{"id":187491,"date":"2025-02-05T04:01:15","date_gmt":"2025-02-05T04:01:15","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=187491"},"modified":"2025-02-05T04:01:17","modified_gmt":"2025-02-05T04:01:17","slug":"platinum-tetrachloride-ptcl4-belongs-to-the-point-group-dah","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/05\/platinum-tetrachloride-ptcl4-belongs-to-the-point-group-dah\/","title":{"rendered":"Platinum tetrachloride, [PtCl4], belongs to the point group Dah"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">2a. Platinum tetrachloride, [PtCl4], belongs to the point group Dah. Determine how the s, p, and d orbitals of the Pt ion would behave when operated on by all of the D4h symmetry elements. Use the attached D4h character table to assign a symmetry label to each of these orbitals. 2 Cl Pt Cl Orbital 2C2 (z)(x. v) (dihedral) Label Platinum s Platinum px Platinum p Platinum pz Platinum dz2 Platinum dx2-y2 Platinum d Platinum dxz Platinum dyz LGO #1 LGO #2 2 0 0 0 -210|2|0|0 2 0 0 0 2 0 200<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-25.png\" alt=\"\" class=\"wp-image-187492\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To determine the symmetry labels (irreducible representations) for the orbitals of platinum in <strong>PtCl\u2084<\/strong>, which belongs to the <strong>D\u2084h point group<\/strong>, we use the <strong>D\u2084h character table<\/strong>. The goal is to analyze how each orbital transforms under the symmetry operations of D\u2084h.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Understanding D\u2084h Point Group<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>D\u2084h<\/strong> group includes symmetry operations such as the identity (<strong>E<\/strong>), rotations (<strong>C\u2084, C\u2082<\/strong>), reflections (<strong>\u03c3h, \u03c3v, \u03c3d<\/strong>), and inversion (<strong>i<\/strong>).<\/li>\n\n\n\n<li>The symmetry-adapted basis functions (such as atomic orbitals) transform according to irreducible representations listed in the character table.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Assigning Symmetry Labels<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Each orbital of the platinum atom behaves according to the irreducible representations in D\u2084h.<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th><strong>Orbital<\/strong><\/th><th><strong>Transformation Behavior in D\u2084h<\/strong><\/th><th><strong>Irreducible Representation<\/strong><\/th><\/tr><\/thead><tbody><tr><td><strong>Platinum s<\/strong><\/td><td>Symmetric under all operations<\/td><td><strong>A\u2081g<\/strong><\/td><\/tr><tr><td><strong>Platinum p\u2093<\/strong><\/td><td>Changes sign under \u03c3v(xz), remains under C\u2084<\/td><td><strong>B\u2081u<\/strong><\/td><\/tr><tr><td><strong>Platinum p\u1d67<\/strong><\/td><td>Changes sign under \u03c3v(yz), similar to p\u2093<\/td><td><strong>B\u2082u<\/strong><\/td><\/tr><tr><td><strong>Platinum p\ud835\udccf<\/strong><\/td><td>Symmetric under C\u2084, antisymmetric under i<\/td><td><strong>A\u2082u<\/strong><\/td><\/tr><tr><td><strong>Platinum d\ud835\udccf\u00b2<\/strong><\/td><td>Symmetric under C\u2084, C\u2082, \u03c3h<\/td><td><strong>A\u2081g<\/strong><\/td><\/tr><tr><td><strong>Platinum d\u2093\u00b2\u208by\u00b2<\/strong><\/td><td>Changes sign under C\u2084, symmetric under \u03c3h<\/td><td><strong>B\u2081g<\/strong><\/td><\/tr><tr><td><strong>Platinum d\u2093\u02b8<\/strong><\/td><td>Changes sign under C\u2082 and \u03c3h<\/td><td><strong>B\u2082g<\/strong><\/td><\/tr><tr><td><strong>Platinum d\u2093\ud835\udccf<\/strong><\/td><td>Changes under \u03c3h but remains in-plane<\/td><td><strong>E\u2081u<\/strong><\/td><\/tr><tr><td><strong>Platinum d\u1d67\ud835\udccf<\/strong><\/td><td>Similar to d\u2093\ud835\udccf<\/td><td><strong>E\u2081u<\/strong><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Explanation of the Symmetry Labels<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>s-Orbital (A\u2081g)<\/strong>: The spherical <strong>s-orbital<\/strong> is totally symmetric and remains unchanged under all symmetry operations.<\/li>\n\n\n\n<li><strong>p-Orbitals<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>p\ud835\udccf (A\u2082u)<\/strong>: Oriented along the principal <strong>C\u2084 axis<\/strong>, it remains unchanged under rotation but inverts under inversion.<\/li>\n\n\n\n<li><strong>p\u2093, p\u1d67 (B\u2081u, B\u2082u)<\/strong>: These orbitals are in-plane and transform differently under reflection through \u03c3v(xz) and \u03c3v(yz).<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>d-Orbitals<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>d\ud835\udccf\u00b2 (A\u2081g)<\/strong>: Similar to <strong>s<\/strong>, it is symmetric under all operations.<\/li>\n\n\n\n<li><strong>d\u2093\u00b2\u208by\u00b2 (B\u2081g)<\/strong>: Changes sign under a C\u2084 rotation.<\/li>\n\n\n\n<li><strong>d\u2093\u02b8 (B\u2082g)<\/strong>: Behaves similarly but with a different transformation under mirror reflections.<\/li>\n\n\n\n<li><strong>d\u2093\ud835\udccf, d\u1d67\ud835\udccf (E\u2081u)<\/strong>: These two orbitals form a degenerate pair.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Answer<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>s: A\u2081g<\/strong><\/li>\n\n\n\n<li><strong>p\u2093: B\u2081u<\/strong><\/li>\n\n\n\n<li><strong>p\u1d67: B\u2082u<\/strong><\/li>\n\n\n\n<li><strong>p\ud835\udccf: A\u2082u<\/strong><\/li>\n\n\n\n<li><strong>d\ud835\udccf\u00b2: A\u2081g<\/strong><\/li>\n\n\n\n<li><strong>d\u2093\u00b2\u208by\u00b2: B\u2081g<\/strong><\/li>\n\n\n\n<li><strong>d\u2093\u02b8: B\u2082g<\/strong><\/li>\n\n\n\n<li><strong>d\u2093\ud835\udccf, d\u1d67\ud835\udccf: E\u2081u<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">These assignments help in understanding bonding and electronic properties in <strong>square-planar<\/strong> complexes like <strong>PtCl\u2084<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>2a. Platinum tetrachloride, [PtCl4], belongs to the point group Dah. Determine how the s, p, and d orbitals of the Pt ion would behave when operated on by all of the D4h symmetry elements. Use the attached D4h character table to assign a symmetry label to each of these orbitals. 2 Cl Pt Cl Orbital [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-187491","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187491","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=187491"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187491\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=187491"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=187491"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=187491"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}