{"id":187362,"date":"2025-02-04T09:03:50","date_gmt":"2025-02-04T09:03:50","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=187362"},"modified":"2025-02-04T09:03:52","modified_gmt":"2025-02-04T09:03:52","slug":"a-technical-machinist-is-asked-to-build-a-cubical-steel-tank-that-will-hold-230l-of-water","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/04\/a-technical-machinist-is-asked-to-build-a-cubical-steel-tank-that-will-hold-230l-of-water\/","title":{"rendered":"A technical machinist is asked to build a cubical steel tank that will hold 230L of water"},"content":{"rendered":"\n<p>A technical machinist is asked to build a cubical steel tank that will hold 230L of water.<br>Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.001m.<\/p>\n\n\n\n<p>What is the molecular geometry of SF<sub>4<\/sub>O?<\/p>\n\n\n\n<p>a. trigonal bipyramidal<\/p>\n\n\n\n<p>b. pentagonal<\/p>\n\n\n\n<p>c. square pyramidal<\/p>\n\n\n\n<p>d. tetrahedral<\/p>\n\n\n\n<p>e. trigonal planar<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Problem 1: Smallest Possible Inside Length of the Tank<\/strong><\/h3>\n\n\n\n<p>We need to determine the smallest possible inside length (( l )) of a <strong>cubical<\/strong> steel tank that can hold <strong>230 liters<\/strong> of water.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 1: Convert Liters to Cubic Meters<\/strong><\/h4>\n\n\n\n<p>Since ( 1 ) liter ( = 0.001 ) cubic meters, we convert:<\/p>\n\n\n\n<p>[<br>230L = 230 \\times 0.001 = 0.230 \\text{ m}^3<br>]<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 2: Use the Volume Formula for a Cube<\/strong><\/h4>\n\n\n\n<p>The volume of a cube is given by:<\/p>\n\n\n\n<p>[<br>V = l^3<br>]<\/p>\n\n\n\n<p>Setting ( V = 0.230 ) m\u00b3:<\/p>\n\n\n\n<p>[<br>l^3 = 0.230<br>]<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 3: Solve for ( l )<\/strong><\/h4>\n\n\n\n<p>Taking the cube root:<\/p>\n\n\n\n<p>[<br>l = \\sqrt[3]{0.230}<br>]<\/p>\n\n\n\n<p>Using a calculator:<\/p>\n\n\n\n<p>[<br>l \\approx 0.608<br>]<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 4: Round to the Nearest 0.001m<\/strong><\/h4>\n\n\n\n<p>[<br>l \\approx 0.608 \\text{ m}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Answer:<\/strong> <strong>0.608 m<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Problem 2: Molecular Geometry of SF\u2084O<\/strong><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Correct Answer:<\/strong> <strong>(a) Trigonal Bipyramidal<\/strong><\/h4>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Explanation:<\/strong><\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Valence Electrons &amp; Lewis Structure<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Sulfur (S)<\/strong>: 6 valence electrons<\/li>\n\n\n\n<li><strong>Fluorine (F) (\u00d74)<\/strong>: ( 4 \\times 7 = 28 ) valence electrons<\/li>\n\n\n\n<li><strong>Oxygen (O)<\/strong>: 6 valence electrons<\/li>\n\n\n\n<li><strong>Total Electrons<\/strong>: ( 6 + 28 + 6 = 40 ) valence electrons The sulfur atom is the <strong>central atom<\/strong> with <strong>four fluorine atoms and one oxygen atom<\/strong> bonded to it.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Electron Domain &amp; Molecular Shape<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Steric Number (SN) Calculation:<\/strong><br>The steric number is determined by <strong>bonded atoms + lone pairs<\/strong> around the central atom.<ul><li><strong>4 fluorine atoms + 1 oxygen atom \u2192 5 regions<\/strong><\/li><li><strong>No lone pairs on sulfur<\/strong><\/li><\/ul>A steric number of <strong>5<\/strong> corresponds to a <strong>trigonal bipyramidal<\/strong> electronic geometry.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Molecular Geometry<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Since <strong>all five positions are occupied by atoms<\/strong>, the molecular shape remains <strong>trigonal bipyramidal<\/strong>.<\/li>\n\n\n\n<li>If there were lone pairs on sulfur, the shape would have been distorted.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Comparison with Other Options<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Square Pyramidal (c)<\/strong>: Requires <strong>6 electron groups<\/strong> (not applicable).<\/li>\n\n\n\n<li><strong>Tetrahedral (d)<\/strong>: Requires <strong>4 electron groups<\/strong> (not applicable).<\/li>\n\n\n\n<li><strong>Trigonal Planar (e)<\/strong>: Requires <strong>3 electron groups<\/strong> (not applicable).<\/li>\n\n\n\n<li><strong>Pentagonal (b)<\/strong>: Requires <strong>6+ electron groups<\/strong> (not applicable).<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h4>\n\n\n\n<p>The correct molecular geometry of <strong>SF\u2084O<\/strong> is <strong>Trigonal Bipyramidal (option a)<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A technical machinist is asked to build a cubical steel tank that will hold 230L of water.Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.001m. What is the molecular geometry of SF4O? a. trigonal bipyramidal b. pentagonal c. square pyramidal d. tetrahedral e. trigonal planar The [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-187362","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187362","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=187362"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187362\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=187362"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=187362"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=187362"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}