{"id":187846,"date":"2025-02-06T07:29:42","date_gmt":"2025-02-06T07:29:42","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=187846"},"modified":"2025-02-06T07:29:45","modified_gmt":"2025-02-06T07:29:45","slug":"determine-the-name-of-the-compound","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/06\/determine-the-name-of-the-compound\/","title":{"rendered":"Determine the name of the compound"},"content":{"rendered":"\n

Determine the name of the compound, V(ClO3)5.a. vanadium pentachlorideb. vanadium(III) acetatec. vanadium(V) chlorate<\/p>\n\n\n\n

d. vanadium pentachloratee. vanadium pentachlorite<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

e correct name for the compound V(ClO\u2083)\u2085 is vanadium(V) chlorate<\/strong>. Explanation:**<\/p>\n\n\n\n

In emical nomenclature, the name of a compound provides information about its composition and the oxidation states of its elements. Let break down the compound V(ClO\u2083)\u2085 to understand its correct naming:<\/p>\n\n\n\n

    \n
  1. Identifying the Cation (Metal):**\n
      \n
    • The syol “V” represents vanadium, a transition metal.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • ntifying the Anion (Polyatomic Ion):<\/strong>\n
        \n
      • The formu “ClO\u2083” denotes the chlorate ion, which consists of one chlorine atom covalently bonded to three oxygen atoms and carries a -1 charge.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • Detining the Oxidation State of Vanadium:<\/strong>\n
          \n
        • In the compod V(ClO\u2083)\u2085, there are five chlorate ions, each with a -1 charge, contributing a total negative charge of -5.<\/li>\n\n\n\n
        • To bala thisthe vanadium ion must have a +5 oxidation state.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
        • Naming thompound:<\/strong>\n
            \n
          • According to IUPAComenclature rules, when naming ionic compounds containing a metal with variable oxidation states, the oxidation state of the metal is indicated in parentheses using Roman numerals.<\/li>\n\n\n\n
          • Therefore, V(\u2083)\u2085 inamed vanadium(V) chlorate, indicating that vanadium is in the +5 oxidation state.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

            Evaluation of the en Options:<\/strong><\/p>\n\n\n\n

            a. Vanadium pentachloride:<\/strong><\/p>\n\n\n\n

              \n
            • This name suggests a comund composed of vanadium and chlorine atoms only, with the formula VCl\u2085. However, VCl\u2085 is not a stable compound under normal conditions; vanadium typically forms VCl\u2084 or VCl\u2083.<\/li>\n<\/ul>\n\n\n\n

              b. Vanadium(III) acet:<\/strong><\/p>\n\n\n\n

                \n
              • This refers to a compound wre vanadium has a +3 oxidation state and is bonded to acetate ions (CH\u2083COO\u207b). Its formula would be V(C\u2082H\u2083O\u2082)\u2083, which does not match V(ClO\u2083)\u2085.<\/li>\n<\/ul>\n\n\n\n

                c. **Vanadium(V) chlorate: – This correctly identifies the mpound as containing vanadium in the +5 oxidation state and chlorate ions, matching the formula V(ClO\u2083)\u2085.<\/p>\n\n\n\n

                d. *Vanadium pentachlorate:<\/em> – This name implies a compound withive chlorate ions but does not specify the oxidation state of vanadium. While it might seem descriptive, it is not the standard IUPAC naming convention for such compounds.<\/p>\n\n\n\n

                e. Vanadium pentachlorite:<\/strong> The term “chlorite” refers to the Cl\u207b ion. A compound named vanadium pentachlorite would have the formula V(ClO\u2082)\u2085, which differs from V(ClO\u2083)\u2085.<\/p>\n\n\n\n

                Therefore, the most accurate and IU-mpliant name for V(ClO\u2083)\u2085 is vanadium(V) chlorate<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"

                Determine the name of the compound, V(ClO3)5.a. vanadium pentachlorideb. vanadium(III) acetatec. vanadium(V) chlorate d. vanadium pentachloratee. vanadium pentachlorite The Correct Answer and Explanation is : e correct name for the compound V(ClO\u2083)\u2085 is vanadium(V) chlorate. Explanation:** In emical nomenclature, the name of a compound provides information about its composition and the oxidation states of its […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-187846","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187846","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=187846"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/187846\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=187846"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=187846"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=187846"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}