{"id":188206,"date":"2025-02-06T13:53:00","date_gmt":"2025-02-06T13:53:00","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=188206"},"modified":"2025-02-06T13:53:02","modified_gmt":"2025-02-06T13:53:02","slug":"aldohexoses-a-and-b-both-undergo-ruff-degradation-to-give-aldopentose-c","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/06\/aldohexoses-a-and-b-both-undergo-ruff-degradation-to-give-aldopentose-c\/","title":{"rendered":"Aldohexoses A and B both undergo Ruff degradation to give aldopentose C"},"content":{"rendered":"\n<p>Aldohexoses A and B both undergo Ruff degradation to give aldopentose C. On treatment with warm nitric acid, aldopentose C gives an optically active aldaric acid. B also<br>reacts with warm nitric acid to give an optically active aldaric acid, but A reacts to give<br>an optically inactive aldaric acid. Aldopentose C is degraded to aldotetrose D, which<br>gives optically active tartaric acid when it is treated with nitric acid. Aldotetrose D is<br>degraded to (+)@glyceraldehyde. Deduce the structures of sugars A, B, C, and D, and use<br>Figure 23-3 to determine the correct names of these sugars.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Based on the given information, we can deduce the structures of sugars A, B, C, and D step by step using the information about the reactions and their outcomes.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Understand the Ruff degradation<\/h3>\n\n\n\n<p>Ruff degradation is a reaction where aldoses (like hexoses) are converted to pentoses by the oxidative cleavage of the aldehyde group, followed by a decarboxylation reaction. The result is the formation of a pentose sugar. Aldohexoses A and B both undergo Ruff degradation to give the same aldopentose C. Therefore, both A and B are aldoses, and they must be <strong>epimers<\/strong> (sugars that differ in the configuration of only one stereocenter).<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Reaction of aldopentose C with warm nitric acid<\/h3>\n\n\n\n<p>Aldopentose C reacts with warm nitric acid to give an optically active aldaric acid. Aldaric acid is formed by the oxidation of both the aldehyde group and the hydroxyl group on the terminal carbon, creating a dicarboxylic acid. The fact that the aldaric acid is optically active indicates that aldopentose C is a <strong>chiral<\/strong> molecule (it has at least one asymmetric center). This suggests that C is <strong>not<\/strong> a meso compound.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Reactions of A and B with nitric acid<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Sugar A<\/strong> gives an optically inactive aldaric acid, suggesting that it is a <strong>meso compound<\/strong>, meaning A has symmetry in its structure (likely a sugar with two chiral centers that are mirror images of each other). A likely corresponds to <strong>D-glucose<\/strong>.<\/li>\n\n\n\n<li><strong>Sugar B<\/strong>, which also reacts with nitric acid to give an optically active aldaric acid, likely corresponds to <strong>D-mannose<\/strong>, which is an epimer of D-glucose.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Aldopentose C and its degradation<\/h3>\n\n\n\n<p>Aldopentose C is degraded to <strong>aldotetrose D<\/strong>. This suggests that C is a <strong>pentose<\/strong> sugar, and it undergoes further oxidation under nitric acid treatment. Tetrose D gives <strong>optically active tartaric acid<\/strong> upon treatment with nitric acid, indicating that D is also <strong>chiral<\/strong> and likely a sugar with two chiral centers.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 5: Degradation of D to glyceraldehyde<\/h3>\n\n\n\n<p>Aldotetrose D is further degraded to <strong>(+)-glyceraldehyde<\/strong>. This suggests that D is a <strong>tetrose<\/strong> with a chiral center at its second carbon. The structure of D corresponds to <strong>D-erythrose<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Summary of Structures<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Sugar A<\/strong> is D-glucose (meso compound).<\/li>\n\n\n\n<li><strong>Sugar B<\/strong> is D-mannose (epimer of glucose).<\/li>\n\n\n\n<li><strong>Sugar C<\/strong> is D-xylose (pentose).<\/li>\n\n\n\n<li><strong>Sugar D<\/strong> is D-erythrose (tetrose).<\/li>\n<\/ul>\n\n\n\n<p>These deductions are supported by known sugar structures and their reactions in Ruff degradation and oxidation processes.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Aldohexoses A and B both undergo Ruff degradation to give aldopentose C. On treatment with warm nitric acid, aldopentose C gives an optically active aldaric acid. B alsoreacts with warm nitric acid to give an optically active aldaric acid, but A reacts to givean optically inactive aldaric acid. Aldopentose C is degraded to aldotetrose D, [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-188206","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/188206","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=188206"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/188206\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=188206"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=188206"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=188206"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}