{"id":187525,"date":"2025-02-05T04:45:43","date_gmt":"2025-02-05T04:45:43","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=187525"},"modified":"2025-02-05T04:45:48","modified_gmt":"2025-02-05T04:45:48","slug":"benzene-is-an-organic-chemical-compound-with-the-molecular-formula-c6h6","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/05\/benzene-is-an-organic-chemical-compound-with-the-molecular-formula-c6h6\/","title":{"rendered":"Benzene is an organic chemical compound with the molecular formula C6H6"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Benzene is an organic chemical compound with the molecular formula C6H6. In the benzene molecule, carbon atoms form a ring with alternating single and double bonds connecting them. Thus, each individual carbon atom forms one a bond with another carbon atom and one and one bond with another carbon atom. Each carbon atom also forms one o bond with a hydrogen atom. H Identify which types of orbitals overlap to form the bonds between the atoms in a benzene molecule. Drag the appropriate labels to their respective targets. \u00c3\u00a2\u00e2\u20ac\u201c\u00c2\u00ba View Available Hint(s) sp\u00c3\u201a\u00c2\u00b2-8 sp\u00c3\u201a\u00c2\u00b3-sp\u00c3\u201a\u00c2\u00b3 sp-sp sp\u00c3\u201a\u00c2\u00b2-sp\u00c3\u201a\u00c2\u00b2 \u00c3\u2018\u00e2\u201a\u00ac-\u00c3\u2018\u00e2\u201a\u00ac Bonds formed Carbon-carbon a bond Carbon-carbon bond H Carbon-hydrogen o bond C-H H Type of orbitals involved P Pearson<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Answer:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon-carbon \u03c3 bond:<\/strong> <strong>sp\u00b2-sp\u00b2<\/strong><\/li>\n\n\n\n<li><strong>Carbon-carbon \u03c0 bond:<\/strong> <strong>p-p<\/strong><\/li>\n\n\n\n<li><strong>Carbon-hydrogen \u03c3 bond:<\/strong> <strong>sp\u00b2-s<\/strong><\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Benzene (<strong>C\u2086H\u2086<\/strong>) is an aromatic hydrocarbon with a <strong>planar cyclic structure<\/strong> where six carbon atoms form a hexagonal ring. The <strong>bonding in benzene<\/strong> can be understood through <strong>valence bond theory and hybridization<\/strong>.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Hybridization of Carbon Atoms<\/strong><br>Each carbon atom in benzene undergoes <strong>sp\u00b2 hybridization<\/strong>, meaning that <strong>one s orbital and two p orbitals<\/strong> mix to form three <strong>sp\u00b2 hybrid orbitals<\/strong>. These <strong>sp\u00b2 orbitals lie in the same plane<\/strong>, forming <strong>\u03c3 bonds<\/strong> with adjacent carbon atoms and one hydrogen atom.<\/li>\n\n\n\n<li><strong>Formation of \u03c3 Bonds<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon-Carbon \u03c3 Bonds:<\/strong> Each carbon atom forms <strong>two \u03c3 bonds<\/strong> with neighboring carbon atoms using its <strong>sp\u00b2 hybrid orbitals<\/strong>. Thus, the <strong>C-C \u03c3 bonds<\/strong> arise from <strong>sp\u00b2-sp\u00b2 orbital overlap<\/strong>.<\/li>\n\n\n\n<li><strong>Carbon-Hydrogen \u03c3 Bonds:<\/strong> Each carbon atom forms a <strong>\u03c3 bond with a hydrogen atom<\/strong> using its <strong>remaining sp\u00b2 hybrid orbital<\/strong>, which overlaps with the <strong>1s orbital of hydrogen<\/strong>. Thus, <strong>C-H \u03c3 bonds<\/strong> are formed from <strong>sp\u00b2-s orbital overlap<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Formation of \u03c0 Bonds<\/strong><br>The <strong>unhybridized p orbitals<\/strong> on each carbon atom are <strong>perpendicular to the plane of the benzene ring<\/strong>. These <strong>p orbitals overlap laterally<\/strong>, forming a <strong>delocalized \u03c0 system<\/strong> above and below the ring. This leads to the formation of <strong>C-C \u03c0 bonds from p-p orbital overlap<\/strong>.<\/li>\n\n\n\n<li><strong>Delocalization of Electrons<\/strong><br>The <strong>p orbitals of all six carbon atoms<\/strong> interact <strong>simultaneously<\/strong>, creating a <strong>continuous \u03c0 electron cloud<\/strong>. This delocalization is responsible for benzene\u2019s <strong>aromatic stability<\/strong> and its resistance to typical alkene reactions.<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>C-C \u03c3 bonds<\/strong>: <strong>sp\u00b2-sp\u00b2 orbital overlap<\/strong><\/li>\n\n\n\n<li><strong>C-C \u03c0 bonds<\/strong>: <strong>p-p orbital overlap<\/strong><\/li>\n\n\n\n<li><strong>C-H \u03c3 bonds<\/strong>: <strong>sp\u00b2-s orbital overlap<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This bonding model explains benzene\u2019s <strong>planar geometry, equal bond lengths, and high stability<\/strong>, distinguishing it from alkenes with localized double bonds.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Benzene is an organic chemical compound with the molecular formula C6H6. In the benzene molecule, carbon atoms form a ring with alternating single and double bonds connecting them. Thus, each individual carbon atom forms one a bond with another carbon atom and one and one bond with another carbon atom. Each carbon atom also forms [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-187525","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187525","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=187525"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187525\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=187525"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=187525"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=187525"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}