{"id":186629,"date":"2025-01-26T05:00:51","date_gmt":"2025-01-26T05:00:51","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=186629"},"modified":"2025-01-26T05:00:53","modified_gmt":"2025-01-26T05:00:53","slug":"which-has-the-correct-name-formula-combination","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/26\/which-has-the-correct-name-formula-combination\/","title":{"rendered":"Which has the correct name-formula combination"},"content":{"rendered":"\n<p>Which has the correct name-formula combination? A) Iron(II) nitride &#8211; FeN B) Nickel (II) oxide -NIO2 C) Titanium (IV) phosphide &#8211; TiP D) Manganese(II) sulfide &#8211; MnS 2. What type of reaction is represented by the following equation: CoCl2(aq) + 2NaOH(aq) \u2192 Co(OH)2(s) + 2NaCl(aq) A) acid-base B) decomposition C) precipitation D) redox (oxidation-reduction)<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p><strong>Question 1 Answer: A) Iron(II) nitride &#8211; FeN<\/strong><\/p>\n\n\n\n<p>Explanation:<br>In this question, we need to match the correct name to the chemical formula of a compound. To do so, we must first understand the oxidation states of the metals in each option and whether they match the chemical formula.<\/p>\n\n\n\n<p>A) <strong>Iron(II) nitride &#8211; FeN<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Iron (Fe) can have different oxidation states, such as +2 or +3. In this case, the &#8220;Iron(II)&#8221; indicates an oxidation state of +2.<\/li>\n\n\n\n<li>Nitride (N\u00b3\u207b) is the ion formed by nitrogen when it gains three electrons, giving it a charge of -3.<\/li>\n\n\n\n<li>To balance the charges, you need one Fe\u00b2\u207a ion to pair with one N\u00b3\u207b ion, resulting in FeN, which is indeed correct.<\/li>\n<\/ul>\n\n\n\n<p>B) <strong>Nickel(II) oxide &#8211; NiO2<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nickel (Ni) in the &#8220;Nickel(II)&#8221; form means it has an oxidation state of +2.<\/li>\n\n\n\n<li>However, oxide (O\u00b2\u207b) has an oxidation state of -2. So, for a balanced compound, the correct formula should be NiO (not NiO2).<\/li>\n<\/ul>\n\n\n\n<p>C) <strong>Titanium(IV) phosphide &#8211; TiP<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Titanium (Ti) with the oxidation state of +4 will form a compound with phosphide (P\u00b3\u207b), which requires balancing. The correct formula for this compound should be Ti\u2083P\u2084, not TiP.<\/li>\n<\/ul>\n\n\n\n<p>D) <strong>Manganese(II) sulfide &#8211; MnS<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Manganese (Mn) in the +2 oxidation state would combine with sulfide (S\u00b2\u207b) to form MnS, which is indeed a valid compound, but the correct formula is not needed for this question as option A is correct.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Question 2 Answer: C) Precipitation<\/strong><\/p>\n\n\n\n<p>Explanation:<br>The given reaction is:<br>[ \\text{CoCl}_2(aq) + 2\\text{NaOH}(aq) \\rightarrow \\text{Co(OH)}_2(s) + 2\\text{NaCl}(aq) ]<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>CoCl\u2082<\/strong> and <strong>NaOH<\/strong> are both aqueous solutions, meaning they are dissolved in water. The reaction forms <strong>Co(OH)\u2082<\/strong>, which is a solid precipitate (as indicated by &#8220;(s)&#8221;).<\/li>\n\n\n\n<li>Precipitation reactions occur when two aqueous solutions react to form a solid product, which is what happens here with <strong>Co(OH)\u2082<\/strong>. Therefore, the correct answer is <strong>C) Precipitation<\/strong>.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Which has the correct name-formula combination? A) Iron(II) nitride &#8211; FeN B) Nickel (II) oxide -NIO2 C) Titanium (IV) phosphide &#8211; TiP D) Manganese(II) sulfide &#8211; MnS 2. What type of reaction is represented by the following equation: CoCl2(aq) + 2NaOH(aq) \u2192 Co(OH)2(s) + 2NaCl(aq) A) acid-base B) decomposition C) precipitation D) redox (oxidation-reduction) The [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-186629","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186629","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=186629"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186629\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=186629"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=186629"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=186629"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}