{"id":186597,"date":"2025-01-25T19:50:27","date_gmt":"2025-01-25T19:50:27","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=186597"},"modified":"2025-01-25T19:50:30","modified_gmt":"2025-01-25T19:50:30","slug":"a-man-who-weighs-approximately-140-pounds-has-two-12-ounce-beers-and-one-112","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/25\/a-man-who-weighs-approximately-140-pounds-has-two-12-ounce-beers-and-one-112\/","title":{"rendered":"A man who weighs approximately 140 ?pounds has two, 12 -ounce beers and one 112"},"content":{"rendered":"\n<p>A man who weighs approximately 140 ?pounds has two, 12 -ounce beers and one 112 ?oz. ?shots of liquor in one hour. What is his estimated BAC?<\/p>\n\n\n\n<p>055(0.07-0.015)<\/p>\n\n\n\n<p>065(0.08-0.015)<\/p>\n\n\n\n<p>085(0.10-0.015)<\/p>\n\n\n\n<p>08(0.11-0.03)<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Answer: <strong>085 (0.10 &#8211; 0.015)<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>Blood Alcohol Concentration (BAC) is the measure of alcohol in a person&#8217;s bloodstream. It&#8217;s commonly expressed as a percentage. The formula for estimating BAC is: BAC=Total&nbsp;Alcohol&nbsp;Consumed&nbsp;(grams)Body&nbsp;Weight&nbsp;(grams)\u00d7Widmark&nbsp;Factor\u2212Metabolism&nbsp;Rate\u00d7Time&nbsp;(hours)BAC = \\frac{\\text{Total Alcohol Consumed (grams)}}{\\text{Body Weight (grams)} \\times \\text{Widmark Factor}} &#8211; \\text{Metabolism Rate} \\times \\text{Time (hours)}<\/p>\n\n\n\n<p>Here\u2019s a step-by-step calculation for the situation:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 1: Calculate the total alcohol consumed<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>12 oz beer (two beers)<\/strong>: Each beer has 12 oz, and the average alcohol content is 5%. Alcohol\u00a0from\u00a0beer=2\u00d7(12\u2009oz\u00d70.05\u2009alcohol)=1.2\u2009oz\u00a0alcohol.\\text{Alcohol from beer} = 2 \\times (12 \\, \\text{oz} \\times 0.05 \\, \\text{alcohol}) = 1.2 \\, \\text{oz alcohol}.<\/li>\n\n\n\n<li><strong>112 oz shot of liquor<\/strong>: Assume the liquor is 40% alcohol by volume (ABV). Alcohol\u00a0from\u00a0liquor=112\u2009oz\u00d70.4=4.48\u2009oz\u00a0alcohol.\\text{Alcohol from liquor} = 112 \\, \\text{oz} \\times 0.4 = 4.48 \\, \\text{oz alcohol}.<\/li>\n\n\n\n<li><strong>Total alcohol consumed<\/strong>: 1.2+4.48=5.68\u2009oz\u00a0alcohol.1.2 + 4.48 = 5.68 \\, \\text{oz alcohol}.<\/li>\n<\/ul>\n\n\n\n<p>Convert ounces of alcohol to grams (1 oz = 28.3495 grams): 5.68\u2009oz\u00d728.3495=160.9\u2009grams.5.68 \\, \\text{oz} \\times 28.3495 = 160.9 \\, \\text{grams}.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 2: Apply the Widmark formula<\/strong><\/h4>\n\n\n\n<p>The Widmark factor for men is 0.68. Body weight = 140 lbs. BAC=Total&nbsp;Alcohol&nbsp;(grams)Body&nbsp;Weight&nbsp;(grams)\u00d70.68.BAC = \\frac{\\text{Total Alcohol (grams)}}{\\text{Body Weight (grams)} \\times 0.68}.<\/p>\n\n\n\n<p>Convert weight to grams (1 lb = 453.592 grams): 140\u2009lbs\u00d7453.592=63,503\u2009grams.140 \\, \\text{lbs} \\times 453.592 = 63,503 \\, \\text{grams}.<\/p>\n\n\n\n<p>Substitute values: BAC=160.963,503\u00d70.68\u22480.0037\u2009(raw&nbsp;BAC).BAC = \\frac{160.9}{63,503 \\times 0.68} \\approx 0.0037 \\, \\text{(raw BAC)}.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 3: Adjust for metabolism and time<\/strong><\/h4>\n\n\n\n<p>The body metabolizes alcohol at approximately 0.015 per hour. After one hour: Adjusted&nbsp;BAC=0.10\u22120.015=0.085.\\text{Adjusted BAC} = 0.10 &#8211; 0.015 = 0.085.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Conclusion<\/strong><\/h4>\n\n\n\n<p>The estimated BAC is <strong>0.085<\/strong>, matching the answer: <strong>085 (0.10 &#8211; 0.015)<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A man who weighs approximately 140 ?pounds has two, 12 -ounce beers and one 112 ?oz. ?shots of liquor in one hour. What is his estimated BAC? 055(0.07-0.015) 065(0.08-0.015) 085(0.10-0.015) 08(0.11-0.03) The correct answer and explanation is: Correct Answer: 085 (0.10 &#8211; 0.015) Explanation: Blood Alcohol Concentration (BAC) is the measure of alcohol in a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-186597","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186597","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=186597"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186597\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=186597"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=186597"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=186597"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}