{"id":186972,"date":"2025-01-27T06:49:00","date_gmt":"2025-01-27T06:49:00","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=186972"},"modified":"2025-01-27T06:49:02","modified_gmt":"2025-01-27T06:49:02","slug":"n2-hcn-h30-12-nh4-ch20-4-steric-n-a-n-a-electron-geometry","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/27\/n2-hcn-h30-12-nh4-ch20-4-steric-n-a-n-a-electron-geometry\/","title":{"rendered":"N2 HCN H30+ 12 NH4+ CH20 4 Steric # N\/A N\/A Electron Geometry"},"content":{"rendered":"\n

N2 HCN H30+ 12 NH4+ CH20 4 Steric # N\/A N\/A Electron Geometry Choose.. Choose\u2026 – Choose.. tetrahedra Choose Choose\u2026 Choose Choose\u2026 N\/A N\/A # of bonding electron groups 3 N\/A N\/A # of lone pairs N\/A 1 N\/A Choose\u2026 Molecular Geometry Choose.. Choose\u2026 – trigonalp! – Choose. Choose\u2026 Choose Choose\u2026 – N\/A N\/A How many bonds have a dipole? If present, do the dipoles cancel each other? Choose.. Choose\u2026 – Choose. Choose\u2026 – Choose\u2026 Choose\u2026 – Choose.. Choose\u2026 Choose Choose\u2026 Choose Choose\u2026 – Is this molecule polar? Choose Choose\u2026 – Choose. Choose\u2026 – Choose Choose\u2026 – Choose\u2026 Choose\u2026 Choose Choose\u2026 Choose Choose\u2026<\/p>\n\n\n\n

<\/figure>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

The information provided is somewhat incomplete or difficult to interpret, but I can still help you break down the molecule and answer the relevant questions. It appears to involve several molecules or ions, so let’s clarify and address each component step by step.<\/p>\n\n\n\n

Molecules\/Compounds in the Question:<\/h3>\n\n\n\n
    \n
  1. N\u2082<\/strong> (Nitrogen molecule)<\/li>\n\n\n\n
  2. HCN<\/strong> (Hydrogen Cyanide)<\/li>\n\n\n\n
  3. H\u2083O\u207a<\/strong> (Hydronium ion)<\/li>\n\n\n\n
  4. NH\u2084\u207a<\/strong> (Ammonium ion)<\/li>\n\n\n\n
  5. CH\u2082O<\/strong> (Formaldehyde)<\/li>\n<\/ol>\n\n\n\n

    Step-by-Step Explanation:<\/h3>\n\n\n\n
      \n
    1. Electron Geometry:<\/strong><\/li>\n<\/ol>\n\n\n\n
        \n
      • N\u2082<\/strong>: Linear, because it’s a simple diatomic molecule (N\u2261N).<\/li>\n\n\n\n
      • HCN<\/strong>: Linear, as it consists of a central carbon atom triple-bonded to nitrogen and single-bonded to hydrogen.<\/li>\n\n\n\n
      • H\u2083O\u207a<\/strong>: Tetrahedral, with one oxygen bonded to three hydrogens, and the oxygen atom carries a lone pair.<\/li>\n\n\n\n
      • NH\u2084\u207a<\/strong>: Tetrahedral, as the nitrogen is bonded to four hydrogens with no lone pairs.<\/li>\n\n\n\n
      • CH\u2082O<\/strong>: Trigonal planar, with carbon in the center and double-bonded to oxygen while single-bonded to two hydrogens.<\/li>\n<\/ul>\n\n\n\n
          \n
        1. Bonding Electron Groups & Lone Pairs:<\/strong><\/li>\n<\/ol>\n\n\n\n
            \n
          • N\u2082<\/strong>: There are two bonding electron groups (triple bond between N atoms), no lone pairs.<\/li>\n\n\n\n
          • HCN<\/strong>: Three bonding electron groups (C-H and C\u2261N), no lone pairs on C or N.<\/li>\n\n\n\n
          • H\u2083O\u207a<\/strong>: Three bonding electron groups (O-H) and one lone pair on the oxygen atom.<\/li>\n\n\n\n
          • NH\u2084\u207a<\/strong>: Four bonding electron groups, no lone pairs on nitrogen.<\/li>\n\n\n\n
          • CH\u2082O<\/strong>: Three bonding electron groups (C-H and C=O), no lone pairs on carbon.<\/li>\n<\/ul>\n\n\n\n
              \n
            1. Molecular Geometry:<\/strong><\/li>\n<\/ol>\n\n\n\n
                \n
              • N\u2082<\/strong>: Linear.<\/li>\n\n\n\n
              • HCN<\/strong>: Linear.<\/li>\n\n\n\n
              • H\u2083O\u207a<\/strong>: Tetrahedral.<\/li>\n\n\n\n
              • NH\u2084\u207a<\/strong>: Tetrahedral.<\/li>\n\n\n\n
              • CH\u2082O<\/strong>: Trigonal planar.<\/li>\n<\/ul>\n\n\n\n
                  \n
                1. Dipoles:<\/strong><\/li>\n<\/ol>\n\n\n\n
                    \n
                  • N\u2082<\/strong>: No dipole, as it’s a homonuclear diatomic molecule.<\/li>\n\n\n\n
                  • HCN<\/strong>: Yes, HCN has a dipole because of the difference in electronegativity between carbon and nitrogen.<\/li>\n\n\n\n
                  • H\u2083O\u207a<\/strong>: Yes, the H-O bond has a dipole. The hydronium ion is polar due to the lone pair on oxygen.<\/li>\n\n\n\n
                  • NH\u2084\u207a<\/strong>: No dipole, because the tetrahedral geometry is symmetrical, and the bond dipoles cancel.<\/li>\n\n\n\n
                  • CH\u2082O<\/strong>: Yes, CH\u2082O has a dipole moment because the oxygen is more electronegative than carbon and hydrogen.<\/li>\n<\/ul>\n\n\n\n
                      \n
                    1. Polarity:<\/strong><\/li>\n<\/ol>\n\n\n\n
                        \n
                      • N\u2082<\/strong>: Nonpolar, as the dipoles cancel out.<\/li>\n\n\n\n
                      • HCN<\/strong>: Polar, as the dipoles don\u2019t cancel.<\/li>\n\n\n\n
                      • H\u2083O\u207a<\/strong>: Polar, due to the lone pair on oxygen and the distribution of electron density.<\/li>\n\n\n\n
                      • NH\u2084\u207a<\/strong>: Nonpolar, due to symmetry.<\/li>\n\n\n\n
                      • CH\u2082O<\/strong>: Polar, as the dipoles don\u2019t cancel.<\/li>\n<\/ul>\n\n\n\n

                        Conclusion:<\/h3>\n\n\n\n

                        Based on the molecular structures, we can conclude that some of the molecules or ions are polar (like HCN, H\u2083O\u207a, and CH\u2082O), while others are nonpolar (like N\u2082 and NH\u2084\u207a). Dipoles exist in molecules that have significant electronegativity differences between bonded atoms, such as in HCN, H\u2083O\u207a, and CH\u2082O.<\/p>\n","protected":false},"excerpt":{"rendered":"

                        N2 HCN H30+ 12 NH4+ CH20 4 Steric # N\/A N\/A Electron Geometry Choose.. Choose\u2026 – Choose.. tetrahedra Choose Choose\u2026 Choose Choose\u2026 N\/A N\/A # of bonding electron groups 3 N\/A N\/A # of lone pairs N\/A 1 N\/A Choose\u2026 Molecular Geometry Choose.. Choose\u2026 – trigonalp! – Choose. Choose\u2026 Choose Choose\u2026 – N\/A N\/A How […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-186972","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186972","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=186972"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/186972\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=186972"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=186972"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=186972"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}