{"id":188387,"date":"2025-02-06T19:51:34","date_gmt":"2025-02-06T19:51:34","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=188387"},"modified":"2025-02-06T19:51:35","modified_gmt":"2025-02-06T19:51:35","slug":"part-a-draw-the-shear-diagram-for-the-beam","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/06\/part-a-draw-the-shear-diagram-for-the-beam\/","title":{"rendered":"Part A Draw the shear diagram for the beam"},"content":{"rendered":"\n<p>Part A Draw the shear diagram for the beam. Follow the sign convention. Part B Draw the moment diagram for the beam. Follow the sign convention.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-109.png\" alt=\"\" class=\"wp-image-188388\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>o analyze the shear and moment diagrams for a simply supported beam subjected to a central point load, we can follow these steps:<br><strong>Part A: Shear Force Diagram (SFD)<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Determine Reactions at Supports:<\/strong> &#8211; or a simply supported beam with a central point load ( P ) applied at the midpoint, the reactions at both supports are equal and can be calculated as: [ R_A = R_B = \\frac{P}{2} ] his is because the load is symmetrically placed, and the beam is in static equilibrium.<\/li>\n\n\n\n<li><strong>Construct the Shear Force Diagram:<\/strong> &#8211; he shear force is constant between the supports and equal to the reaction forces. &#8211; t the left support (A), the shear force is ( +\\frac{P}{2} ). &#8211; t the right support (B), the shear force is ( -\\frac{P}{2} ). &#8211; he shear force diagram is a horizontal line at ( +\\frac{P}{2} ) from A to the midpoint, and then a drop to ( -\\frac{P}{2} ) from the midpoint to B.<br><strong>Part B: Bending Moment Diagram (BMD)<\/strong><\/li>\n\n\n\n<li><strong>Calculate Bending Moments at Key Points:<\/strong> &#8211; t the supports (A and B), the bending moment is zero because there is no moment arm. &#8211; t the midpoint (C), the bending moment is maximum and can be calculated as: [ M_C = R_A \\times \\frac{L}{2} = \\frac{P}{2} \\times \\frac{L}{2} = \\frac{P \\times L}{4} ] here ( L ) is the length of the beam.<\/li>\n\n\n\n<li><strong>Construct the Bending Moment Diagram:<\/strong> &#8211; he bending moment increases linearly from A to C, reaching a maximum of ( \\frac{P \\times L}{4} ) at C. &#8211; t then decreases linearly from C to B, returning to zero at B. &#8211; he BMD is a triangle with a peak at the midpoint.<br><strong>Sign Conventions:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><em>Shear Force:<\/em>* Positive when the left side of the section is pushed upward.- <em>Bending Moment:<\/em>* Positive when the moment causes compression at the top of the beam.<br>or a visual demonstration of constructing shear and moment diagrams for a simply supported beam with a central point load, you can refer to the following video:<br>\ue200video\ue202SIMPLY SUPPORTED BEAM WITH POINT LOAD AT CENTRE SHEAR FORCE AND BENDING MOMENT DIAGRAM\ue202turn0search0\ue201<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Part A Draw the shear diagram for the beam. Follow the sign convention. Part B Draw the moment diagram for the beam. Follow the sign convention. The Correct Answer and Explanation is : o analyze the shear and moment diagrams for a simply supported beam subjected to a central point load, we can follow these [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-188387","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/188387","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=188387"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/188387\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=188387"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=188387"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=188387"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}