{"id":186556,"date":"2025-01-25T09:10:20","date_gmt":"2025-01-25T09:10:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=186556"},"modified":"2025-01-25T09:10:23","modified_gmt":"2025-01-25T09:10:23","slug":"find-the-value-of-each-trigonometric-ratio","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/25\/find-the-value-of-each-trigonometric-ratio\/","title":{"rendered":"Find the value of each trigonometric ratio"},"content":{"rendered":"\n<p>Find the value of each trigonometric ratio. Make sure you reduce\/simplify the fractions. 1) sin z 2) sinc 40 24 36 39 32 3) cos X 4) cos X X 15 Z 37 12 9 12 35 5) tan 2 6) tan C Z 24 40 30 32 50 C X 7) sin A 8) tanz B \u0441 30 40 24 50 For 9) and 10) find ALL SIX trigonometric ratios ( sin, cos, tan, sec, csc, and cot) NOT only the one that is typed. 9) tan 4<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/01\/image-467.png\" alt=\"\" class=\"wp-image-186557\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To determine the values of the six trigonometric ratios for an angle \u03b8, we need to know the lengths of the sides of a right-angled triangle relative to \u03b8. The six trigonometric functions are:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Sine (sin \u03b8)<\/strong>: \ue203Opposite side \/ Hypotenuse\ue204\ue206<\/li>\n\n\n\n<li><strong>Cosine (cos \u03b8)<\/strong>: \ue203Adjacent side \/ Hypotenuse\ue204\ue206<\/li>\n\n\n\n<li><strong>Tangent (tan \u03b8)<\/strong>: \ue203Opposite side \/ Adjacent side\ue204\ue206<\/li>\n\n\n\n<li><strong>Cosecant (csc \u03b8)<\/strong>: \ue203Hypotenuse \/ Opposite side\ue204\ue206<\/li>\n\n\n\n<li><strong>Secant (sec \u03b8)<\/strong>: \ue203Hypotenuse \/ Adjacent side\ue204\ue206<\/li>\n\n\n\n<li><strong>Cotangent (cot \u03b8)<\/strong>: \ue203Adjacent side \/ Opposite side\ue204\ue206<\/li>\n<\/ol>\n\n\n\n<p>Given the information provided, it appears that some of the data might be incomplete or unclear. However, based on the available details, let&#8217;s attempt to calculate the trigonometric ratios for the following scenarios:<\/p>\n\n\n\n<p><strong>1) sin z<\/strong><\/p>\n\n\n\n<p>Without specific information about the sides of the triangle or the angle z, it&#8217;s not possible to determine sin z. \ue203To calculate sin z, we need the length of the side opposite angle z and the hypotenuse.\ue204\ue206<\/p>\n\n\n\n<p><strong>2) sinc 40 24 36 39 32<\/strong><\/p>\n\n\n\n<p>This expression is unclear. \ue203If it refers to a triangle with sides 24, 36, and 40, we can use the Pythagorean theorem to check if it&#8217;s a right-angled triangle:\ue204\ue206<\/p>\n\n\n\n<p>\ue20324\u00b2 + 36\u00b2 = 576 + 1296 = 1872\ue204\ue206 \ue20340\u00b2 = 1600\ue204\ue206<\/p>\n\n\n\n<p>Since 1872 \u2260 1600, this is not a right-angled triangle, and trigonometric ratios cannot be determined without additional information.<\/p>\n\n\n\n<p><strong>3) cos X<\/strong><\/p>\n\n\n\n<p>Without details about the sides of the triangle or the angle X, it&#8217;s not possible to determine cos X. \ue203To calculate cos X, we need the length of the adjacent side and the hypotenuse.\ue204\ue206<\/p>\n\n\n\n<p><strong>4) cos X X 15 Z 37 12 9 12 35<\/strong><\/p>\n\n\n\n<p>This expression is unclear. \ue203If it refers to a triangle with sides 9, 12, and 15, we can check if it&#8217;s a right-angled triangle:\ue204\ue206<\/p>\n\n\n\n<p>\ue2039\u00b2 + 12\u00b2 = 81 + 144 = 225\ue204\ue206 \ue20315\u00b2 = 225\ue204\ue206<\/p>\n\n\n\n<p>Since 225 = 225, this is a right-angled triangle. \ue203For angle X, cos X = Adjacent \/ Hypotenuse = 12 \/ 15 = 4 \/ 5.\ue204\ue206<\/p>\n\n\n\n<p><strong>5) tan 2<\/strong><\/p>\n\n\n\n<p>Without information about the sides of the triangle or the angle, it&#8217;s not possible to determine tan 2. \ue203To calculate tan 2, we need the length of the opposite side and the adjacent side.\ue204\ue206<\/p>\n\n\n\n<p><strong>6) tan C Z 24 40 30 32 50 C X<\/strong><\/p>\n\n\n\n<p>This expression is unclear. \ue203If it refers to a triangle with sides 24, 32, and 40, we can check if it&#8217;s a right-angled triangle:\ue204\ue206<\/p>\n\n\n\n<p>\ue20324\u00b2 + 32\u00b2 = 576 + 1024 = 1600\ue204\ue206 \ue20340\u00b2 = 1600\ue204\ue206<\/p>\n\n\n\n<p>Since 1600 = 1600, this is a right-angled triangle. \ue203For angle C, tan C = Opposite \/ Adjacent = 24 \/ 32 = 3 \/ 4.\ue204\ue206<\/p>\n\n\n\n<p><strong>7) sin A<\/strong><\/p>\n\n\n\n<p>Without information about the sides of the triangle or the angle A, it&#8217;s not possible to determine sin A. \ue203To calculate sin A, we need the length of the opposite side and the hypotenuse.\ue204\ue206<\/p>\n\n\n\n<p><strong>8) tan B \u0441 30 40 24 50<\/strong><\/p>\n\n\n\n<p>This expression is unclear. \ue203If it refers to a triangle with sides 24, 30, and 50, we can check if it&#8217;s a right-angled triangle:\ue204\ue206<\/p>\n\n\n\n<p>\ue20324\u00b2 + 30\u00b2 = 576 + 900 = 1476\ue204\ue206 \ue20350\u00b2 = 2500\ue204\ue206<\/p>\n\n\n\n<p>Since 1476 \u2260 2500, this is not a right-angled triangle, and trigonometric ratios cannot be determined without additional information.<\/p>\n\n\n\n<p><strong>9) tan 4<\/strong><\/p>\n\n\n\n<p>Without information about the sides of the triangle or the angle, it&#8217;s not possible to determine tan 4. \ue203To calculate tan 4, we need the length of the opposite side and the adjacent side.\ue204\ue206<\/p>\n\n\n\n<p><strong>10) tan 4<\/strong><\/p>\n\n\n\n<p>This is a repeat of question 9. \ue203Without information about the sides of the triangle or the angle, it&#8217;s not possible to determine tan 4.\ue204\ue206<\/p>\n\n\n\n<p><strong>General Approach to Finding Trigonometric Ratios:<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Identify the Triangle Type<\/strong>: Determine if the triangle is a right-angled triangle. \ue203If it is, you can use the Pythagorean theorem to find missing sides.\ue204\ue206<\/li>\n\n\n\n<li><strong>Label the Sides<\/strong>: Label the sides of the triangle as opposite, adjacent, and hypotenuse relative to the angle of interest.\ue206<\/li>\n\n\n\n<li><strong>Apply Trigonometric Definitions<\/strong>: Use the definitions of the trigonometric functions to find the desired ratios.\ue206<\/li>\n\n\n\n<li><strong>Simplify the Results<\/strong>: \ue203Ensure that all fractions are in their simplest form.\ue204\ue206<\/li>\n<\/ol>\n\n\n\n<p>For a more detailed explanation and visual demonstration, you might find the following video helpful:<\/p>\n\n\n\n<p>\ue200video\ue2024 3 Right Triangle Trigonometry\ue202turn0search7\ue201<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Find the value of each trigonometric ratio. Make sure you reduce\/simplify the fractions. 1) sin z 2) sinc 40 24 36 39 32 3) cos X 4) cos X X 15 Z 37 12 9 12 35 5) tan 2 6) tan C Z 24 40 30 32 50 C X 7) sin A 8) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-186556","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186556","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=186556"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186556\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=186556"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=186556"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=186556"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}