{"id":187336,"date":"2025-02-04T06:44:52","date_gmt":"2025-02-04T06:44:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=187336"},"modified":"2025-02-04T06:44:54","modified_gmt":"2025-02-04T06:44:54","slug":"give-the-balanced-chemical-equation-for-cellular-respiration-all-balanced-chemical-equations-require-states-for-full-credit","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/04\/give-the-balanced-chemical-equation-for-cellular-respiration-all-balanced-chemical-equations-require-states-for-full-credit\/","title":{"rendered":"Give the balanced chemical equation for Cellular Respiration (all balanced chemical equations require states for full credit)"},"content":{"rendered":"\n<p>Give the balanced chemical equation for Cellular Respiration (all balanced chemical equations require states for full credit)<\/p>\n\n\n\n<p>Solid glucose (C6H120) &amp; oxygen gas react to product carbon dioxide and water vapor \u2022<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Balanced Chemical Equation for Cellular Respiration:<\/strong><\/h3>\n\n\n\n<p>[<br>C_6H_{12}O_6 (s) + 6O_2 (g) \\rightarrow 6CO_2 (g) + 6H_2O (g)<br>]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300 words)<\/strong><\/h3>\n\n\n\n<p>Cellular respiration is the biochemical process by which cells convert glucose into usable energy (ATP) through a series of metabolic pathways. The overall reaction represents aerobic respiration, which requires oxygen.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Breaking Down the Equation:<\/strong><\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Reactants:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Glucose (C\u2086H\u2081\u2082O\u2086) (s):<\/strong> A solid organic molecule that acts as the primary energy source.<\/li>\n\n\n\n<li><strong>Oxygen (O\u2082) (g):<\/strong> A gaseous molecule required for aerobic respiration.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Products:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon dioxide (CO\u2082) (g):<\/strong> A gaseous waste product expelled during exhalation.<\/li>\n\n\n\n<li><strong>Water vapor (H\u2082O) (g):<\/strong> Water in gaseous form, another byproduct.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Balancing the Equation:<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Glucose consists of 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.<\/li>\n\n\n\n<li>Oxygen gas ((O_2)) is added as a reactant.<\/li>\n\n\n\n<li>The products include carbon dioxide and water vapor.<\/li>\n<\/ul>\n\n\n\n<p>To balance:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Carbon atoms: 6 from glucose \u2192 6 CO\u2082 molecules.<\/li>\n\n\n\n<li>Hydrogen atoms: 12 from glucose \u2192 6 H\u2082O molecules.<\/li>\n\n\n\n<li>Oxygen atoms: 6 O\u2082 molecules (12 oxygen atoms) + 6 from glucose = 6 CO\u2082 (12 oxygen atoms) + 6 H\u2082O (6 oxygen atoms).<\/li>\n<\/ol>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Importance of Cellular Respiration:<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>This reaction releases <strong>energy (ATP)<\/strong>, which is essential for cellular functions.<\/li>\n\n\n\n<li>Occurs in the <strong>mitochondria<\/strong> of eukaryotic cells.<\/li>\n\n\n\n<li>Helps maintain homeostasis by converting chemical energy into a usable form.<\/li>\n<\/ul>\n\n\n\n<p>Overall, this balanced equation represents the complete oxidation of glucose in the presence of oxygen, producing energy, carbon dioxide, and water.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Give the balanced chemical equation for Cellular Respiration (all balanced chemical equations require states for full credit) Solid glucose (C6H120) &amp; oxygen gas react to product carbon dioxide and water vapor \u2022 The Correct Answer and Explanation is : Balanced Chemical Equation for Cellular Respiration: [C_6H_{12}O_6 (s) + 6O_2 (g) \\rightarrow 6CO_2 (g) + 6H_2O [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-187336","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187336","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=187336"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187336\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=187336"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=187336"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=187336"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}