s22s22p63s23p64s23d104p4 B) 1s22s22px22py22pz23s2 C) 1s22s22p63s23p63d10 D) 1s22s22p63s2 42) The electron configuration shown below is for the element __. 1s22s22p63s23p64s23d104p4 A) Se B) Ga C) As D) Br 43) Which element has the electron configuration [Kr]5s24d105p2? A) Sn B) Sb C) Pb D) Ge [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-185779","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185779","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=185779"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185779\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=185779"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=185779"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=185779"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}