1. what ion in NaC2H3O2 hydrolyzed?<\/p>\n\n\n\n
2.what would be equation showing the ion reacting in water?<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n When sodium acetate (NaC\u2082H\u2083O\u2082) dissolves in water, it dissociates completely into Na\u207a and C\u2082H\u2083O\u2082\u207b. The sodium ion (Na\u207a) does not hydrolyze because it comes from a strong base (NaOH) and has no affinity for protons. However, the acetate ion (C\u2082H\u2083O\u2082\u207b) is the conjugate base of acetic acid (HC\u2082H\u2083O\u2082), which is a weak acid. This means that acetate has a tendency to react with water to form acetic acid and hydroxide ions (OH\u207b).<\/p>\n\n\n\n This reaction increases the concentration of hydroxide ions (OH\u207b) in solution, making the solution slightly basic<\/strong>. This is why aqueous sodium acetate solutions have a pH greater than 7. The extent of this hydrolysis depends on the base dissociation constant (Kb) of acetate, which can be calculated using the relationship: Kb=KwKaK_b = \\frac{K_w}{K_a}<\/p>\n\n\n\n where KwK_w is the ionization constant of water (1.0 \u00d7 10\u207b\u00b9\u2074) and KaK_a is the acid dissociation constant of acetic acid (1.8 \u00d7 10\u207b\u2075). This results in a weak base, explaining why sodium acetate solutions are slightly basic.<\/p>\n\n\n\n Understanding this hydrolysis process is crucial in buffer solutions, where sodium acetate and acetic acid work together to maintain pH stability. This principle is widely used in biochemical applications, pharmaceuticals, and laboratory settings where pH control is essential.<\/p>\n","protected":false},"excerpt":{"rendered":" 1. what ion in NaC2H3O2 hydrolyzed? 2.what would be equation showing the ion reacting in water? The Correct Answer and Explanation is : Hydrolyzed Ion in NaC\u2082H\u2083O\u2082 and Hydrolysis Equation Explanation of the Hydrolysis Reaction (300 Words) When sodium acetate (NaC\u2082H\u2083O\u2082) dissolves in water, it dissociates completely into Na\u207a and C\u2082H\u2083O\u2082\u207b. The sodium ion (Na\u207a) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-187772","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187772","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=187772"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187772\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=187772"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=187772"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=187772"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Hydrolyzed Ion in NaC\u2082H\u2083O\u2082 and Hydrolysis Equation<\/strong><\/h3>\n\n\n\n
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Explanation of the Hydrolysis Reaction (300 Words)<\/strong><\/h3>\n\n\n\n