{"id":186416,"date":"2025-01-25T06:55:35","date_gmt":"2025-01-25T06:55:35","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=186416"},"modified":"2025-01-25T06:55:37","modified_gmt":"2025-01-25T06:55:37","slug":"in-figure-a-particles-1-and-2have-charge-20-0%c2%b5c-each-and-are-held-at-separation-distance-d-1-50-m","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/25\/in-figure-a-particles-1-and-2have-charge-20-0%c2%b5c-each-and-are-held-at-separation-distance-d-1-50-m\/","title":{"rendered":"In Figure a, particles 1 and 2have charge 20.0\u00b5C each and are held at separation distance d = 1.50 m"},"content":{"rendered":"\n<p>In Figure a, particles 1 and 2have charge 20.0\u00b5C each and are held at separation distance d = 1.50 m.<br>(a) What is the magnitude of the electrostatic force on particle 1 due to particle 2? In Figure b, particle 3 of charge 20.0\u00b5C is positioned so as to complete an equilateral triangle.<br>(b) What is the magnitude of the net electrostatic force on particle 1 due to particles 2 and 3?<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/01\/image-452.png\" alt=\"\" class=\"wp-image-186417\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>I can&#8217;t access the image directly from the link, but I can still guide you through solving the problem based on the information you provided.<\/p>\n\n\n\n<p><strong>Part (a): Magnitude of the electrostatic force on particle 1 due to particle 2<\/strong><\/p>\n\n\n\n<p>The electrostatic force between two charged particles can be found using Coulomb\u2019s Law:<\/p>\n\n\n\n<p>[<br>F = \\frac{{k \\cdot |q_1 \\cdot q_2|}}{{r^2}}<br>]<\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>( F ) is the electrostatic force,<\/li>\n\n\n\n<li>( k = 8.99 \\times 10^9 \\, \\text{N} \\cdot \\text{m}^2 \/ \\text{C}^2 ) (Coulomb\u2019s constant),<\/li>\n\n\n\n<li>( q_1 ) and ( q_2 ) are the charges of particles 1 and 2,<\/li>\n\n\n\n<li>( r ) is the distance between the particles.<\/li>\n<\/ul>\n\n\n\n<p>In this case:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>( q_1 = q_2 = 20.0 \\, \\mu C = 20.0 \\times 10^{-6} \\, C ),<\/li>\n\n\n\n<li>( r = d = 1.50 \\, m ).<\/li>\n<\/ul>\n\n\n\n<p>Substitute the values into Coulomb&#8217;s law:<\/p>\n\n\n\n<p>[<br>F = \\frac{{(8.99 \\times 10^9) \\cdot (20.0 \\times 10^{-6})^2}}{{(1.50)^2}}<br>]<\/p>\n\n\n\n<p>Now, you can calculate ( F ).<\/p>\n\n\n\n<p><strong>Part (b): Magnitude of the net electrostatic force on particle 1 due to particles 2 and 3<\/strong><\/p>\n\n\n\n<p>In the second part, you have particle 3 positioned to form an equilateral triangle with particles 1 and 2. This means that the distances between particles 1, 2, and 3 are all the same (1.50 m).<\/p>\n\n\n\n<p>The force on particle 1 due to particle 3 will be the same as the force due to particle 2 (from part a), but now we need to account for the vector nature of the forces since they are not along the same line.<\/p>\n\n\n\n<p>To find the net force, calculate the individual forces between particle 1 and particles 2, and between particle 1 and particle 3. Then, add them vectorially. Since they form an equilateral triangle, the angle between the forces will be 120\u00b0.<\/p>\n\n\n\n<p>The net force ( F_{\\text{net}} ) is calculated using the vector sum:<\/p>\n\n\n\n<p>[<br>F_{\\text{net}} = \\sqrt{F_1^2 + F_2^2 + 2F_1F_2 \\cos \\theta}<br>]<\/p>\n\n\n\n<p>Where ( \\theta = 120^\\circ ), and ( F_1 = F_2 ).<\/p>\n\n\n\n<p>Using this approach, you can solve for the net electrostatic force on particle 1.<\/p>\n\n\n\n<p>Let me know if you&#8217;d like further help with the specific calculations!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>In Figure a, particles 1 and 2have charge 20.0\u00b5C each and are held at separation distance d = 1.50 m.(a) What is the magnitude of the electrostatic force on particle 1 due to particle 2? In Figure b, particle 3 of charge 20.0\u00b5C is positioned so as to complete an equilateral triangle.(b) What is the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-186416","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186416","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=186416"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186416\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=186416"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=186416"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=186416"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}