Construct a multistep synthetic route for the synthesis of acetylene from ethane<\/p>\n\n\n\n
They give CH3CH3, then they ask for reagent 1, product 1, reagent 2, product 2, reagent 3, product 3, reagent 4, and product 4 is CHCH.<\/p>\n\n\n\n
The options, to fulfill reagents and products are:<\/p>\n\n\n\n
HBr\/ROOR, HBr\/CH2Cl2, BrCH2CH3, CH2\u2026<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To synthesize acetylene (CH\u2261CH) from ethane (CH\u2083CH\u2083), we need to carry out a series of reactions. Here’s a step-by-step synthetic route using the provided reagents and products:<\/p>\n\n\n\n Reagent 1<\/strong>: HBr\/ROOR<\/strong> Explanation<\/strong>: The first step involves the free radical addition of HBr to ethane (CH\u2083CH\u2083). The radical initiator (ROOR) promotes the formation of a free radical at the ethane molecule. This leads to the generation of bromoethane (CH\u2083CH\u2082Br) as the product.<\/p>\n\n\n\n Reagent 2<\/strong>: BrCH\u2082CH\u2083<\/strong> Explanation<\/strong>: In this step, bromoethane (CH\u2083CH\u2082Br) undergoes a dehydrohalogenation reaction in the presence of a base (e.g., KOH). This reaction causes the elimination of a hydrogen atom and a bromine atom from the \u03b2-carbon, resulting in the formation of ethene (CH\u2082=CH\u2082).<\/p>\n\n\n\n Reagent 3<\/strong>: HBr\/CH\u2082Cl\u2082<\/strong> Explanation<\/strong>: In this step, ethene (CH\u2082=CH\u2082) undergoes an electrophilic addition reaction with HBr, where the bromine adds across the double bond, yielding 1,2-dibromoethane (CH\u2082BrCH\u2082Br) as the product. The CH\u2082Cl\u2082 is used as a solvent.<\/p>\n\n\n\n Reagent 4<\/strong>: CH\u2082\u2026 (Strong base such as NaNH\u2082)<\/strong> Explanation<\/strong>: Finally, the 1,2-dibromoethane undergoes a double dehydrohalogenation reaction when treated with a strong base such as sodium amide (NaNH\u2082) or another strong base. This removes two equivalents of hydrogen and bromine, forming the triple-bonded product acetylene (CH\u2261CH).<\/p>\n\n\n\n This series of reactions effectively transforms ethane (CH\u2083CH\u2083) into acetylene (CH\u2261CH).<\/p>\n","protected":false},"excerpt":{"rendered":" Construct a multistep synthetic route for the synthesis of acetylene from ethane They give CH3CH3, then they ask for reagent 1, product 1, reagent 2, product 2, reagent 3, product 3, reagent 4, and product 4 is CHCH. The options, to fulfill reagents and products are: HBr\/ROOR, HBr\/CH2Cl2, BrCH2CH3, CH2\u2026 The Correct Answer and Explanation […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-188482","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/188482","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=188482"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/188482\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=188482"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=188482"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=188482"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Step 1:<\/h3>\n\n\n\n
Product 1<\/strong>: Bromoethane (CH\u2083CH\u2082Br)<\/strong><\/p>\n\n\n\nStep 2:<\/h3>\n\n\n\n
Product 2<\/strong>: Ethene (CH\u2082=CH\u2082)<\/strong><\/p>\n\n\n\nStep 3:<\/h3>\n\n\n\n
Product 3<\/strong>: 1,2-Dibromoethane (CH\u2082BrCH\u2082Br)<\/strong><\/p>\n\n\n\nStep 4:<\/h3>\n\n\n\n
Product 4<\/strong>: Acetylene (CH\u2261CH)<\/strong><\/p>\n\n\n\nFinal Summary:<\/h3>\n\n\n\n
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