{"id":185973,"date":"2025-01-23T19:34:52","date_gmt":"2025-01-23T19:34:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=185973"},"modified":"2025-01-23T19:34:54","modified_gmt":"2025-01-23T19:34:54","slug":"use-this-condensed-chemical-structure-to-complete-the-table-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/23\/use-this-condensed-chemical-structure-to-complete-the-table-below\/","title":{"rendered":"Use this condensed chemical structure to complete the table below"},"content":{"rendered":"\n

Use this condensed chemical structure to complete the table below. OH I CH3- -CH-OH Some facts about the 1,1-ethanediol molecule: number of carbon-carbon single (C – C) bonds: number of carbon-hydrogen single (CH) bonds: number of oxygen-hydrogen single (O – H) bonds: number of lone pairs: X The condensed chemical structure of 1,1-ethanediol 8 000
Pls help asap and make sure your answer is correct. Also can you pls explain how did you get the answer. I am little confused what I am doing wrong there, thank you<\/p>\n\n\n\n

Use this condensed chemical structure to complete the table below. OH I -CH-OH CH3- The condensed chemical structure of 1,1-ethanediol Some facts about the 1,1-ethanediol molecule: number of carbon-carbon single (C – C) bonds: number of carbon-hydrogen single (C – H) bonds: number of oxygen-hydrogen single (O – H) bonds: number of lone pairs: X 0<\/p>\n\n\n\n

The correct answer and explanation is:
<\/mark><\/strong>


Problem 1: Factors of 1080 divisible by 10 but not by 30<\/p>\n\n\n\n

Step 1: Prime Factorization of 1080<\/h4>\n\n\n\n

1080=23\u22c533\u22c5511080 = 2^3 \\cdot 3^3 \\cdot 5^1<\/p>\n\n\n\n

A factor is divisible by 1010 if it contains at least 212^1 and 515^1. A factor is divisible by 3030 if it contains 212^1, 313^1, and 515^1.<\/p>\n\n\n\n

Step 2: Total factors divisible by 10<\/h4>\n\n\n\n

To count factors divisible by 1010, fix 2\u226512 \\geq 1 and 5\u226515 \\geq 1. The exponents of 22, 33, and 55 can vary as follows:<\/p>\n\n\n\n

    \n
  • 2k2^k where k=1,2,3k = 1, 2, 3<\/li>\n\n\n\n
  • 3m3^m where m=0,1,2,3m = 0, 1, 2, 3<\/li>\n\n\n\n
  • 5n5^n where n=1n = 1<\/li>\n<\/ul>\n\n\n\n

    The total number of such factors: 3\u22c54\u22c51=123 \\cdot 4 \\cdot 1 = 12<\/p>\n\n\n\n

    Step 3: Total factors divisible by 30<\/h4>\n\n\n\n

    Fix 2\u226512 \\geq 1, 3\u226513 \\geq 1, and 5\u226515 \\geq 1. The exponents of 22, 33, and 55 can vary as:<\/p>\n\n\n\n

      \n
    • 2k2^k where k=1,2,3k = 1, 2, 3<\/li>\n\n\n\n
    • 3m3^m where m=1,2,3m = 1, 2, 3<\/li>\n\n\n\n
    • 5n5^n where n=1n = 1<\/li>\n<\/ul>\n\n\n\n

      The total number of such factors: 3\u22c53\u22c51=93 \\cdot 3 \\cdot 1 = 9<\/p>\n\n\n\n

      Step 4: Factors divisible by 10 but not 30<\/h4>\n\n\n\n

      12\u22129=312 – 9 = 3<\/p>\n\n\n\n

      Answer: (b) 3<\/strong><\/p>\n\n\n\n

      \n\n\n\n

      Problem 2: Factors of 1920 satisfying conditions<\/h3>\n\n\n\n

      Step 1: Prime Factorization of 1920<\/h4>\n\n\n\n

      1920=27\u22c531\u22c5511920 = 2^7 \\cdot 3^1 \\cdot 5^1<\/p>\n\n\n\n

      Step 2: Conditions<\/h4>\n\n\n\n
        \n
      1. Perfect square<\/strong>: All exponents in the prime factorization must be even.<\/li>\n\n\n\n
      2. Multiple of 10<\/strong>: Contains at least 212^1 and 515^1.<\/li>\n\n\n\n
      3. Not divisible by 30<\/strong>: Cannot contain 313^1.<\/li>\n<\/ol>\n\n\n\n

        Step 3: Satisfying all conditions<\/h4>\n\n\n\n
          \n
        • For a perfect square, 272^7 contributes even powers: 20,22,24,262^0, 2^2, 2^4, 2^6 (4 choices).<\/li>\n\n\n\n
        • 313^1 cannot be present (00 choice).<\/li>\n\n\n\n
        • 515^1 contributes 505^0 or 525^2 (11 choice for 525^2).<\/li>\n<\/ul>\n\n\n\n

          Thus, the valid factors are combinations of 2k\u22c5522^k \\cdot 5^2, where k=0,2,4,6k = 0, 2, 4, 6. These are 4 factors<\/strong>.<\/p>\n\n\n\n

          Answer: (d) 5<\/strong>

          <\/p>\n","protected":false},"excerpt":{"rendered":"

          Use this condensed chemical structure to complete the table below. OH I CH3- -CH-OH Some facts about the 1,1-ethanediol molecule: number of carbon-carbon single (C – C) bonds: number of carbon-hydrogen single (CH) bonds: number of oxygen-hydrogen single (O – H) bonds: number of lone pairs: X The condensed chemical structure of 1,1-ethanediol 8 000Pls […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-185973","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185973","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=185973"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/185973\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=185973"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=185973"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=185973"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}