{"id":187051,"date":"2025-01-31T09:41:59","date_gmt":"2025-01-31T09:41:59","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=187051"},"modified":"2025-01-31T09:42:03","modified_gmt":"2025-01-31T09:42:03","slug":"draw-the-structural-formulas-for-each-of-the-following-organic-compounds","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/01\/31\/draw-the-structural-formulas-for-each-of-the-following-organic-compounds\/","title":{"rendered":"Draw the structural formulas for each of the following organic compounds"},"content":{"rendered":"\n<p>Draw the structural formulas for each of the following organic compounds. Circle the non- alkyl functional groups a. hexan-2-one b. 2- methylpentanal c. Pentane-1,3-diol d. buta-1,3-diene e. 1-propoxybutane f. ethyl ethanoate Draw the structural formulas for each of the following organic compounds. Circle the non- alkyl functional groups a. hexan-2-one b. 2- methylpentanal c. Pentane-1,3-diol d. buta-1,3-diene e. 1-propoxybutane f. ethyl ethanoate<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Structural Formulas:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Hexan-2-one<\/strong> (C6H12O):\n<ul class=\"wp-block-list\">\n<li>Structure: <code>CH3-CH2-CO-CH2-CH2-CH3<\/code><\/li>\n\n\n\n<li>Explanation: Hexan-2-one is a ketone, with the carbonyl group (C=O) at position 2. The non-alkyl functional group is the <strong>carbonyl group<\/strong> (C=O), which is located at the second carbon in the chain.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>2-Methylpentanal<\/strong> (C6H12O):\n<ul class=\"wp-block-list\">\n<li>Structure: <code>CH3-CH2-CH(CH3)-CH2-CHO<\/code><\/li>\n\n\n\n<li>Explanation: 2-Methylpentanal is an aldehyde, with the aldehyde group (\u2013CHO) at the terminal position. The non-alkyl functional group is the <strong>aldehyde group<\/strong> (\u2013CHO), located at the end of the chain.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Pentane-1,3-diol<\/strong> (C5H12O2):\n<ul class=\"wp-block-list\">\n<li>Structure: <code>HO-CH2-CH2-CH(OH)-CH2-CH3<\/code><\/li>\n\n\n\n<li>Explanation: Pentane-1,3-diol is a diol (contains two alcohol groups). The non-alkyl functional groups are the <strong>hydroxyl groups<\/strong> (\u2013OH) located at positions 1 and 3.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Buta-1,3-diene<\/strong> (C4H6):\n<ul class=\"wp-block-list\">\n<li>Structure: <code>CH2=CH-CH=CH2<\/code><\/li>\n\n\n\n<li>Explanation: Buta-1,3-diene contains two double bonds, making it a <strong>diene<\/strong>. The non-alkyl functional groups are the <strong>double bonds<\/strong> (C=C) between carbon atoms at positions 1 and 3.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>1-Propoxybutane<\/strong> (C7H14O):\n<ul class=\"wp-block-list\">\n<li>Structure: <code>CH3-CH2-CH2-O-CH2-CH2-CH3<\/code><\/li>\n\n\n\n<li>Explanation: 1-Propoxybutane is an ether, with an <strong>ether group<\/strong> (\u2013O\u2013) between a propyl and a butyl group. The non-alkyl functional group is the <strong>ether group<\/strong> (\u2013O\u2013).<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Ethyl ethanoate<\/strong> (C4H8O2):\n<ul class=\"wp-block-list\">\n<li>Structure: <code>CH3COOCH2CH3<\/code><\/li>\n\n\n\n<li>Explanation: Ethyl ethanoate is an ester, with the ester group (\u2013COO\u2013) linking an ethyl group and an acyl group (ethanoate). The non-alkyl functional group is the <strong>ester group<\/strong> (\u2013COO\u2013).<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation of Non-Alkyl Functional Groups:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbonyl group (C=O)<\/strong>: Found in ketones and aldehydes, it&#8217;s a key functional group with a carbon-oxygen double bond.<\/li>\n\n\n\n<li><strong>Hydroxyl group (\u2013OH)<\/strong>: Found in alcohols, this functional group consists of a hydroxide attached to a carbon.<\/li>\n\n\n\n<li><strong>Double bonds (C=C)<\/strong>: Characteristic of alkenes and dienes, where carbon atoms share two electrons, forming a bond.<\/li>\n\n\n\n<li><strong>Ether group (\u2013O\u2013)<\/strong>: Found in ethers, where an oxygen atom is bonded to two alkyl groups.<\/li>\n\n\n\n<li><strong>Ester group (\u2013COO\u2013)<\/strong>: Found in esters, formed by an alcohol and an acid, with a carbonyl oxygen bond.<\/li>\n<\/ul>\n\n\n\n<p>Each of these compounds contains alkyl chains (C\u2013H groups), but the non-alkyl functional groups provide their distinct chemical properties.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw the structural formulas for each of the following organic compounds. Circle the non- alkyl functional groups a. hexan-2-one b. 2- methylpentanal c. Pentane-1,3-diol d. buta-1,3-diene e. 1-propoxybutane f. ethyl ethanoate Draw the structural formulas for each of the following organic compounds. Circle the non- alkyl functional groups a. hexan-2-one b. 2- methylpentanal c. Pentane-1,3-diol [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-187051","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187051","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=187051"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187051\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=187051"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=187051"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=187051"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}