{"id":187258,"date":"2025-02-04T05:11:32","date_gmt":"2025-02-04T05:11:32","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=187258"},"modified":"2025-02-04T05:11:34","modified_gmt":"2025-02-04T05:11:34","slug":"which-molecules-must-be-polar","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/04\/which-molecules-must-be-polar\/","title":{"rendered":"Which molecule(s) must be polar"},"content":{"rendered":"\n<p>Which molecule(s) must be polar?<br>XeCl2F2<br>PCI3F2<br>CIF5<br>CBr2Cl2<br>PCI3<br>XeF4<br>ICI3<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To determine which molecules among XeCl\u2082F\u2082, PCl\u2083F\u2082, ClF\u2085, CBr\u2082Cl\u2082, PCl\u2083, XeF\u2084, and ICl\u2083 are polar, we must analyze their molecular geometries and the distribution of their bond dipoles. A molecule is polar if it has a net dipole moment, resulting from an uneven distribution of electron density due to differences in electronegativity and molecular shape.<\/p>\n\n\n\n<p><strong>1. XeCl\u2082F\u2082 (Xenon dichloride difluoride):<\/strong><\/p>\n\n\n\n<p>Xenon can form compounds with more than eight electrons (expanded octet). The molecular geometry of XeCl\u2082F\u2082 depends on the arrangement of the substituents around the xenon atom. If the molecule adopts a square planar geometry with fluorine and chlorine atoms positioned trans to each other, the dipoles may cancel out, resulting in a nonpolar molecule. However, if the arrangement is such that the dipoles do not cancel, the molecule will be polar. Therefore, XeCl\u2082F\u2082 can exist in both polar and nonpolar forms, depending on its geometric configuration.<\/p>\n\n\n\n<p><strong>2. PCl\u2083F\u2082 (Phosphorus trichloride difluoride):<\/strong><\/p>\n\n\n\n<p>Phosphorus has five valence electrons and can form five bonds. The molecular geometry of PCl\u2083F\u2082 is trigonal bipyramidal. If the fluorine atoms occupy the axial positions and the chlorine atoms occupy the equatorial positions, the molecule will have a net dipole moment due to the difference in electronegativity between fluorine and chlorine, making it polar.<\/p>\n\n\n\n<p><strong>3. ClF\u2085 (Chlorine pentafluoride):<\/strong><\/p>\n\n\n\n<p>Chlorine pentafluoride has a square pyramidal geometry with chlorine at the center and five fluorine atoms around it. The lone pair on chlorine causes a distortion, resulting in a net dipole moment. Therefore, ClF\u2085 is polar.<\/p>\n\n\n\n<p><strong>4. CBr\u2082Cl\u2082 (Dibromodichloromethane):<\/strong><\/p>\n\n\n\n<p>This molecule has a tetrahedral geometry with carbon at the center bonded to two bromine and two chlorine atoms. Due to the different electronegativities of bromine and chlorine, the bond dipoles do not cancel out completely, resulting in a polar molecule.<\/p>\n\n\n\n<p><strong>5. PCl\u2083 (Phosphorus trichloride):<\/strong><\/p>\n\n\n\n<p>PCl\u2083 has a trigonal pyramidal geometry due to the lone pair on phosphorus. The three P-Cl bonds create a net dipole moment, making PCl\u2083 a polar molecule.<\/p>\n\n\n\n<p><strong>6. XeF\u2084 (Xenon tetrafluoride):<\/strong><\/p>\n\n\n\n<p>XeF\u2084 has a square planar geometry with xenon at the center and four fluorine atoms at the corners. The molecule also has two lone pairs on xenon positioned opposite each other. This symmetrical arrangement causes the bond dipoles to cancel out, resulting in a nonpolar molecule.<\/p>\n\n\n\n<p><strong>7. ICl\u2083 (Iodine trichloride):<\/strong><\/p>\n\n\n\n<p>ICl\u2083 has a T-shaped molecular geometry due to two lone pairs on the iodine atom. This asymmetrical shape leads to a net dipole moment, making ICl\u2083 polar.<\/p>\n\n\n\n<p>In summary, the polar molecules among the given compounds are PCl\u2083F\u2082, ClF\u2085, CBr\u2082Cl\u2082, PCl\u2083, and ICl\u2083. XeCl\u2082F\u2082 can be polar or nonpolar depending on its geometric configuration, while XeF\u2084 is nonpolar due to its symmetrical square planar geometry.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Which molecule(s) must be polar?XeCl2F2PCI3F2CIF5CBr2Cl2PCI3XeF4ICI3 The Correct Answer and Explanation is : To determine which molecules among XeCl\u2082F\u2082, PCl\u2083F\u2082, ClF\u2085, CBr\u2082Cl\u2082, PCl\u2083, XeF\u2084, and ICl\u2083 are polar, we must analyze their molecular geometries and the distribution of their bond dipoles. A molecule is polar if it has a net dipole moment, resulting from an uneven [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-187258","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187258","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=187258"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187258\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=187258"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=187258"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=187258"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}