{"id":187681,"date":"2025-02-05T18:23:03","date_gmt":"2025-02-05T18:23:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=187681"},"modified":"2025-02-05T18:23:05","modified_gmt":"2025-02-05T18:23:05","slug":"boron-trifluoride-bf3-belongs-to-the-point-group-d3h","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/05\/boron-trifluoride-bf3-belongs-to-the-point-group-d3h\/","title":{"rendered":"Boron trifluoride, BF3, belongs to the point group D3h"},"content":{"rendered":"\n<p>Boron trifluoride, BF3, belongs to the point group D3h.<br>i) Draw the symmetry elements belonging to BF3.<br>ii) Determine the symmetry of the vibrations for BF3.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-43.png\" alt=\"\" class=\"wp-image-187682\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Solution for BF\u2083 Symmetry Analysis<\/strong><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>(i) Symmetry Elements of BF\u2083<\/strong><\/h4>\n\n\n\n<p>Boron trifluoride (<strong>BF\u2083<\/strong>) is a <strong>trigonal planar<\/strong> molecule, and it belongs to the <strong>D\u2083h point group<\/strong>. The symmetry elements present in this point group are:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Principal rotation axis (C\u2083)<\/strong> \u2013 A threefold axis passing through the boron atom, allowing 120\u00b0 rotations.<\/li>\n\n\n\n<li><strong>Three perpendicular C\u2082 axes<\/strong> \u2013 These pass through the boron atom and the midpoints of opposite B\u2013F bonds.<\/li>\n\n\n\n<li><strong>Horizontal mirror plane (\u03c3\u2095)<\/strong> \u2013 Lies in the plane of the molecule.<\/li>\n\n\n\n<li><strong>Three vertical mirror planes (\u03c3\u1d65)<\/strong> \u2013 Each plane contains one B\u2013F bond and the C\u2083 axis.<\/li>\n\n\n\n<li><strong>Improper rotation axis (S\u2083)<\/strong> \u2013 A threefold improper rotation (rotation by 120\u00b0 followed by reflection through \u03c3\u2095).<\/li>\n\n\n\n<li><strong>Identity element (E)<\/strong> \u2013 The molecule remains unchanged under identity operation.<\/li>\n<\/ol>\n\n\n\n<p>These symmetry elements define the <strong>D\u2083h point group<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>(ii) Determining the Symmetry of Vibrations for BF\u2083<\/strong><\/h4>\n\n\n\n<p>To determine the vibrational symmetry of BF\u2083, we follow these steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Find the number of vibrational modes<\/strong> using the formula:<br>[<br>\\Gamma_{\\text{vib}} = 3N &#8211; 6<br>]<br>where ( N ) is the number of atoms.<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>For BF\u2083, ( N = 4 ) (1 B + 3 F), so:<br>[<br>3(4) &#8211; 6 = 6 \\text{ vibrational modes}<br>]<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Character Table for D\u2083h Point Group:<\/strong><br>The <strong>D\u2083h<\/strong> group has the following irreducible representations: D\u2083h E 2C\u2083 3C\u2082 \u03c3\u2095 2S\u2083 3\u03c3\u1d65 A\u2081&#8217; 1 1 1 1 1 1 A\u2082&#8217; 1 1 -1 1 1 -1 E&#8217; 2 -1 0 2 -1 0 A\u2081&#8221; 1 1 1 -1 -1 -1 A\u2082&#8221; 1 1 -1 -1 -1 1 E&#8221; 2 -1 0 -2 1 0<\/li>\n\n\n\n<li><strong>BF\u2083 Vibrational Modes:<\/strong><br>The <strong>6 normal modes<\/strong> transform according to: [<br>\\Gamma_{\\text{vib}} = 2A&#8217;\u2081 + E&#8217; + 2E&#8217; + A&#8221;\u2082<br>]<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>2 A\u2081&#8217;<\/strong>: Symmetric stretching and symmetric bending (Raman active).<\/li>\n\n\n\n<li><strong>E&#8217; (double degenerate)<\/strong>: Asymmetric stretching (IR and Raman active).<\/li>\n\n\n\n<li><strong>E&#8217; (double degenerate)<\/strong>: Asymmetric bending (IR and Raman active).<\/li>\n\n\n\n<li><strong>A\u2082&#8221;<\/strong>: Out-of-plane bending (IR active).<\/li>\n<\/ul>\n\n\n\n<p>Thus, the <strong>vibrational modes of BF\u2083<\/strong> are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>IR Active:<\/strong> E&#8217; (asymmetric stretch), E&#8217; (asymmetric bend), A\u2082&#8221; (out-of-plane bend).<\/li>\n\n\n\n<li><strong>Raman Active:<\/strong> A\u2081&#8217; (symmetric stretch), E&#8217; (asymmetric stretch and bend).<\/li>\n<\/ul>\n\n\n\n<p>These symmetry assignments help in understanding BF\u2083\u2019s spectroscopic behavior in IR and Raman spectroscopy.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Boron trifluoride, BF3, belongs to the point group D3h.i) Draw the symmetry elements belonging to BF3.ii) Determine the symmetry of the vibrations for BF3. The Correct Answer and Explanation is : Solution for BF\u2083 Symmetry Analysis (i) Symmetry Elements of BF\u2083 Boron trifluoride (BF\u2083) is a trigonal planar molecule, and it belongs to the D\u2083h [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-187681","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187681","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=187681"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187681\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=187681"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=187681"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=187681"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}