{"id":186074,"date":"2025-01-24T05:51:52","date_gmt":"2025-01-24T05:51:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=186074"},"modified":"2025-01-24T05:51:54","modified_gmt":"2025-01-24T05:51:54","slug":"draw-the-line-bond-structure-for-acetone","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/24\/draw-the-line-bond-structure-for-acetone\/","title":{"rendered":"Draw the Line Bond Structure for Acetone"},"content":{"rendered":"\n<p>Draw the Line Bond Structure for Acetone (C3H\u00c3\u00a2\u00e2\u20ac\u0161\u00e2\u20ac\u0161O) Step 2: Step 1A: (ADD HYDROGENS UNTIL EACH CARBON HAS 4 BONDS = OCTET) Use the skeleton structure from step 1A to find: O || C C C Step 1B: Count the total number of valence electrons from all the atoms in the molecule. Chemical formula of molecule Atom # of atoms X X X # of valence electrons = = Total # of electrons in structure = totals Step 3: Subtract the number of electrons used to make the skeleton structure from the total number of valence electrons. Total # of electrons in structure (from step 1 above) # of electrons used in skeleton (from step 2 above) Remaining # electrons to be added= Step 5: Check for Octets Check the structure in step 4 for octets (4 pairs) of electrons around each atom. If octet rule is satisfied, you are done. If octet rule is not satisfied, go to Step 6. # of electrons used in skeleton = (multiply # of bonds in skeleton by 2) Step 4: Add the remaining electrons (if any remain) to the skeletal structure above as lone pairs as evenly as possible on all atoms except hydrogen. Step 6: Use existing lone pairs to make double or triple bonds until the octet rule is satisfied for all atoms<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Acetone (C\u2083H\u2086O), also known as propan-2-one, is the simplest ketone with a central carbonyl group (C=O) flanked by two methyl groups (CH\u2083). To draw its Lewis structure, follow these steps:<\/p>\n\n\n\n<p><strong>Step 1A: Skeleton Structure<\/strong><\/p>\n\n\n\n<p>Arrange the atoms to reflect the molecular formula:<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>   H3C\u2014C\u2014C\u2014H3\n        ||\n        O<\/code><\/pre>\n\n\n\n<p>Here, the central carbon (C\u2082) is double-bonded to oxygen (O) and single-bonded to two other carbons (C\u2081 and C\u2083), each bonded to three hydrogens.<\/p>\n\n\n\n<p><strong>Step 1B: Count Valence Electrons<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon (C):<\/strong> Each carbon atom has 4 valence electrons. With three carbons, that&#8217;s 4 \u00d7 3 = 12 electrons.<\/li>\n\n\n\n<li><strong>Hydrogen (H):<\/strong> Each hydrogen atom has 1 valence electron. With six hydrogens, that&#8217;s 1 \u00d7 6 = 6 electrons.<\/li>\n\n\n\n<li><strong>Oxygen (O):<\/strong> Oxygen has 6 valence electrons.<\/li>\n<\/ul>\n\n\n\n<p><strong>Total valence electrons:<\/strong> 12 (C) + 6 (H) + 6 (O) = 24 electrons.<\/p>\n\n\n\n<p><strong>Step 2: Add Hydrogens to Satisfy Carbon&#8217;s Octet<\/strong><\/p>\n\n\n\n<p>Each carbon atom needs four bonds to satisfy the octet rule:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>C\u2081 and C\u2083:<\/strong> Each is bonded to three hydrogens, fulfilling their valency.<\/li>\n\n\n\n<li><strong>C\u2082 (central carbon):<\/strong> Forms a double bond with oxygen and single bonds with C\u2081 and C\u2083, totaling four bonds.<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 3: Subtract Electrons Used in Skeleton from Total Valence Electrons<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Bonds in skeleton:<\/strong><\/li>\n\n\n\n<li>C\u2081\u2014C\u2082: 1 bond<\/li>\n\n\n\n<li>C\u2082\u2014C\u2083: 1 bond<\/li>\n\n\n\n<li>C\u2082=O: 1 bond<\/li>\n\n\n\n<li>C\u2081\u2014H\u2083, C\u2083\u2014H\u2083: 3 bonds each<\/li>\n\n\n\n<li><strong>Total bonds:<\/strong> 1 + 1 + 1 + 3 + 3 = 9 bonds<\/li>\n\n\n\n<li><strong>Electrons used:<\/strong> 9 bonds \u00d7 2 electrons\/bond = 18 electrons<\/li>\n<\/ul>\n\n\n\n<p><strong>Remaining electrons:<\/strong> 24 total electrons \u2013 18 used electrons = 6 electrons.<\/p>\n\n\n\n<p><strong>Step 4: Add Remaining Electrons as Lone Pairs<\/strong><\/p>\n\n\n\n<p>Distribute the remaining 6 electrons as lone pairs:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Oxygen (O):<\/strong> Needs two lone pairs to complete its octet.<\/li>\n\n\n\n<li><strong>C\u2082 (central carbon):<\/strong> No lone pairs; all valence electrons are used in bonding.<\/li>\n\n\n\n<li><strong>C\u2081 and C\u2083:<\/strong> No lone pairs; all valence electrons are used in bonding.<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 5: Check for Octets<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>C\u2081 and C\u2083:<\/strong> Each has four bonds (three single bonds with hydrogens and one single bond with C\u2082), satisfying the octet rule.<\/li>\n\n\n\n<li><strong>C\u2082:<\/strong> Four bonds (one double bond with O and two single bonds with C\u2081 and C\u2083), satisfying the octet rule.<\/li>\n\n\n\n<li><strong>O:<\/strong> Two lone pairs and one double bond with C\u2082, satisfying the octet rule.<\/li>\n<\/ul>\n\n\n\n<p>All atoms have complete octets, confirming the structure is correct.<\/p>\n\n\n\n<p>For a visual demonstration, you can refer to the following video:<\/p>\n\n\n\n<p><a href=\"https:\/\/www.youtube.com\/watch?v=ZJj2sllAlbw&amp;utm_source=chatgpt.com\" target=\"_blank\" rel=\"noopener\">Acetone Lewis Structure: How to Draw the Lewis Structure for Acetone<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw the Line Bond Structure for Acetone (C3H\u00c3\u00a2\u00e2\u20ac\u0161\u00e2\u20ac\u0161O) Step 2: Step 1A: (ADD HYDROGENS UNTIL EACH CARBON HAS 4 BONDS = OCTET) Use the skeleton structure from step 1A to find: O || C C C Step 1B: Count the total number of valence electrons from all the atoms in the molecule. Chemical formula of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-186074","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186074","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=186074"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186074\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=186074"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=186074"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=186074"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}